Use that goodn't meme

Question

There is currently a meme on the internet that consist of taking a sentence, reverse the meaning and adding n't at the end. For example, I am small becomes I am talln't

Challenge

For the sake of the challenge, we'll simplify this : Your task will be to detect whenever there is a negation in a sentence, and replace it with the 'positive' one with n't added at the end. There will be some tricky parts that will be explained in the rules.

Rules

• You have to take a String as input, and return a String as output.
• Input will be a sentence in lowercase, with only . and , as punctuation marks.
• You have to replace any no <any_word> or not <any_word> with <any_word>n't.
• no/not have to be a word and not a substring : you don't have to change anything in none of those
• If the word already finish with a n, you have to replace n't with 't : no plan become plan't and not plann't
• When no or not isn't followed by any word, a punctuation mark or another no/not, you have to replace it with yesn't.
• compound words count as one word. so even if no-op contain the substring no, it doesn't contain the word no. So the result will be no-op and not -opn't.
• You do not have to worry about grammar errors. For example, there is no way will result to there is wayn't.
• No standard loopholes allowed.
• This is codegolf, so the shortest code wins.

There are some examples, even if this challenge looks clearn't for now.

Examples

Input : i love codegolfing, but i do not like short programs. does this sentence makes sense ... of course no.
Output : i love codegolfing, but i do liken't short programs. does this sentence makes sense ... of course yesn't.

Input : you are not invited. get out.
Output : you are invitedn't. get out.

Input : i am not ok, i have no plan and i have no gunn
Output : i am okn't, i have plan't and i have gunn't

Input : oh no no no i refuse.
Output : oh yesn't yesn't in't refuse.

Input : oh no no no, i refuse.
Output : oh yesn't yesn't yesn't, i refuse.

Input : i cannot believe this, you can't codegolf.
Output : i cannot believe this, you can't codegolf.

Input : oh no ... he did it again.
Output : oh yesn't ... he did it again.

Input : nn't is not a word, kevin. so this is not nn't.
Output : nn't is an't word, kevin. so this is nn'tn't.

Input : is it not clearn't for everyone
Output : is this clearn'tn't for everyone

Input : this is non't sense ...
Output : this is non't sense ...

Answer 1

Retina, 86 70 65 bytes

T`-'`L
\bnot?\s+(?!not?\b)(\w+?)n?\b
$1n't
\bnot?\b
yesn't
T`L`-'

-16 bytes thanks to @Neil.
-5 bytes thanks to @ovs.

Try it online.

Explanation:

T`-'`L             # Replace all "-" with "A" and all "'" with "B" to store them

\bnot?             # Then replace the word "no" or "not",
 \s+               #  followed by 1 or more whitespaces,
 (?!not?\b)(\w+?)  #  followed by a word/letter that is not "not" or "no"
 n?\b              #  minus a single trailing "n" if there are any
$1                 # with: the word/letter
 n't               #  appended with "n't"

\bnot?\b           # Then replace any remaining loose "no" or "not"
yesn't             # with "yesn't"

T`L`-'             # And finally replace all "A" with "-" and all "B" with "'" again

Answer 2

Python 2, 208 123 113 146 bytes

lambda s:re.sub(r"\bnot?\b(?!['-])(\s(?!not?(\b)(?!['-]))([\w'-]+))?",lambda m:(m.group(3)or"yes")+"n't"[(m.group(3)or'')[-1:]=='n':],s)
import re

Try it online!

Lost a bunch of bytes because of words ending in n't or n. Either or is shorter, but handling both was longer.

Answer 3

JavaScript (Node.js), 95 bytes

s=>s.replace(/\bnot?\b( (?!not?\b)(['\w-]*(\w)))?/g,(a,b,s,t)=>(s||'yes')+(t=='n'?'':'n')+"'t")

Try it online!

Thank Rick Hitchcock for 2 bytes

Answer 4

Stax, 75 73 50 bytes

ä§▀t9lJ₧5M#|+4╖¼├n▌ ·=┌«∙£╣▀K╖¥y▐▲·(■◄╙→á╣ó•ô╓╢Θ₧○

Run and debug it

Answer 5

Japt, 72 bytes

F=_r"%bnot?%s+(?!not?%b)(%w+?)n?%b|%bnot?%b(?!['-])",@Y=Y||"yes"Y+"n't"}

Try it online!

Answer 6

Java 8, 163 136 bytes

s->s.replaceAll("(^|[ ,.])not?(?= *([,.]|$|not?(?=$|[ ,.])))","$1yesn't").replaceAll("(^|[ ,.])not? ([\\w'-]+?)n?(?=$|[ ,.])","$1$2n't")

-27 bytes by creating a port of @recursive's Stax' answer.

Try it online.