Get the remainder of a mathematical division without using any arithemetic operation [closed]

Question

Write a code that will display the remainder of a division. Code with shortest byte wins.

Rules:

• No arithmetic operation whatsoever should be in your code
• No use of functions or methods
• If you are using a function or method, it has to be written by you also

Samples:

Sample1: 9/3
Result1: 0

Sample2: 7/2
Result2: 1

Answer 1

J (23)

f=:4 :'##~,-.(-y)>\x#1'

e.g.

   f=:4 :'##~,-.(-y)>\x#1'
   9 f 3
0
   7 f 2
1

How it works:

• x#1: make a list of 1s as long as the left argument (x)
• (-y)>\: divide the list into a y-row (right arg) matrix, padding with zeroes.
• -.: negate the list (so the padding is 1)
• ,: flatten the matrix
• #~: replicate each number by itself (so all the zeroes disappear and all the ones remain)
• #: count how long the list is now.

Answer 2

CMD - 48 chars

start "" "http://google.com/search?q=%1 %%25 %2"

This program leverages the power of the mighty Google to calculate the result. Very rule bendy...

Answer 3

Perl, 46 chars

The challenge is kind of vague, but if string manipulation and regexps are allowed, this should work:

($_,$x)=map$"x$_,split"/",<>;s/$x//g;say y///c

This code reads a line of the form 7/3 from stdin, and outputs the remainder of the division (in this case 1). Needs Perl 5.10+ and the -M5.010 (or -E) switch for the say feature.

Answer 4

PHP, 38 chars

function m($a,$b){return fmod($a,$b);}

Answer 5

Python 2.7 - 67 chars

n,d=raw_input().split('/')
d=-int(d)
print range(int(n))[d::d][-1]

Old answer 87:

Takes a string input and aside from converting it to numbers does no numeric manipulation. The asterisk looks like a multiplication sign, but its actually repeated string concatenation ;)

n,d=raw_input().split('/')
x="."*int(n)
d=int(d)
while len(x)>d:
 x=x[d:]
print len(x)