# The real treasure was the numbers we made along the way

Your task is to write a program, function or snippet (yes, snippets are allowed) that simply outputs an integer. However, you must be able to separate your submission into prefixes that also produce distinct integers. You cannot use any bytes that have appeared in previous prefixes. For example, we can have the prefixes:

1         # 1    (Now we can't use 1)
1-6       # -5   (Now we can't use - or 6)
1-6/3     # -1   (Now we can't use / or 3)
1-6/3+0xA # 9    Final submission


## Rules

• Your goal is to create to try and create the most unique integers, while keeping them close to zero.
• The scoring system is ((number of unique integers)**3)/(sum of absolute values), where the higher your score, the better. The above example scores $$\(4^3)/(1+\lvert-5\rvert+\lvert-1\rvert+9) = 64/16 = 4$/extract_tex]. • There should be at least two unique integers (no dividing by zero!) • Please format your answer similar to: # Language, $$\(4^{3})/16 = 4$$/extract_tex] 1-6/3+0xA (the full program)  • Mention if your submission is composed of snippets that evaluate to a value, functions or full programs. • List each of the prefixes and (optionally) an explanation for how they work. • The Final submission line appears to have swapped the 3 for a 2 (I haven't edited to correct this in case I've misunderstood) Feb 11, 2019 at 1:23 • It looks to me like you can get a near-optimal score in Python by writing print 123-len(open(__file__).read()) followed by # then one of each byte not used so far (except some control characters), with prefixes chopping those bytes. Adjust 123 to whatever centers the range of outputs around 0. For a better score, the non-comment part of the program can be rewritten using only the 7 distinct characters that are universal for Python. Is this all valid? – xnor Feb 11, 2019 at 1:37 • @JoKing I do include negatives, when the difference is negative. – xnor Feb 11, 2019 at 1:41 • @JoKing This method also be done in languages where a string can be written without a closing quote. – xnor Feb 11, 2019 at 1:47 • I can't believe so few other people noticed it and upvoted the earlier comment. :P I just noticed that @trichoplax spotted the typo, too. Feb 12, 2019 at 11:07 ## 17 Answers # TI-BASIC (TI-84+ CE), $$\238^3/14161 = 952.0\$$ 118-length("+×/ABCDEFGHIJK...  The 256 bytes in TI-BASIC break down thusly: • 240 bytes are one-byte tokens that can be quoted • 11 are the start of two-byte tokens • 2 are unused • The remaining 3 are the ",→, and newline characters which break strings. The string contains all 237 allowable bytes in the first category not already in 118-length(. The program calculates 238 distinct integers, ranging from 118 down to -119. The score is therefore $$\frac{238^3}{\sum_{n = -119}^{118} |n|} = 952.$$ • Wouldn't the string have to end with " which is a byte that was already used? Or why not? I am a bit confused by this also in other answers this seems to happen so probably I miss something. Feb 13, 2019 at 8:42 • @findusl TI-BASIC has a tendency to automatically complete parentheses and strings for you. so you could write mean({1,2,3, which would complete to mean({1,2,3}). strings are also completed: Disp "Hi! completes to Disp "Hi!". Therefore the final closing quote is unnecessary Feb 13, 2019 at 12:23 ## vim, 14³ / 53 = 51.77 i10<esc>X<c-x>r2hx<c-a>Pa<del>4<c-c>d^s5<c-o>I-<c-o><c-o>C6<c-h>7  Try it online! (all prefixes) Breakdown: i1 1 0 10 <esc>X 0 <c-x> -1 <c-x> decrements r2 -2 hx 2 hx is X, but we've already used that <c-a> 3 <c-a> increments P -3 paste the - from two steps ago a<del>4 -4 <c-c>d^ 4 <c-c> is an <esc> alternative s5 5 <c-o>I-<c-o><c-o> -5 <c-o> allows a single normal mode input C6 -6 trailing <c-o> from previous line used here <c-h>7 -7 <c-h> = backspace  • are you not reusing the < byte? Or is that a placeholder for a different byte? Feb 13, 2019 at 13:20 • @findusl no - <esc> represents the escape key and <c-char> represents ctrl+char Feb 13, 2019 at 14:20 ## Lenguage, 256³ / 16384 = 1024 The source code of the solution can be described as follows: 183662808731984092 0x00 bytes 4775233027031586288 0x01 bytes 27 0x02 bytes 81 0x03 bytes 128931291729852829668 0x04 bytes 108 0x05 bytes 648 0x06 bytes 81 0x07 bytes 2079 0x08 bytes 27 0x09 bytes 3481144876706026401009 0x0A bytes 108 0x0B bytes 2808 0x0C bytes 27 0x0D bytes 17496 0x0E bytes 81 0x0F bytes 2079 0x10 bytes 27 0x11 bytes 56106 0x12 bytes 756 0x13 bytes 93990911671062712827216 0x14 bytes 108 0x15 bytes 2808 0x16 bytes 27 0x17 bytes 75789 0x18 bytes 756 0x19 bytes 474552 0x1A bytes 27 0x1B bytes 81 0x1C bytes 56025 0x1D bytes 756 0x1E bytes 1514835 0x1F bytes 20439 0x20 bytes 2537754615118693246334805 0x21 bytes 108 0x22 bytes 2808 0x23 bytes 27 0x24 bytes 75789 0x25 bytes 756 0x26 bytes 2046276 0x27 bytes 20439 0x28 bytes 12812877 0x29 bytes 108 0x2A bytes 729 0x2B bytes 2079 0x2C bytes 27 0x2D bytes 1512648 0x2E bytes 40920957 0x2F bytes 1689866867948183303767857 0x30 bytes 66829507740256534347823839 0x31 bytes 2808 0x32 bytes 27 0x33 bytes 75789 0x34 bytes 756 0x35 bytes 2046276 0x36 bytes 20439 0x37 bytes 55249425 0x38 bytes 551880 0x39 bytes 345947652 0x3A bytes 2916 0x3B bytes 27 0x3C bytes 19656 0x3D bytes 56133 0x3E bytes 40842225 0x3F bytes 1104865839 0x40 bytes 45626405434600949201732247 0x41 bytes 1804396708986926427391243545 0x42 bytes 27 0x43 bytes 75789 0x44 bytes 756 0x45 bytes 2046276 0x46 bytes 20439 0x47 bytes 55249425 0x48 bytes 551880 0x49 bytes 1491734448 0x4A bytes 9355487364 0x4B bytes 78732 0x4C bytes 756 0x4D bytes 530685 0x4E bytes 1515591 0x4F bytes 1102740075 0x50 bytes 29831377653 0x51 bytes 1231912946734225628446770696 0x52 bytes 48718711142647013539563576444 0x53 bytes 2066715 0x54 bytes 55801305 0x55 bytes 1506635235 0x56 bytes 292874988897 0x57 bytes 2125764 0x58 bytes 14348907 0x59 bytes 40920957 0x5A bytes 29773982025 0x5B bytes 33261649561824092773510005450 0x5C bytes 1315405200851469365568216563988 0x5D bytes 55801305 0x5E bytes 1506635235 0x5F bytes 7948303851537 0x60 bytes 57395628 0x61 bytes 387420489 0x62 bytes 1104865839 0x63 bytes 803897514675 0x64 bytes 898064538169250504884770147177 0x65 bytes 35515940422989672870341847227676 0x66 bytes 1506635235 0x67 bytes 40679151345 0x68 bytes 214604203991472 0x69 bytes 1549681956 0x6A bytes 10460353203 0x6B bytes 29831377653 0x6C bytes 24001245795414021635055080475036 0x6D bytes 246496735155742018538946394995 0x6E bytes 958930391420721167499229875147252 0x6F bytes 40679151345 0x70 bytes 5795411844856032 0x71 bytes 41841412812 0x72 bytes 282429536481 0x73 bytes 805447196631 0x74 bytes 648033636476178584146487172825972 0x75 bytes 108 0x76 bytes 6655411849205034500551552664784 0x77 bytes 25891120568359471522479206628975804 0x78 bytes 1098337086315 0x79 bytes 156484875126743748 0x7A bytes 21747074309037 0x7B bytes 17496908184856821771955153666301244 0x7C bytes 108 0x7D bytes 2808 0x7E bytes 27 0x7F bytes 81 0x80 bytes 179696119928535931514891921949087 0x81 bytes 699060255345705731106938578982346708 0x82 bytes 4225121283523411674 0x83 bytes 472416520991134187843376319996477587 0x84 bytes 108 0x85 bytes 2808 0x86 bytes 27 0x87 bytes 75789 0x88 bytes 108 0x89 bytes 729 0x8A bytes 2079 0x8B bytes 27 0x8C bytes 4851795238070470150902081892625349 0x8D bytes 18874626894334054739887341632523361116 0x8E bytes 114078274655132115171 0x8F bytes 12755246066760623071771160639904894849 0x90 bytes 108 0x91 bytes 2808 0x92 bytes 27 0x93 bytes 75789 0x94 bytes 756 0x95 bytes 2046276 0x96 bytes 2916 0x97 bytes 27 0x98 bytes 19656 0x99 bytes 56133 0x9A bytes 130998471427902694074356211100885179 0x9B bytes 854006569949556303994892977044130020645 0x9C bytes 108 0x9D bytes 2808 0x9E bytes 27 0x9F bytes 75789 0xA0 bytes 756 0xA1 bytes 2046276 0xA2 bytes 55269864 0xA3 bytes 78732 0xA4 bytes 756 0xA5 bytes 530685 0xA6 bytes 1515591 0xA7 bytes 3536958728553372740007617699723899860 0xA8 bytes 23058177388638020207862110380191510557388 0xA9 bytes 108 0xAA bytes 2808 0xAB bytes 27 0xAC bytes 75789 0xAD bytes 756 0xAE bytes 2046276 0xAF bytes 20439 0xB0 bytes 55249425 0xB1 bytes 1492286328 0xB2 bytes 2125764 0xB3 bytes 14348907 0xB4 bytes 40920957 0xB5 bytes 622666287378897486676257185943063330345696 0xB6 bytes 108 0xB7 bytes 2808 0xB8 bytes 27 0xB9 bytes 75789 0xBA bytes 756 0xBB bytes 2046276 0xBC bytes 20439 0xBD bytes 55249425 0xBE bytes 1492286328 0xBF bytes 40291730856 0xC0 bytes 57395628 0xC1 bytes 387420489 0xC2 bytes 1104865839 0xC3 bytes 16811989759230232140258944020462709919333792 0xC4 bytes 108 0xC5 bytes 2808 0xC6 bytes 27 0xC7 bytes 75789 0xC8 bytes 756 0xC9 bytes 2046276 0xCA bytes 20439 0xCB bytes 55249425 0xCC bytes 551880 0xCD bytes 1491734448 0xCE bytes 40291730856 0xCF bytes 1087876733112 0xD0 bytes 1549681956 0xD1 bytes 10460353203 0xD2 bytes 29831377653 0xD3 bytes 453923723499216267786991488552493167822012492 0xD4 bytes 2808 0xD5 bytes 27 0xD6 bytes 75789 0xD7 bytes 756 0xD8 bytes 2046276 0xD9 bytes 20439 0xDA bytes 55249425 0xDB bytes 551880 0xDC bytes 1491734448 0xDD bytes 40291730856 0xDE bytes 1087876733112 0xDF bytes 29372671794024 0xE0 bytes 324270949293 0xE1 bytes 805447196631 0xE2 bytes 12255940534478839230248770190917315531194337311 0xE3 bytes 76545 0xE4 bytes 2066715 0xE5 bytes 55801305 0xE6 bytes 1506635235 0xE7 bytes 832318279426764 0xE8 bytes 21747074309037 0xE9 bytes 330910394430928659216716795154767519342247107424 0xEA bytes 2066715 0xEB bytes 55801305 0xEC bytes 1506635235 0xED bytes 22472634223673946 0xEE bytes 8934580649635073798851353469178723609411678244474 0xEF bytes 55801305 0xF0 bytes 1506635235 0xF1 bytes 40679151345 0xF2 bytes 606761124039196515 0xF3 bytes 241233677540146992568986543667825537454115312600825 0xF4 bytes 1506635235 0xF5 bytes 40679151345 0xF6 bytes 6513309293583968799362636679031305893812560835614495 0xF7 bytes 40679151345 0xF8 bytes 1098337086315 0xF9 bytes 175859350926767157582791190333845259132939142561591365 0xFA bytes 1098337086315 0xFB bytes 4748202475022713254735362139013821996589386504264297360 0xFC bytes 29655101330505 0xFD bytes 128201466825613257877854777753373193907913435615136028720 0xFE bytes 3461439604291557962702078999341076235513663562296408699075 0xFF bytes  Each run of identical bytes combined with the previous runs constitutes a prefix, and the full program is all the strings described above concatenated. This is an optimal score. (The programs print all numbers from -127 to 128 inclusive.) To create this answer, first, I copied the Java answer here for generating brainfuck programs to print a string. I ran it with this main function: public static void main(String[] args) { for (int i = -127; i <= 128; ++i) generate(""+i); }  Then, I ran this Ruby script to generate the human-readable text shown here: #!/usr/bin/ruby nums = File.open('f').map do |line| line.chomp.sub(/^\+/, '>+').chars.map{|ch| '+-><.,[]'.index(ch).to_s(3).rjust(3,?0) }.join.to_i 3 end puts (+nums.sort).each_cons(2).map.with_index{|x,i|"#{x-x} 0x#{i.to_s(16).rjust(2,?0).upcase} bytes"}*"\n"  The largest program is 3594571896764310192036774345469579167648804468538578264427 bytes long (and prints -90). • Props for the speed and practical problem-solving skill! Feb 11, 2019 at 3:30 # Javascript, $$\(111^{3})/2530 = 540.5656126482213\$$ 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)[!+[]+!+[]+[+[]]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]])().0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ_abcdefghijklmnopqrstuvwxyzÀāłƃǄȅɆʇˈ̉͊βόЍюҏӐԑՒ֓הٖؕڗۘܙݚޛߜరᡡⱱ㣣䤤奥榦秧訨驩ꪪ뫫쬬흝ﯯ&''|""**"",~{}  (Credit to this interesting utility for the conversion.) The above effectively evaluates into the following code: (new Proxy({},{get:(a,p,b,n=p.length+3)=>n%2?(n-1)/2:-n/2})).0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ_abcdefghijklmnopqrstuvwxyzÀāłƃǄȅɆʇˈ̉͊βόЍюҏӐԑՒ֓הٖؕڗۘܙݚޛߜరᡡⱱ㣣䤤奥榦秧訨驩ꪪ뫫쬬흝ﯯ&''|""**"",~{}  ...which creates a proxy that converts the length of a property name into a number. The first prefix ends one character after the ., and uses only 6 unique characters, excluding the .. The next 63 slices append 63 other single-byte characters which are valid in JS object property names. The next 44 slices append two-byte valid characters made up of unused bytes. The final slices append &'', |""**"", and ,~{}. The first slice returns -2, the second 2, then -3, then 3, -4, 4, -5, etc. up to the last three slices which are 0, 1, and -1. # Brain-Flak, $$\4^3/4=16\$$ For this one we use brain-flak snippets so we are concerned with the value not what they do. Complete program: <>(())[[][][]]{}  Prefixes and output  0 : <> 1 : <>(()) -2 : <>(())[[][][]] -1 : <>(())[[][][]]{}  Try it online! ## Explanation This is probably the best a brain-flak answer can get since we've used up all the character Brain-flak cares about, and we can't cluster the numbers closer to zero. The first snippet is <>, <> changes the stack but otherwise evaluates to zero, so we start with zero. From here we add (()) this makes one. We could have just done (), because that is also one, but if we push a one now we will be able to recall it later with {} and []. This is pretty much the only way {} and [] can create value so we do that. Since there is one thing on the stack [] counts as a 1 so we subtract 3 from the total with [[][][]] bringing us to -2. Lastly we use {} to pop the one we pushed earlier bringing us up to -1. # Jelly, 984 LNḂ¡:2µ}“¢¢¢£¤¥¦©¬®½¿€ÆÇÐÑ×ØŒÞßæçðıȷñ÷øœþ !"#%&'()*+,-./013456789;<=>?@ABCDEFGHIJKMOPQRSTUVWXYZ[$^_abcdefghijklmnopqrstuvwxyz{|~¶°¹²³⁴⁵⁶⁷⁸⁹⁺⁻⁼⁽⁾ƁƇƊƑƓƘⱮƝƤƬƲȤɓƈɗƒɠɦƙɱɲƥʠɼʂƭʋȥẠḄḌẸḤỊḲḶṂṆỌṚṢṬỤṾẈỴẒȦĊḊĖḞĠḢİĿṀṄȮṖṘṠṪẆẊẎŻạḅḍẹḥịḳḷṃṇọṛṣṭ§Äẉỵẓȧḃċḋėḟġḣŀṁṅȯṗṙṡṫẇẋẏż”‘  Try it online! You can see the prefixes (separated by a double newline) here. The numbers printed are, in order: 0 1 -1 -2 2 -3 3 -4 4 -5 5 -6 6 -7 7 -8 8 -9 9 -10 10 -11 11 -12 12 -13 13 -14 14 -15 15 -16 16 -17 17 -18 18 -19 19 -20 20 -21 21 -22 22 -23 23 -24 24 -25 25 -26 26 -27 27 -28 28 -29 29 -30 30 -31 31 -32 32 -33 33 -34 34 -35 35 -36 36 -37 37 -38 38 -39 39 -40 40 -41 41 -42 42 -43 43 -44 44 -45 45 -46 46 -47 47 -48 48 -49 49 -50 50 -51 51 -52 52 -53 53 -54 54 -55 55 -56 56 -57 57 -58 58 -59 59 -60 60 -61 61 -62 62 -63 63 -64 64 -65 65 -66 66 -67 67 -68 68 -69 69 -70 70 -71 71 -72 72 -73 73 -74 74 -75 75 -76 76 -77 77 -78 78 -79 79 -80 80 -81 81 -82 82 -83 83 -84 84 -85 85 -86 86 -87 87 -88 88 -89 89 -90 90 -91 91 -92 92 -93 93 -94 94 -95 95 -96 96 -97 97 -98 98 -99 99 -100 100 -101 101 -102 102 -103 103 -104 104 -105 105 -106 106 -107 107 -108 108 -109 109 -110 110 -111 111 -112 112 -113 113 -114 114 -115 115 -116 116 -117 117 -118 118 -119 119 -120 120 -121 121 -122 122 123  # Python 2, 3234.740$$\(11^{3})/32 = 41.59375$/extract_tex] After two hours of trial and error I finally got all integers from -4 to +5 (and 7). 0^cmp('','_')&3+1/~9*2-[-[-[[]==[]][[]==[[]]]][[]==[[]]]-[-[[]==[]][[]==[[]]]][[]==[[]]]-[-[[]==[]][[]==[[]]]][[]==[[]]]-[-[[]==[]][[]==[[]]]][[]==[[]]]-[-[[]==[]][[]==[[]]]][[]==[[]]]][[]==[[]]]|6<<7<<7>>8>>8and 5  This is a snippet with the following prefix snippets: # -1 cmp(cmp,()) # +3 = (-1) & 3 cmp(cmp,())&3 # +7 = 3 + 4 cmp(cmp,())&3+4 # +2 = 3 + (-1) = 3 + floor(4/-10) cmp(cmp,())&3+4/~9 # +1 = 3 + (-2) = 3 + 2*floor(4/-10) cmp(cmp,())&3+4/~9*2 # -4 = 1 - 5 cmp(cmp,())&3+4/~9*2-1-1-1-1-1 # -2 = (-4) | 6 cmp(cmp,())&3+4/~9*2-1-1-1-1-1|6 # -3 = (-4) | 1 = (-4) | floor(6/4) = (-4) | (6>>2) cmp(cmp,())&3+4/~9*2-1-1-1-1-1|6<<7<<7>>8>>8 # 0 = -3 and 0 cmp(cmp,())&3+4/~9*2-1-1-1-1-1|6<<7<<7>>8>>8and 0 # +5 = -3 and 05 cmp(cmp,())&3+4/~9*2-1-1-1-1-1|6<<7<<7>>8>>8and 05 # +4 = 5 ^ 1 cmp(cmp,())&3+4/~9*2-1-1-1-1-1|6<<7<<7>>8>>8and 05^True  Try it online! • You can change the 2*2 to 22&7 (-3&6 instead of -3&4) to fix that repetition of *. Feb 12, 2019 at 11:47 • @KevinCruijssen thanks for the suggestion. – ovs Feb 12, 2019 at 11:54 • You can free up ' and _ by using cmp(cmp,()) instead of cmp('','_') If that is helpful. Feb 13, 2019 at 3:46 • You could also make the list section a little shorter and a lot easier to understand by doing --[-1-1-1-1-1], but that doesn't really improve your score. Feb 13, 2019 at 3:54 ## Batch, 176³/7744 = 704 @cmd/cset/a%~z0-110 : !"#&'()*+,.23456789;<=>?ABCDEFGHIJKLMNOPQRSTUVWXYZ[$^_bfghijklnopqruvwxy{|} ¡¢£¤¥¦§¨©ª«¬­®¯°±²³´µ¶·¸¹º»¼½¾¿ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖ×ØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõö÷øùúûüýþÿ  The first prefix includes the colon and outputs the number -88. Subsequent prefixes output ascending numbers and the final program outputs 87. # Pyth, $$\(249^{3})/15500 = 996.0$/extract_tex] -C\|l"\x01\x02\x03\x04\x05\x06\x07\x08\t\n\x0b\x0c\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !#%&\'()*+,./0123456789:;<=>?@ABDEFGHIJKLMNOPQRSTUVWXYZ[]^_abcdefghijkmnopqrstuvwxyz{}~\x80\x81\x82\x83\x84\x85\x86\x87\x88\x89\x8a\x8b\x8c\x8d\x8e\x8f\x90\x91\x92\x93\x94\x95\x96\x97\x98\x99\x9a\x9b\x9c\x9d\x9e\x9f\xa0¡¢£¤¥¦§¨©ª«¬\xad®¯°±²³´µ¶·¸¹º»¼½¾¿ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖ×ØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõö÷øùúûüýþÿ  All of the escaped characters are single bytes - I've presented the program in this form for ease of copying and pasting. This link is to the full program without escaped characters; as can be seen there are a lot of placeholders for the unprintable characters used. The approach used is similar to lirtosiast's TI-BASIC answer, though I wrote my answer before browsing the other entries. The cord works as follows: -C\|l"... \| "|" C Character code of the above, i.e. 124 - Subtract from the above... l"... ... the length of the trailing string - the closing quote is inferred  The string is made of every single-byte character other than 0 (NULL), 127 (backspace), and the boilerplate characters (-C\|l"). That way, each character of the string can be removed one at a time to produce strings of lengths 248 down to 0. These programs yield results in the range [-124 - 124], with sum of absolute values of 15500. The code was generated using this program: +J"-C\\|l\""sCM-U256+CMJ,Z127 J"-C\\|l\"" Assign the boilerplate code to J CMJ Get the character code of each character in J + ,Z127 Append 0 and 127 -U256 Get values in range [0-256) which are not in the above CM Get each character with code points in the above s Concatenate into string +J Prepend boilerplate  And the sum of the numbers generated from each of the truncated programs was found with this program: sm.a.vd>._+J"-C\\|l\""sCM-U256+CMJ,Z127 5 +J"-C\\|l\""sCM-U256+CMJ,Z127 The full program string, as above ._ Get the prefixes of the above > 5 Discard the first 5 (those prefixes which don't include all the boilerplate code) m Map each of the above to: .vd Evaluate as Pyth code .a Take the absolute value of the above s Take the sum  ## Python 2, $$\11^3/53 = 25.1132075472\$$ 015-8*2+6/3&9%7if[]else 4^ord('\b')  Prefixes: 0 # 0 01 # 1 015 # 13 (octal) 015-8 # 5 015-8*2 # -3 015-8*2+6 # 3 015-8*2+6/3 # -1 015-8*2+6/3&9 # 9 (-1 bitwise-AND 9 = 9) 015-8*2+6/3&9%7 # 2 015-8*2+6/3&9%7if[]else 4 # 4 015-8*2+6/3&9%7if[]else 4^ord('\b') # 12 (4 bitwise-XOR 8 -- OR would also work)  Not optimal, but the best I could personally find with this particular structure. # Python 2 $$\6^3/9 = 24\$$ False-False**0&1+[[]<[[]]][[]<[]]^~3>>2  Here are the prefixes and what they output  0 : False-False -1 : False-False**0 1 : False-False**0&1 2 : False-False**0&1+[[]<[[]]][[]<[]] -2 : False-False**0&1+[[]<[[]]][[]<[]]^~3 -3 : False-False**0&1+[[]<[[]]][[]<[]]^~3>>2  # Clean, 40$$\^3\$$/400 = 160 import StdEnv,Data.GenDefault,Gast.GenLibTest derive genShow G derive gDefault G n = sum[(bitnot o bitnot) one \\ n <-: s]-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one-one s = (hd o show o d) undef d :: G -> G d g = gDefault{|*|} g :: G = GABCFHIJKMNOPQRUVWXYZcjkqxyz_0123456789  Try it online! Defines n which produces -20, -19, ..., 18, 19 depending on the length of the type G. The smallest prefix of G looks like :: G = G, preceded by the assorted imports and definitions. The largest prefix of G looks like :: G = GABCFHIJKMNOPQRUVWXYZcjkqxyz_0123456789$$$$, similarly preceded. • I think I'm missing something in this challenge, but… this answer (and a handful of others) is reusing "bytes that have appeared in previous prefixes", isn't it? Feb 12, 2019 at 1:39 • @Blackhole As I (and I assume others) understood it, you can use bytes multiple times in the same prefix, but not in subsequent ones. Feb 12, 2019 at 1:40 # Japt, $$\245^3/15006=980.0163268026123\$$ _Ê-122}("  !#%&')*+,./03456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\$^abcdefghijklmnopqrstuvwxyz|~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ ¡¢£¤¥¦§¨©ª«¬­®¯°±²³´µ¶·¸¹º»¼½¾¿ÀÁÂÃÄÅÆÇÈÉËÌÍÎÏÐÑÒÓÔÕÖ×ØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõö÷øùúûüýþÿ  Try it online! Like the other entries, uses the length of a string. Characters in the starting snippet, as well as \r (textareas don't play nice with this) and { (string interpolation character) are excluded from the string. First program is _Ê-122}(", each program is one character longer with the exception of when you add \\. • Not entirely sure this is valid, haven't checked that the string doesn't have any characters of the snippet Feb 27, 2019 at 5:06 • I was going to suggest replacing 122 with #z but that wouldn't improve your score. Feb 27, 2019 at 12:33 # Python 3, $$\(6^{3})/12 = 18$/extract_tex] 0x1-2+3|True*~4  This is a snippet. The individual prefix snippets are: 0 # gives 0 0x1 # gives 1 (hex syntax) 0x1-2 # gives -1 (1 minus 2) 0x1-2+3 # gives 2 (-1 plus 3) 0x1-2+3|True # gives 3 (True == 1; 2 bitwise-OR 1 == 3) 0x1-2+3|True*~4 # gives -5 (~4 == -5; True*~4 == -5; 2|-5 == -5)  Python's bitwise operators treat negative integers as two's complement with unlimited 1s to the right, so -5 is treated as ...11111011, which when ORed with ...000010 gives ...11111011 unchanged. ## Excel, $$\(6^{3})/12 = 18\$$ =0 0 =01 1 =01*2 2 =01*2-5 -3 =01*2-5+8 5 =01*2-5+8/4 -1  Prefix challenge does not gel well with Excel's formula structure # Runic Enchantments, 1173/3422 = 468.034 >"ul'B-;  !#%&()*+,.:0123456789@<=?ACDEFGHIJKLMNOPQRSTUVWXYZ[$^_abcdefghijkmnopqrstvwxyz{|}~€  Try it online! Prints [-58,58] inclusive. Uses a similar tactic as other entries, using a progressively longer string, getting its length, subtracts B (decimal value of 66), and prints the result. Uses a non-printing character (shown in the code block as € because apparently that's what &#128; evaluates to in HTML) in order to utilize byte value 0x80 (and consuming an otherwise unusable 0x00) and score one more value. Only byte values up to 127 that can't be represented in any fashion are 10 and 13, because they would cause the program to be two lines tall and not be read correctly by the instruction pointer. # Charcoal, 95³/2256 = 380.04211 96³/2304 = 384 Ｉ⁻⁴⁸Ｌ´´ !"#%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[$$^_abcdefghijklmnopqrstuvwxyz{|}~


The first prefix is the first 7 bytes and outputs the number 47. Try it online! Subsequent prefixes output descending numbers and the final program outputs -48. Try it online! Edit: Increased score by 3.95789 thanks to @ASCII-only.

• I think you should be able to escape a non-ASCII character at the start or end of the string? (using the escape character, the one that looks like a flipped grave accent) Feb 27, 2019 at 5:09