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It's 2017 2018 2019 already, folks, go home.

So, now that it's 2014, it's time for a code question involving the number 2014.

Your task is to make a program that prints the number 2014, without using any of the characters 0123456789 in your code, and independently of any external variables such as the date or time or a random seed.

The shortest code (counting in bytes) to do so in any language in which numbers are valid tokens wins.


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  • 10
    \$\begingroup\$ Even though numbers are ignored in brainfuck, I thought I'd post one anyway. 32 Chars: ++++++[>++++++++<-]>++.--.+.+++. \$\endgroup\$ – Braden Best Apr 1 '15 at 21:37
  • 4
    \$\begingroup\$ Brainfuck isn't a valid language for this challenge. \$\endgroup\$ – Joe Z. Apr 1 '15 at 22:49
  • 8
    \$\begingroup\$ I wonder if this question gets a small spike in popularity around New Year's. \$\endgroup\$ – Joe Z. Dec 26 '15 at 23:28
  • 3
    \$\begingroup\$ Waiting for "Come on folks, don't you realize it's 2016?" :) \$\endgroup\$ – padawan Jan 4 '16 at 23:35
  • 1
    \$\begingroup\$ @BradenBest It's possible to do it in 31 characters in at least two different ways: +++++++[>+++++++<-]>+.--.+.+++. and ++++++++++[>+++++<-]>.--.+.+++. \$\endgroup\$ – Zubin Mukerjee Feb 21 '16 at 17:47

274 Answers 274


><>, 7 bytes


You can try it on The Online ><> interpreter.


a        # push 10
 a       # push 10
  +      # push sum of top two values
   n     # output top value as number
    e    # push 14
     n   # output top value as number
      ;  # halt program

This doesn't print...


...because n outputs the top value as a number without a newline.

Alternate Solution (9 bytes)

This one actually puts 2014 on the stack as a single number and outputs it.


I basically just tried random values for this one :P


HaykamScript, 11 bytes



s       - string
  [     - executed parameters
    ⛉   - constant for 201
    ☄   - constant for 4
i       - convert to integer

Other Years

It's pretty simple to make any other year with the same amount of bytes, Unicode codepoints 0x2600 to 0x26FF represent integers 0 to 255 in my language.

For example, to make the year this was posted:


k4, 20 bytes


      "j"$("Ud";"/") / convert "Ud" and "/" to underlying integer representation -> (85 100;47)
  (-).               / subtract 47 from 85 and 100 -> 38 53
*/                   / multiply over

C, 29 bytes (Emacs) / 40 bytes (VI)

Before creating program, execute the shell command

stty -ixon      ### 11 bytes, with the newline

N.B this is required for most terminal editors, but is not required for emacs

then write this code:


N.B. '^S' is a single XOFF character e.g. in VI use control-V, control-S; in emacs use control-Q, control-S; emacs turns off flow control by default.

I assume the comment [You can't type ^S in a Linux terminal] below left off an implied [without the stty command or equivalent e.g. emacs default behavior upon startup], otherwise that comment is inaccurate.

And here is the requested hexdump:

$ od -a -t x1 x.c
0000000   m   a   i   n   (   )   {   p   r   i   n   t   f   (   "   %
         6d  61  69  6e  28  29  7b  70  72  69  6e  74  66  28  22  25
0000020   d   "   ,   '   j   '   *   ' dc3   '   )   ;   }  nl
         64  22  2c  27  6a  27  2a  27  13  27  29  3b  7d  0a
  • 2
    \$\begingroup\$ This isn't a valid answer. You have to count the shell command also, since it's a non-standard configuration. Also, if you have unprintables in your code, you should include a hexdump, for extra clarity. \$\endgroup\$ – Mego Sep 27 '16 at 15:46
  • \$\begingroup\$ You can't type ^S in a Linux terminal. -1 \$\endgroup\$ – MD XF May 21 '17 at 23:37
  • \$\begingroup\$ There is more than one way to ^Skin a cat, so these comments are incorrect as written; I clarified my post to address the confusion these folks (and others) may be having. It's still 29 if you use emacs as an editor. MD XF: how do you enter your [U+07DE] character into C-source; also, my compiler throws an error when replacing [main()] with [f()] (excluding the obvious gcc -Df=main hack), but if there is a compiler that accepts [f()], then all C source scores drop by 3. So you need to bump your score by 3, or reduce all other C solutions. \$\endgroup\$ – Brian Carcich May 22 '17 at 14:29

protected by Community Jan 14 at 6:34

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