Make a program that outputs the number of seconds from the beginning of today (00:00:00 of the day you run it) to the second you ran it. However, if this number is divisible by three, print
Fizz instead. If it is divisible by five, print
Buzz instead. If it is divisible by three and five, print
Don't pad the number printed with extra zeroes (44 instead of 00044). You don't need to take leap seconds into account (saying for the universe in which people answer this years after I post it). Standard loopholes apply, shortest program wins.
Beginning of todayas in 13th of June or Midnight of the day you run it? \$\endgroup\$