The year counter is here [closed]

Question

Create a program that, given an integer N, outputs the number of years we have to get to N A.D. or how many years it has been since N A.D, as a string or int. For example, given 2014, the program should output 5 as it has been that many years since 2014. Input of the year in which you run the program should result in 0.

Treat the input "0" however you like: as its own year, as 1 A.D. or as 1 B.C. This means that you can pretend there IS a year zero and have all BC years be off by one.

Negative integers (integers with - in front of them) are treated as years B.C. For example inputting -2 would result in the program telling how many years it has been since 2 B.C.

Treat improper inputs (inputs that don't only use numbers and the dash as characters (abcd), or use the dash by itself or use it wrongly (e.g. 6-)) however you want, error or exit or something else.

The winning program is the program with the shortest code that does all of this. Have fun.

Answer 1

05AB1E, 3 bytes

žgα

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Explanation

  α   # absolute difference between
      # implicit input
žg    # and current year

Answer 2

Java 8, 46 bytes

n->(n-=java.time.Year.now().getValue())<0?-n:n

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Or alternatively:

n->Math.abs(n-java.time.Year.now().getValue())

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Answer 3

Japt, 3 bytes

aKi

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aKi     :Implicit input of year
a       :Absolute difference with
 K      :  Date
  i     :  Get year

Answer 4

Pyth, 4 bytes

a.d3

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Explanation:

a.d3Q - full program. implicit Q added.
a     - absolute difference of
 .d3  - current year and
    Q - implicit input

Answer 5

C# (Visual C# Interactive Compiler) with /u:System.Math and /u:System.DateTime flags, 32 18 bytes

n=>Abs(Now.Year-n)

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Answer 6

PHP, 22 bytes

<?=date('Y')-$argv[1];

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Answer 7

Python 3, 66 bytes

from datetime import*
print(abs(int(input())-datetime.now().year))

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Gives 5 for 2014 because it's 2019, not 2018.

Answer 8

Red, 30 bytes

func[y][absolute y - now/year]

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Answer 9

JavaScript (Node.js), 33 bytes

a=>Math.abs(Date().split` `[3]-a)

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-6 bytes thanks to Luis felipe De jesus Munoz

Answer 10

C++ (gcc), 131 127 bytes

#include<ctime>
#include<cstdio>
int main(){long y,t=time(0);scanf("%d",&y);y-=gmtime(&t)->tm_year+1900;printf("%d",y<0?-y:y);}

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