Produce the number 2014 without any numbers in your source code

Question

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It's 2017 2018 2019 2020 2021 2022 2023 2024 already, folks, go home.

Woo, 10 years of this challenge!

So, now that it's 2014, it's time for a code question involving the number 2014.

Your task is to make a program that prints the number 2014, without using any of the characters 0123456789 in your code, and independently of any external variables such as the date or time or a random seed.

The shortest code (counting in bytes) to do so in any language in which numbers are valid tokens wins.

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Leaderboard:

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Answer 1

C# (56 characters)

Class P{static void Main(){Console.Write(','*','+'N');}} 

Answer 2

BAT (windows batch), 7 characters

echo %*

save as a.bat and invoke as a 2014

is there any restriction on using command line parameters? – Einacio

I don't think so, but echo $1 still has a number in it. – Joe Z.

not a so valid answer, but noone was posting an answer in this wonderful language

Answer 3

PHP (27) - not shortest ASCII PHP but more readable

<?=hexdec($e=hexdec(E)).$e;

Answer 4

Bat (Windows batch), 13 bytes (characters)

echo.^T |od -x

(^T is one character.)

Answer 5

Bash, 15 bytes

echo "^T "|od -x

(^T is one character.)

Answer 6

PYTHON

print(str(len('Happy new year to me')) + str(len('Happy new year')))

Answer 7

PHP, 22 bytes

echo ord('').ord('')

Edit

SE is stripping the characters. Working version here: http://codepad.org/unzjXNY2.

Answer 8

k 11 & 17 chars

this 11-char one is from a colleague

@:[:']*.(.)

this 17-char one is the best i could come up with on my own; it's a variant on ASCII abuse:

.,/$-/"i"$$`zz`fl

and just for interest, here are a few others of mine:

."c"$"RPQT"-"e"$" " / ascii (only 2.x)
."c"$-/"e"$("RPQT";" ") / ascii (all versions)

-_-(s*(exp acos@-`=`)xexp x)-(s xexp s:x*x)%x:+/``=`` / port of David Carraher's solution above

.,/$#:'(``;();`;````) / another approach

Answer 9

Delphi (26bytes & 26 chars)

ord('-')*ord('/')-ord('e')

Ascii values
- : 45
/ : 47
e : 101
45*47 = 2115 - 101 = 2014

Answer 10

You never said we couldn't put it on an external page!

Javascript - 19 Chars

location='//x.vu/u'

PS. It took 2 tries to get a shortened URL without numbers :P

Answer 11

e-TeX, 21 bytes

\the\numexpr`*`j\bye

It contains an invisible control character with code 19 (0x13) before the asterisk. A version with printable ASCII characters needs two more bytes:

\the\numexpr`^^S*`j\bye

In TeX ` takes the character code of the next token:

• [0x13] (^^S): 19
• j: 106

\numexpr calculates: 19 * 106 = 2014

The result is a DVI file with "2014" on the first page.

Variant with 2014 as page number:

\pageno\numexpr`^^S*`j~\bye

(25 bytes, if ^^S is replaced by the byte with character code 19).

Answer 12

Java without the weird unicode charas @ 115

enum A{A;public static void main(String[]z){int a=A.ordinal(),b=a++;System.out.print(""+(a<<a)+b+a+(a<<(a<<a)));}}

enumerators are pretty handy :)

Answer 13

GTB, 38

π/π→A:A++B:A+A→C:C*C→D~B*C*C+B*C-C-A-A

Compile assuming : at front

Answer 14

Python, 8 characters

ord('ߞ')

I think this ought to be valid :P

Ok, if you want me to use print(),

15 characters

print(ord('ߞ'))

Answer 15

Cardinal, 14 chars

%n=*+.-d++.
 d

The pointer starts at %, reads in the character ‘d’(ASCII 100), creates a duplicate as inactive value (the bottom of the stack), adds active and inactive values, resulting in 200, adds 1, prints out the result 201, subtracts one, divides by inactive value (100), resulting in 2, adds two, prints out 4. Cardinal pointer stacks can only carry values up to 255 (OEM 437 range), everything above leads to a wrap-around.

0             100             100             200             201
0               0             100             100             100
>n=*+.-d++.    %>=*+.-d++.    %n>*+.-d++.    %n=>+.-d++.    %n=*>.-d++.
 d              d              d              d              d
———————————————————————————————————————————————————————————————————————
   201             200               2               3               4
   100             100             100             100             100
%n=*+>-d++.    %n=*+.>d++.    %n=*+.->++.    %n=*+.-d>+.    %n=*+.-d+>.

print:"201"
———————————————————————————————————————————————————————————————————————
          4
        100  
%n=*+.-d++>

  print:"4"

Result:

Executing program..

2014

Execution complete.

Answer 16

C, 24 / 68

main(){printf("MMXIV");}

Haha, Roman Numerals For The Win!

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Or, for real:

main(){printf("%i%i%i%i",strlen("aa"),nil,strlen("a"),sizeof(int));}

Answer 17

q, 20 17 bytes

{x+y*z}."j"$"$+."

Answer 18

TeaScript, 7 bytes

'ߞ'c()

Takes the char code of the character with a char code of 2014

Answer 19

Groovy, 48 bytes

For 2015 change cabe to cabf...

n={it.each{print(((int)it)-(int)'a')}}
n('cabe')

Answer 20

JavaScript, 17 Bytes

atob("MjAxNA==")

Answer 21

VBA, 21 characters

?cells(,"BYL").column

Write and run the above code in the Immediate Window. Basically, the code converts column name BYL to its column index (2014).

Answer 22

C (gcc 5.3.1), 49 bytes

Pure arithmetic! \o/

main(a){printf("%d",(++a<<(a<<a|a))-(a<<a+a)-a);}

Undefined behaviours.

Specifically, use this compiler (languages are defined by implementation).

Without undefined behaviour (which would work on all compilers), 51 bytes

main(a){a++;printf("%d",(a<<(a<<a|a))-(a<<a+a)-a);}

Explanation

Basically 2048 - 32 - 2, constructed using powers of 2.

Answer 23

Swift 2.2, 28 bytes

print("\(ENOTDIR)\(EFAULT)")

Falling back on Darwin/glibc error codes from errno.h.

Answer 24

Mathematica, 16 bytes

FromDigits@"JAE"

Answer 25

QBIC, 10 bytes - Not Competing

?z^s*r+z+t

Calculates 2014 from the pre-initialised variables q-z (1-10) and prints it. Development of QBIC started some two years after 2014...

Alternative 12-byte version:

?(u*y)^r-z-q

Answer 26

Pushy, 6 bytes

`��`j#

Contains control characters, so here's a hexdump:

0000-0006:  60 14 0e 60 6a 23

The first unprintable is the literal DC4 byte (\x14), and the second is SHIFT-OUT (\x0e).

First these bytes are pushed as charcodes, so the stack is [20, 14]. The j operator concatenates these and # outputs the result: "2014".

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10-byte solution:

`<:;>`KT-"

Uses char-code manipulation and the builtin T (10).

`<:;>`       Push string as char-codes: [60, 58, 59, 62]
     KT-     Take 10 from each: [50, 48, 49, 52]
        "    Interpret as char-codes and print: results in "2014"

Answer 27

Microscript, 10 bytes

Noncompeting, language postdates the question..

'js'(s';-*

Explanation: 106*(59-40), using the language's equivalent of character literals. I'd do 53*38, but the character corresponding to 53... is the digit 5. And the character corresponding to 19 is, of course, nonprintable, so that wouldn't work.

Answer 28

Pyke, 3 bytes, noncompetitive

w߾

Try it here!

Where ߾ is 0xDFBE

Loads ord(0xDFBD-0x20) as an integer and implicit prints it

Answer 29

tcl, 16

puts [scan ߞ %c]

Can be seen on: http://rextester.com/live/SVXB29034

Answer 30

Groovy, casting to int, 8 bytes

(int)'ߞ'