Code-generator with unique characters

Question

Challenge

Your task is to write a piece of code that outputs another piece of code. That code must in turn output yet another code until the final code outputs the integer 1. The chain ends the first time 1 is outputted.

None of your programs may share any characters (there's one exception in the Rules-section).

The winning submission will be the submission with the longest chain. The tie-breaker will be shortest total code-length.

Rules:

You may use both functions, programs and snippets. You may assume a REPL environment.
All functions must be written in the same language
Symbol independent languages are disallowed. This includes partially symbol independent languages such as Headsecks.
Default output formatting may optionally be disregarded in a function's output. This includes trailing newlines, ans = etc.
You may reuse the space character (ASCII code point 32), but note the following:
- You may use as many space characters as you like in one of the functions, but restrict it to maximum 5 in all other functions
- You may not reuse any characters if code point 32 is not space in your language.
None of the programs may take input
The chain must be at least two programs long.

Example:

Your initial code is abc+cab+bac. This outputs: foofoo*123, which in turn outputs disp(~0), which outputs 1. This is a chain of 3 programs, with a combined length of 29 (tie breaker).

To make sure I understood: the programs may use comments, right? I mean, parts of code that are "useless" — Luis Mendo, May 28, 2018 at 13:00
Are simple expressions allowed? For example, could the final link of a Python program be 2^3, which would just evaluate to 1, or does it have to be e.g. lambda:2^3, print(2^3), etc.? — nneonneo, May 29, 2018 at 1:22
In languages where literals can be programs (such as in a lot of the golfing langs), can 1 be both a program and the output of that program or does the chain end when 1 is the output? — Emigna, May 29, 2018 at 7:26

Emigna · Accepted Answer · 2018-06-05 16:30:30Z

18

+250

05AB1E, 5-chain: 236 + 29 + 13 + 3 + 1 = 282 bytes

10101100011010001101100010110110001111000111001110101001000000000010111100100110011011010110011000100110101001001101100001110001111010100100000100010010001010011101011001110001000001011010101111001110011110001010111100001110110C₁<Au¦н.V

Try it online!

which prints the program

633693S<J6bαð3<žQTÌ>è9663тαhJ

Try it online!

which prints the program

522472 2-255B

Try it online!

which prints the program

88ç

Try it online!

which prints the program

Try it online!

which prints 1

edited Jun 5, 2018 at 16:30

answered May 28, 2018 at 12:38

Emigna

52.8k5 gold badges41 silver badges161 bronze badges

\$\begingroup\$ 8784>žxB and I'm probably KO'd. The lack of numbers for base conversion is a total crapshoot unless you calc it. The goal, if you want to beat emigna, is use the least amount of unique numbers per iteration. His answer reigns supreme because of the 88 in the second to last iteration. Truly a great answer. \$\endgroup\$
– Magic Octopus Urn
Jun 1, 2018 at 0:43
\$\begingroup\$ @MagicOctopusUrn: We could easily free up 10 and make something in binary. But I don't know if we can generate the first program from binary without B. \$\endgroup\$
– Emigna
Jun 1, 2018 at 7:26
2

\$\begingroup\$ @MagicOctopusUrn: Your task may be a bit harder as I believe I have a 5-chain ;) \$\endgroup\$
– Emigna
Jun 5, 2018 at 16:21
2

\$\begingroup\$ @MagicOctopusUrn: I'll be happy to :) This was a very fun challenge! \$\endgroup\$
– Emigna
Jun 5, 2018 at 20:28
1

\$\begingroup\$ Congrats for getting the 5th chain! \$\endgroup\$
– Chromium
Jun 19, 2018 at 6:06

| Show 3 more comments

Community · Accepted Answer · 2020-06-17 09:04:33Z

12

Java 8, chain of 2 functions, 90+10 37+4 28+4 = 32 bytes

o\u002D\u003E"\44\55\76"+2/2

Which is equivalent to:

o->"$->"+2/2

-57 bytes thanks to @OlivierGrégoire.

Try it online.

Which returns the String:

$->1

Try it online.

Which returns the integer:

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered May 28, 2018 at 11:54

Kevin Cruijssen

118k10 gold badges134 silver badges361 bronze badges

\$\begingroup\$ \u0076\u002D\u003E\u0022\u0076\u002D\u003E\u0022+(3\u002D2) (59 bytes+4 bytes). The rules says "None of your programs may share any characters", so v->1 is valid because the final 1 isn't a program. \$\endgroup\$
– Olivier Grégoire
May 30, 2018 at 12:04
1

\$\begingroup\$ 39 bytes + 4 bytes \$\endgroup\$
– Olivier Grégoire
May 30, 2018 at 12:14
\$\begingroup\$ @OlivierGrégoire I knew v->1 returning 1 is valid, but in my original answer \u0031 would contain a 1, and v->1 would then contain a 1 as well. Nice combination of both unicode Java and regular Java, though. And I golfed 2 more by changing (2/2) to 2/2. (PS: There is also already a chain-3 Java answer by Jakob.) \$\endgroup\$
– Kevin Cruijssen
May 30, 2018 at 12:30
\$\begingroup\$ @OlivierGrégoire Correction, I've been able to golf it to 28+4 by using "\44\55\76" instead of "\u0076\u002D\u003E" \$\endgroup\$
– Kevin Cruijssen
May 30, 2018 at 12:33
\$\begingroup\$ Nice golfing on top of mine ;) I haven't checked the 3-chain answer yet. I'll do it right now. \$\endgroup\$
– Olivier Grégoire
May 30, 2018 at 12:35

| Show 3 more comments

5 revs, 2 users 51% · Accepted Answer · 2018-08-07 19:29:31Z

R, 3-chain 198 + 44 + 3 bytes

`+`=`\143\141\164`;+"\143\141\164\050\151\156\164\124\157\125\164\146\070\050\143\050\070\070\055\071\055\071\054\071\071\071\055\070\070\071\055\070\055\070\054\070\070\055\071\055\071\051\051\051"

Try it online!

Returns :

cat(intToUtf8(c(88-9-9,999-889-8-8,88-9-9)))

Try it online!

Returns :

F^F

Try it online!

Returns 1

Explanation :

The first program is almost totally written in octal representation, where each character is written as \xxx where xxx is the ASCII code in octal mode. In human readable form would be :

`+`=`cat`;+"cat(intToUtf8(c(88-9-9,999-889-8-8,88-9-9)))"

Here, to avoid the use of round brackets we redefine the prefix operator + equal to cat function, then we use that to print the next string. Even after assigning cat to +, the latter still keeps its prefix operator "status" and will just take whatever follows it as its first parameter.

The second program, simply prints the characters F^F obtaining them from decimal ASCII : 70,94,70

Since in the first program we used the octal representation, only numbers 8 and 9 are free to be used; hence, we obtain 70 and 94 with some differences between numbers with only 8's and 9's.

Finally, the last program, F^F, exploits the ^ function (power of) which coerces FALSE to 0 and computes 0^0 returning 1

Credits to :

@ngm for the first 2-chain idea
@Giuseppe for the hint to use octals in functions
@BLT and @JayCe for the idea to override + in order to avoid brackets

Previous version :

R, 2-chain 27+3 24 + 2 bytes

cat(intToUtf8(c(49,76)))

Try it online!

Returns:

1L

Try it online!

Returns 1.

Well potentially you could have an output as a string with "wri\164e"(function args) to avoid a t or other similar encodings — Giuseppe, May 30, 2018 at 15:50
@Giuseppe @digEmAll According to the latest comments to the question cat(intToUtf8(c(49,76))) would work and is a bit shorter. Doesn't expand the chain though. — JayCe, Jun 4, 2018 at 20:14
@digEmAll See BLT's comment to my answer to another challenge... I think there might be something here. — JayCe, Aug 6, 2018 at 13:25
I've made this answer a Community Wiki. Please feel free to add this with a little explanation. — ngm, Aug 7, 2018 at 13:37

Jo King · Accepted Answer · 2018-05-28 23:47:04Z

8

Python 2, 2-Chain, 7+44 = 51 bytes

lambda:("7072696e74203"+`3-2`).decode("hex")

and

print 1

Try it online!

The base 16 code translates to print 1, which is returned by the anonymous function.

edited May 28, 2018 at 23:47

answered May 28, 2018 at 12:04

Jo King♦

46.7k5 gold badges122 silver badges183 bronze badges

Add a comment |

breadbox · Accepted Answer · 2018-05-29 20:05:15Z

Perl 5, 3-chain, 151 139 chars (114 + 20 + 5)

&{"CORE::SYSWRITe"|"CORE::39372!4"}(STDOUT,"\x70\x72\x69\x6E\x74\47\x50\x42\x5A\3\22\47\x5E\47\43\43\43\43\43\47")

The ugliness inside the &{ } evaluates to CORE::syswrite, and so the hex-escaped string is printed to standard output as:

print'PBZ^C^R'^'#####'

Please note that the ^C and ^R in the above represent literal control characters. (And not to be confused with the literal ^ caret that occurs between the two strings.)

This program in turn outputs:

say 1

Stewie Griffin · Accepted Answer · 2018-05-30 12:30:15Z

7

Octave, 3 programs, Length 42 bytes

char("``;8%79b/7%,,b"-5)

Outputs: [[63 24]*2 '']. Try it online!

[[63 24]*2 '']

Outputs: ~0. Try it online!

~0

Outputs: 1. Try it online!

edited May 30, 2018 at 12:30

answered May 28, 2018 at 13:30

Stewie Griffin

45.8k13 gold badges125 silver badges291 bronze badges

Add a comment |

Chromium · Accepted Answer · 2018-05-29 05:21:12Z

6

Cjam, 4-chain, 28+20+3+1=52 bytes

Snippet 1:

"tugshrm\x18$\x18vj\x1b\x07um~l$\x1b"{71^}%

Snippet 2:

32 4/5*_c_1-\@2*9+c\

Snippet 3:

'Y(

Snippet 4:

Which then prints 1.

Try it online!

Note:

Since Cjam does not have interpretation for escape characters, the ones in snippet 1 are only there for better web view. You need to use the corresponding actual characters to run the snippet.
If I cannot shave off more characters, then good job to @Emigna for the 05AB1E answer!

answered May 29, 2018 at 5:21

Chromium

2111 silver badge5 bronze badges

\$\begingroup\$ In snippet 2 you've reused the character 1 used in snippet 1 \$\endgroup\$
– digEmAll
Jun 3, 2018 at 10:47
\$\begingroup\$ See my note please. The escape characters are for the reader's convenience, in Cjam there are no escape characters, or they would not translate into the characters you think would in languages like C or python. When testing, you literally have to enter the characters manually instead of using the escape characters. \$\endgroup\$
– Chromium
Jun 4, 2018 at 2:28

Add a comment |

tsh · Accepted Answer · 2018-05-28 11:29:43Z

5

Excel, Chain 2, 27+3 bytes

=CHAR(45)&CHAR(45)&CHAR(49)

Not sure if this is OK...

answered May 28, 2018 at 11:29

tsh

33.1k2 gold badges32 silver badges122 bronze badges

2

\$\begingroup\$ Shouldn't there be a CHAR(61)& in the beginning as well for there to be a chain of 2? \$\endgroup\$
– Emigna
May 28, 2018 at 12:05
5

\$\begingroup\$ You should use french instead of english (CHAR become CAR, 3 bytes saved), not sure if another language reduce it more \$\endgroup\$
– Sefa
May 28, 2018 at 13:11
1

\$\begingroup\$ @Emigna But it seems typing --1 in a cell and hit enter, it would just show 1 on the screen... \$\endgroup\$
– tsh
May 29, 2018 at 2:39
\$\begingroup\$ @tsh: Hmm, yeah it seems like Excel adds the = implicitly if you type --1. \$\endgroup\$
– Emigna
May 29, 2018 at 6:37
1

\$\begingroup\$ @Neil Excel does not insert a = mark for +1 (but it does for --1), so I won't consider it as an expression. And I'm not sure if simply writing an 1 in the cell and call it "output 1" is valid. That's why --1 is used. \$\endgroup\$
– tsh
May 29, 2018 at 8:24

| Show 1 more comment

Community · Accepted Answer · 2020-06-17 09:04:33Z

x86 bytecode, Chain 2, 10+4 bytes

(Assembled with FASM, format PE)

ÇA.Ï?¿<÷Y. produces 1À@Ã in the address next to it and executes it, which returns 1 in eax (as per fastcall). In both cases the . actually represents A or LF.

In hex: C7 41 0A CF 3F BF 3C F7 59 0A and 31 C0 40 C3.

Disassembled:

mov dword ptr ds:[ecx+A],3CBF3FCF
neg dword ptr ds:[ecx+A]

produces

xor eax,eax                      
inc eax                          
ret

This (ab?)uses the fact that the entrypoint of the program is stored in ecx, and then writes the inverse of the to be executed code to the address 10 bytes over and negates it.

May or may not break if assembled with anything but fasm, to anything but a PE or with a different entrypoint.

l4m2 · Accepted Answer · 2018-05-31 00:55:33Z

JavaScript REPL, lots of bytes, 4 iterate

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"\x60\44\x7b\55\x7e\x7b\x7d\x7d\44\x7b\55\x7e\x7b\x7d\x7d\x60\56\x73\x70\x6c\x69\x74\x60\x60\56\x74\x6f\x53\x74\x72\x69\x6e\x67\x60\x60"
`${-~{}}${-~{}}`.split``.toString``
1,1
1

Too lazy to optimize the JSFUCK code

JavaScript REPL, 164 bytes, 3 iterate

may be able to expand

[g=222222222222222222,e=2e40,f=2e23,f,2e40,n=2222e49,r=2e24,2e30,e,n,r,8e28,2e40,n,r,9e29,g].map(S=>String.fromCharCode(Math.log(S))).join([])
'\55\x7E\x7B\x7D'
-~{}
1

Try it online!

@JoKing I didn't use 1 in other pros, so the first 1 is program and the 2nd one is result — l4m2, May 29, 2018 at 3:22

Lynn · Accepted Answer · 2018-06-04 21:09:05Z

CJam, 7-chain, 92365+1819+79+14+9+3+1 bytes

This 92365-byte program prints

YaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+1+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR1+1+1+1+1+11+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+1+YaY+`$1<mR1+1+1+1+1+11+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+11+YaY+`$1<mR1+11+11+YaY+`$1<mRYaY+`$1<mR1+1+1+1+1+1+11+1+1+1+1+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR1+11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+11+11+11+11+11+1+1+1+1+YaY+`$1<mR11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1+1+1+1+YaY+`$1<mR1+1+11+11+11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+1+1+1+11+11+1+1+YaY+`$1<mR11+11+YaY+`$1<mR1+1+1+1+1+1+11+1+1+1+YaY+`$1<mR1+11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+11+11+YaY+`$1<mR1+1+11+YaY+`$1<mR1+11+YaY+`$1<mR1+1+1+1+1+11+11+1+1+YaY+`$1<mR11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+YaY+`$1<mR1+1+1+1+1+

which prints

34 4673 4656 4673 4656 5464 4656 4673 4673 4740 34 50 34707 5477]{N7=64777-,=}%

which prints

";*;*Q*;;~"2f^

which prints

9(9(S(99|

which prints

88c

which prints

which prints 1.

Stewie Griffin · Accepted Answer · 2019-08-13 06:15:22Z

MATL, 5 programs, 404+159+35+4+1 = 603 bytes

Getting to 4 programs was hard. 5 programs was very hard!

'/'37 13+3+3+'3`/'37 13+3+3+77 13+37 13+3+3+'3`/'37 13+3+3+'3tttttttt`/'37 13+3+3+'3#'37 13+3+3+'3ttttt`'37 13+3+3+'3ttttt'37 13+3+3+77 13+'/'37 13+3+3+'3`<<tttttttttt'37 13+3+3+'3#'37 13+3+3+77 13+37 13+3+3+'3///<3////t````ttttt```<</////t`````t<3tttttttttt<3tt/'37 13+3+3+'3ttttttttt'37 13+3+3+'3`{'37 13+3+3+77 13+'y$'37 13+3+3+'3/////t`````ttI#I'77 13+3+'dk'hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh3_+''h

Try it online!

,50],5W50],50qqqqqqqq],50 50qqqqq]50qqqqq5W,50]99qqqqqqqqqq50 5W50,,,90,,,,q]]]]qqqqq]]]99,,,,,q]]]]]q90qqqqqqqqqq90qq,50qqqqqqqqq50]x5Wv!50,,,,,q]]]]]qqF FZah

Try it online!

This might be my favorite program I've written on PPCG:

22 2 2**2-2-- 22Y2 2EEEEEEEEBPX)2)

Try it online!

84
c

Try it online!

Explanation:

Having used hours on this program, I won't write the entire explanation now! I'll write it later!

Short summary:

T            -> Literal true = 1

84c          -> Convert 84 to its ASCII-character T

22 2 2**...  -> Calculate 84 using only 2, * and -
 22Y2        -> 22Y2 is a cell array with the name of all the months
 2EE..B      -> Is 512 in binary [1 0 0 ...]
 P           -> Flips is, [0 0 ... 1]
 X)          -> Uses the binary vector as index and gets the 10th element
             -> 'October'
2)           -> The second character, 'c'
             -> Resulting in the stack: 84, 'c' that's implicitly printed

,50]...      -> A string with ASCII character codes of '22 2...
             -> There's a lot of ,xyz], which means "do twice" and q which is decrement

In order to convert this to a string instead of character codes, we need to concatenate it with a string using h. To get a string, without using quotes, or the XY modifiers, we do base conversion and convert an integer to whitespace.

'/'37 13 ...  -> Concatenation of strings and character codes using only available numbers
3_+           -> Subtract 3 from all character codes to get the correct ones
''h           -> And concatenate with the empty string.

Community · Accepted Answer · 2020-06-17 09:04:33Z

CJam, 10 programs, 5,751,122,990 bytes

I was too lazy to golf it... But apparently I don't need to golf it to be competitive. But without golfing it is a bit difficult to post the solution in an answer.

It should work in the JavaScript interpreter in theory, but the program is too long to be tested in a browser. It should output the same in the Java interpreter except for the last program. But it may also run out of memory in the Java interpreter for the first few programs.

Statistics

5683631402 bytes, used )\_l
  65027874 bytes, used %&<>WXehrstu{|} and newline
   2247044 bytes, used +DEFHIS~
    199997 bytes, used ,38=[]`
     15352 bytes, used -25:N and space
      1181 bytes, used 67c
        84 bytes, used #'(@CKMTgkp
        21 bytes, used !"$?BJLQR^fijo
        16 bytes, used */4AGYZabdy
        19 bytes, used .09
         1 byte,  used 1

First bytes

l)__)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))...
\n{s}sX>X<eu{h}sX>X<eu{\n}sX>X<{{XXXXXXX}seeseeseeW>{X<{|}%}%}%{|}sX>X<{{X}se...
SH+~+E+E+E+SH+~+H+E~+SH+~+H+E~+SI+~+H+D+D+SI+~+I+E+E+SH+~+H+E~+SF+~+E+SD+~+D+...
[33]`3=,3333=[33]`3=,388333=[8]`88=,8333=[8]`88=,8333=[8]`88=,8338=[8]`88=,33...
N:--25--22- 2-N:--25--22- 2-N:--22--22-N:--25--22- 2-N:--25--22- 2-N:--22--22...
776776777767c677676676677667c66677666676776c776776777767c7667776c666776666767...
'#('@('T(('k(('T((('k(('K('p(''((('@('T(('k(('T((('k(('k('M('#(('#('C('g('g((...
"?RiQiJo$?RiQijL!"Bf^
4YbZbAd/4YbZbaG*
0.99999999999999999
1

\n is newline in the second program.

Generator

"'#('@('T(('k(('T((('k(('K('p(''((('@('T(('k(('T((('k(('k('M('#(('#('C('g('g((((((((("

{_[i1:X;{_1&6+ \1$X*X5*:X;- 2/}16*;]__,,:)\f<Wf%10fb:c@#)<W%'c}%s

"67c"
"N:--22--22-
N:--25--22- 2-
N:--55--25--5--2--2-"N/ers

"N:-25 "
"[33]`3=,3333=
[33]`3=,388333=
[8]`88=,8333=
[8]`88=,8338=
[8]`88=,333=
[8]`88=,88="N/ers

"[]`38=,"
"SH+~+E+E+E+
SI+~+H+D+D+
SI+~+I+E+E+
SH+~+H+E~+
SI+~+I+D~+H+E~+
SF+~+E+
SD+~+D+D~+"N/ers

"SDEFHI+~"
"{s}sX>X<eu
{t}sX>X<{{XXXXXXXX}s{X}s{XXXXXX}erseeW>{X<{&}%}%}%
{ee}sX>X<eu
{&}sX>X<{{XXXXXXs}s{X}s{XXXXXX}erseeW>{X<{|}%eu}%}%
{h}sX>X<eu
{h}sX>X<eu{X|}%
{N}sX>X<{{XXXXXXX}seeseeseeW>{X<{|}%}%}%
{|}sX>X<{{X}seeW>{X<{|}%}%}%"N/'Nf/Nf*erN\+s

1>"l)_"o)\{'_oi10-')*o'\o}/i10-')*o

Uriel · Accepted Answer · 2018-05-28 13:20:23Z

3

APL (Dyalog), 2 chain, 15+2 = 17 bytes

⎕AV[2+⎕AV⍳'⍳.']

Try it online!

Outputs the program

*0

That outputs

edited May 28, 2018 at 13:20

answered May 28, 2018 at 13:09

Uriel

13.1k4 gold badges16 silver badges44 bronze badges

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Community · Accepted Answer · 2020-06-17 09:04:33Z

3

JavaScript (ES6), 2 functions, 31+4 = 35 bytes

function(){return atob`Xz0+MQ`}

returns _=>1, which returns 1

f0 =
function(){return atob`Xz0+MQ`}

res0 = f0()
console.log('Output of 1st function:', res0)

f1 = eval(res0)
res1 = f1()
console.log('Output of 2nd function:', res1)

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered May 28, 2018 at 13:38

Arnauld

181k18 gold badges168 silver badges611 bronze badges

\$\begingroup\$ Wouldn't function invocation have to be part of each program? \$\endgroup\$
– TehShrike
May 28, 2018 at 17:47
\$\begingroup\$ @TehShrike Functions were explicitly allowed in the rules. (A function + its invocation code would be a full program. So, I don't think that would make much sense.) \$\endgroup\$
– Arnauld
May 28, 2018 at 17:57
\$\begingroup\$ Oh good call, I missed that 👍 \$\endgroup\$
– TehShrike
May 28, 2018 at 20:17

Add a comment |

Jonathan Allan · Accepted Answer · 2018-05-30 17:50:56Z

Jelly, 38 37 36 35 bytes, Chain of 4

ØJiⱮ⁾ɱṾ⁽÷ṃ;ṾØJ⁽¡Ṡị

Try it online! (18 bytes)

8220,163,187Ọ

Try it online! (13 bytes)

“£»

Try it online! (3 bytes)

Try it online! (1 byte)

18+13+3+1=35 bytes

How?

ØJiⱮ⁾ɱṾ⁽÷ṃ;ṾØJ⁽¡Ṡị - Main Link: no arguments
    ⁾ɱṾ            - list of charcters -> ['ɱ','Ṿ']
ØJ                 - yield the characters of Jelly's code-page
   Ɱ               - Ɱap across the two characters applying:
  i                -   first index of? -> [163, 187]
       ⁽÷ṃ         - 8220 (a base 250 compressed number)
          ;        - concatenate -> [8220, 163 187]
           Ṿ       - un-eval (get Jelly code) -> "8220,163,187"
                   - (Note: here a full program prints 8220,163,187 as it is the end
                   - of a leading constant chain due to the following constant)
            ØJ     - yield the characters of Jelly's code-page
              ⁽¡Ṡ  - 1206 (a base 250 compressed number)
                 ị - index into (1-indexed & modular, so gets the 182nd item, 'Ọ')
                   - implicit print (making the final output 8220,163,187Ọ)

8220,163,187Ọ - Main link: no arguments
8220,162,187  - list of numbers -> [8220, 162, 187]
            Ọ - cast ordinals to characters -> ['“','£','»']
              - implicit print (flat Jelly lists print as if strings so outputs “£»)

“£» - Main link: no arguments
“   - open string-literal
 £  - the content of the string-literal
  » - close it interpreting as a compressed string
    - this yields ['!']
    - implicit print (outputs !)

! - Main link: no arguments
! - factorial (of implicit input 0 - 0! = 1 as it is the empty product)
  - implicit print (outputs 1)

Jo King · Accepted Answer · 2018-05-31 06:26:50Z

3

Python 2, 3 snippets, 68 + 12 + 3 = 83 bytes

chr(44*2+4).join([chr(42&54),`45+25`,`42*2+52`,`4*4+55`+chr(42&54)])

which produces the string of octal literals:

"\70\136\71"

which produces:

8^9

Which finally produces 1.

Try it online!

answered May 31, 2018 at 6:26

Jo King♦

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Jakob · Accepted Answer · 2018-06-05 02:07:07Z

3

Java 8, 3 programs, 431 bytes

Program 1, 332 bytes

A lambda from one (empty) parameter of any type to String.

x\u002D\u003E"\151\156\164\40\157\75\70\46\70\52\70\54\156\75\53\53\157\53\70\73\156\145\167\40\123\164\162\151\156\147\50\51\53\50\143\150\141\162\51\50\47\171\47\53\157\51\53\50\143\150\141\162\51\50\47\54\47\53\157\51\53\50\143\150\141\162\51\50\47\75\47\53\157\51\53\156\53\50\143\150\141\162\51\50\47\56\47\53\157\51\53\156\73"

This is just a lambda with the arrow characters Unicode-escaped returning the text of the second program encoded with octal escape sequences.

Try It Online

Program 2, 93 bytes

Snippet producing a String.

int o=8&8*8,n=++o+8;new String()+(char)('y'+o)+(char)(','+o)+(char)('='+o)+n+(char)('.'+o)+n;

Try It Online (with return added)

Program 3, 6 bytes

A lambda from one (empty) parameter of any type to int.

z->9/9

Try It Online

edited Jun 5, 2018 at 2:07

answered May 28, 2018 at 22:59

Jakob

2,7091 gold badge11 silver badges24 bronze badges

2

\$\begingroup\$ Nice answer! You can golf \166 to \44 for -1 byte, since $ is also a valid variable name. Try it online, resulting in $->9-8 (Try it online.) \$\endgroup\$
– Kevin Cruijssen
May 29, 2018 at 11:45
\$\begingroup\$ After several tries, it's just not possible to make a 3-chain with Java. You need the \uXXXX in the first code to avoid ->. Then you need either return (function) or System.out (snippet or function), both contain a u which you already used in \uXXXX. So I personally think this entry is invalid and I downvoted it accordingly. \$\endgroup\$
– Olivier Grégoire
May 30, 2018 at 15:25
\$\begingroup\$ @OlivierGrégoire Snippets are explicitly allowed in this challenge (first rule). In addition, System.console().printf could be used to prevent the use of u. Something similar is done in this answer and I've also used it in these two answers of mine. \$\endgroup\$
– Kevin Cruijssen
May 30, 2018 at 15:45
\$\begingroup\$ Thanks @KevinCruijssen but a snippet must still output. Here's a fix around all: x->"\146\157\162\50\143\150\141\162\40\44\72\156\145\167\40\143\150\141\162\133\135\173\47\171\47\54\47\54\47\54\47\75\47\54\47\70\47\54\47\56\47\54\47\70\47\175\51\123\171\163\164\145\155\56\143\157\156\163\157\154\145\50\51\56\160\162\151\156\164\146\50\53\53\44\53\156\145\167\40\123\164\162\151\156\147\50\51\51\73" (319 bytes) turns into for(char $:new char[]{'y',',','=','8','.','8'})System.out.printf(++$+new String()); (89 bytes) turns into z->9/9 (6 bytes). Total: 404 bytes. \$\endgroup\$
– Olivier Grégoire
May 30, 2018 at 16:08
\$\begingroup\$ I meant System.console() for the 2nd program, which is correctly 89 bytes (while the System.out makes it 83 bytes). \$\endgroup\$
– Olivier Grégoire
May 30, 2018 at 16:26

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Community · Accepted Answer · 2020-06-17 09:04:33Z

2

SmileBASIC, chain 3, 375 bytes

k=59599-44444print c("sbanm",k,4,"")+c("sbwav",44-5,2,"")+c("sbwav",594-222,4,"")+c("game5vs",4528-442,2,"")+c("sbanm",k,4,"")+c("sbanm",72,5-4,"")*2+c("sbwav",594-222,4,"")+c(sbwav,854-44,2,"")+c("staffroll",259+2,9,"")+c("ex8techdemo",24455,5-2,"")+key(4)[.]def c(f,s,l,q)for i=.to-5+l+4q=q+load("txt:sys/"+f,.)[s+i]next:return q:end

Outputs:

CHR$63OUT A$CHR$33OUT B$PRINT A$;B$;L

Outputs:

?!0

Outputs:

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered May 30, 2018 at 15:56

12Me21

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Maz · Accepted Answer · 2018-06-04 14:52:48Z

PHP 7.0, 2-chain, 35 + 8 = 43 bytes

While writing my initial answer I realized I could just use base64 encode the second echo. It shaved off 11 bytes, so here it is. You can find my original idea below, too.

Run using php -r:

echo base64_decode('RUNITyAxPz4=');

This outputs:

ECHO 1?>

Which then obviously prints:

Output:

My code when run in a terminal. The appended && echo is for readability only.

Comments:

There's not much to it really. Very simple once you know about "?>" implicitly acting as ";". The "tricky" part was to figure out what to encode:

ECHO 1; became RUNITyAxOw==, so we have a collision of uppercase O's. No good.
echo 1; became ZWNobyAxOw==, so now there's two lowercase o's. Unfortunate!
ECHO 1?> became RUNITyAxPz4=. It's the same length and none of the characters collide. So that's it!

Alternatively we can use "echO" and "ECHo", too (36 + 7 = 43 bytes).

echO base64_decOde('RUNIbyAxOw==')?>
ECHo 1;
1

We can also switch the ; and ?> around using that. It works equally well and it all scores the same in length.

My initial solution:

PHP 7.0, 2-chain, 44 + 10 = 54 bytes

This is the best I could come up with at first. I understood that "unique characters" meant "echo" is not equal to "ECHO". Hope I got that right!

Run using php -r:

echo strtoupper(urldecode('echo true%3b'))?>

This outputs:

ECHO TRUE;

Which in turn gives us our number:

Output:

My code when run in a terminal. The appended && echo is for readability only.

Some comments:

I think you can only do a 2-chain in PHP since it requires the ";" instruction separator.
- You can get around this once by using "?>", which implies a semicolon, but obviously can't re-use it a second time
- This was the hardest part for me to figure out. I didn't know this worked beforehand, nor that "?>" was even allowed when running via php -r
By using strtoupper() I was able to just write the code for chain #2 in lowercase, while the output is obviously uppercase. Easy mode right there!
urldecode() allows me to encode ";" as "%3b"
That's all there is really, nothing too exciting

Thanks for the challenge, I learned something today!

Community · Accepted Answer · 2020-06-17 09:04:33Z

2

Lua, 2 chain, 83+8=91 bytes

load(('').char(0x70,0x72,0x69,0x6E,0x74,39,0x70,0x72,0x69,0x6E,0x74,34,49,34,39))()

Outputs

print"1"

Which outputs

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Aug 7, 2018 at 19:28

GalladeGuy

1014 bronze badges

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Neil · Accepted Answer · 2018-05-28 13:53:03Z

1

Charcoal, 2 programs, 10 + 2 = 12 bytes

⭆´Ｇ´·℅⊕⊕℅ι

Try it online! Outputs

Ｉ¹

Try it online! Which outputs 1.

answered May 28, 2018 at 13:53

Neil

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Mayube · Accepted Answer · 2018-05-29 12:49:29Z

1

Braingolf, 2 chain, 9 + 2 = 11 bytes

72-_#23-@

Try it online!

This outputs

5/

Try it online!

(Plus some default output which can be ignored per OP's rules)

This in turn outputs

edited May 29, 2018 at 12:49

answered May 29, 2018 at 12:26

Mayube

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fergusq · Accepted Answer · 2018-05-29 17:11:36Z

1

Röda, 2 chain, 31 + 3 = 34 bytes

Snippet 1:

(`X.Z`/"")|ord _|push _+3|chr _

Try it online!

Snippet 2:

[1]

Try it online!

They are snippets, because every valid Röda program must include main{...} bloat. They are also valid Röda REPL programs.

answered May 29, 2018 at 17:11

fergusq

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brhfl · Accepted Answer · 2018-05-31 20:24:10Z

dc, 3 programs, 48 bytes

First:

82 2-adAArdAAI2*-rAAI-I2/2^-f

Yields the second:

Yields the third:

KZn

Yields 1.

Try it online! (has some stack-clearing and newline-printing code thrown in to make all three bits run in one go).

Perhaps best to start at program three, KZn. There are only a few ways to print things in dc, and I realized at this stage I would probably be stuck with either p or n, both of which are in the 100s in decimal ASCII. This means that I was almost certainly going to have to generate 1 instead of just using the program 1n. K pushes the current (default: 0) precision to the stack, and Z pushes the number of digits of top-of-stack, which gives us the 1 to print.

The second program is pretty straightforward. P prints the character with the given ASCII value, so we print 75 (K) 90 (Z) and finally 110 (n), which works wonderfully. It also means that, aside from the aforementioned 1, I can't use the digits 5, 7, 9, or 0 elsewhere. I also need a method other than P for turning numbers into characters.

The first program, then, has to make four numbers without using the digits 1, 5, 7, 9, or 0. It needs to make 80 (ASCII value of P): 82 2-; 75: AA (110) I- (subtract the default input radix, 10) I2/ (so, 5) 2^ (so, 5^2, 25) - (75); 90: AA (110) I2* (twice the default input radix of 10, so 20) - (90); and 110: well, it's just AA. After making 80, we use a to convert a number to a string. There are some reverse and duplicate commands in there to put the Ps in the right spots, and then finally we print the whole stack with f.

I'm pretty sure I didn't screw this up, but I did have my head spinning a little bit...

Muhammad Salman · Accepted Answer · 2018-06-02 16:41:12Z

1

05AB1E, 5 + 3 = 8 bytes

ght<n

Try it online!

which right off the bat returns

I am taking the output 1.0 as not equalling 1, so I run that code:

1.0

Try it online!

which returns

And there you go!

Number of programs = 2

edited Jun 2, 2018 at 16:41

Muhammad Salman

2,56112 silver badges41 bronze badges

answered Jun 2, 2018 at 15:29

Caleb Evans

113 bronze badges

\$\begingroup\$ Welcome to PPCG. \$\endgroup\$
– Muhammad Salman
Jun 2, 2018 at 15:45
\$\begingroup\$ I just tried to write random things and see what i get. Also, one might use a turing machine program. \$\endgroup\$
– Caleb Evans
Jun 2, 2018 at 17:19
\$\begingroup\$ You can remove the h (convert to hexadecimal). The g (get length, default 0) with t (square-root) already gives a decimal 0.0. With < (decrease by 1) it becomes -1.0 and then n (square) changes this into 1.0. You could also replace the <n with > (increase by 1). ;) So in total it's 3 bytes (gt>). Alternatively you could use Xt (1 and square-root). PS: I'm not sure if 1.0 to 1 is a valid part of the chain. I've asked OP to verify. Welcome to PPCG and enjoy your stay. \$\endgroup\$
– Kevin Cruijssen
Jun 4, 2018 at 15:06
\$\begingroup\$ well, computers process the string '1.0' differently than '1'. \$\endgroup\$
– Caleb Evans
Jun 9, 2018 at 23:54

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Community · Accepted Answer · 2020-06-17 09:04:33Z

0

Ruby, 2-chain, 24+3 = 27 bytes

$><<(''<<56+56<<' '<<49)

Output is

p 1

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered May 30, 2018 at 6:35

G B

19.9k1 gold badge19 silver badges50 bronze badges

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Code-generator with unique characters

Challenge

Rules:

Example:

27 Answers 27

05AB1E, 5-chain: 236 + 29 + 13 + 3 + 1 = 282 bytes

Java 8, chain of 2 functions, 90+10 37+4 28+4 = 32 bytes

R, 3-chain 198 + 44 + 3 bytes

R, 2-chain 27+3 24 + 2 bytes

Python 2, 2-Chain, 7+44 = 51 bytes

Perl 5, 3-chain, 151 139 chars (114 + 20 + 5)

Octave, 3 programs, Length 42 bytes

Cjam, 4-chain, 28+20+3+1=52 bytes

Snippet 1:

Snippet 2:

Snippet 3:

Snippet 4:

Excel, Chain 2, 27+3 bytes

x86 bytecode, Chain 2, 10+4 bytes

JavaScript REPL, lots of bytes, 4 iterate

JavaScript REPL, 164 bytes, 3 iterate

CJam, 7-chain, 92365+1819+79+14+9+3+1 bytes

MATL, 5 programs, 404+159+35+4+1 = 603 bytes

Explanation:

CJam, 10 programs, 5,751,122,990 bytes

Statistics

First bytes

Generator

APL (Dyalog), 2 chain, 15+2 = 17 bytes

JavaScript (ES6), 2 functions, 31+4 = 35 bytes

Jelly, 38 37 36 35 bytes, Chain of 4

How?

Python 2, 3 snippets, 68 + 12 + 3 = 83 bytes

Java 8, 3 programs, 431 bytes

Program 1, 332 bytes

Program 2, 93 bytes

Program 3, 6 bytes

SmileBASIC, chain 3, 375 bytes

PHP 7.0, 2-chain, 35 + 8 = 43 bytes

Run using php -r:

Output:

Comments:

Alternatively we can use "echO" and "ECHo", too (36 + 7 = 43 bytes).

My initial solution:

PHP 7.0, 2-chain, 44 + 10 = 54 bytes

Run using php -r:

Output:

Some comments:

Lua, 2 chain, 83+8=91 bytes

Charcoal, 2 programs, 10 + 2 = 12 bytes

Braingolf, 2 chain, 9 + 2 = 11 bytes

Röda, 2 chain, 31 + 3 = 34 bytes

dc, 3 programs, 48 bytes

05AB1E, 5 + 3 = 8 bytes

Ruby, 2-chain, 24+3 = 27 bytes

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