# Calculate the sum of the first n prime numbers

I'm surprised that this challenge isn't already here, as it's so obvious. (Or I'm surprised I couldn't find it and anybody will mark it as a duplicate.)

## Task

Given a non-negative integer $$\n\$$, calculate the sum of the first $$\n\$$ primes and output it.

## Example #1

For $$\n = 5\$$, the first five primes are:

• 2
• 3
• 5
• 7
• 11

The sum of these numbers is $$\2 + 3 + 5 + 7 + 11 = 28\$$, so the program has to output $$\28\$$.

## Example #2

For $$\n = 0\$$, the "first zero" primes are none. And the sum of no numbers is - of course - $$\0\$$.

## Rules

• You may use built-ins, e.g., to check if a number is prime.
• This is , so the lowest number of bytes in each language wins!

# Japt -mx, 8 bytes

T=_j}a°T


Try it

# Pyth, 5 bytes

s.fP_


Try it online here.

s.fP_ZQ   Implicit: Q=eval(input())
Trailing ZQ inferred
.f   Q   Starting at Z=1, return the first Q numbers where...
P_Z    ... Z is prime
s         Sum the resulting list, implicit print


# Reticular, 52 40 bytes

indQ2j;o_1-2~d:^=[d@P~1-]:^*[+]:^1+*o;


Try it online!

## Explanation

Fun fact: Reticular does not count 2 as a prime number, so the instruction @P which gives the $$\n\$$-th prime in reality gives the $$\(n+1)\$$-th prime and due to this we have to add the first prime 2 manually.

in           # Read input and convert to int
dQ2j;o_      # Check if input is 0. If so, output and exit
1-2~d:^=     # Subtract 1 from input and save it as  ^
[d@P~1-]     # Duplicate the top of the stack (call it k)
and push the k-th prime. Finally swap the two top items
in the stack and subtract 1.
Stack before: [k]
Stack after: [k-1, k-th prime]
:^*         # Repeat the above a ^ number of times.
Stack before: [n]
Stack after: [0, 3, 5, ...,  n-th prime, 2]
[+]:^1+*    # Add the two top items in the stack a
total of (^+1) number of times
o;           # Output the sum and exit.