Print the largest String with the shortest Code [closed]

Question

As the title says, your task is to print the largest string using the shortest code without taking any input value.

Rules

• The program must take no input and print the largest string to STDOUT

• The string must contain only ASCII Characters. If you don't know the ASCII Characters, take a look at the table

• No Loops are allowed

• No multiplication, exponentiation or any kind of elevation is permitted.

• The score is measured by subtracting the amount of bytes of your code to the amount of bytes of your string. Example. My code is 60 Bytes and it generates an string of 300 Bytes. My score will be 300-60=240

• The highest score wins.

Example

try{a.b}catch(e){alert(e)}

The output of my program is ReferenceError: a is not defined = 32 bytes

My Score will be 32-26 = 6

---

Update

By Loops i mean any repetitive structure. For example for, while, do while, recursive functions etc..

Answer 1

R, 541-9 = 532

When passing a built-in function name to R, the console describes it parameters. I'm sure there are longer ones, but I went for the low-hanging fruit

Code:

.packages

Output:

function (all.available = FALSE, lib.loc = NULL) 
{
if (is.null(lib.loc)) 
    lib.loc <- .libPaths()
if (all.available) {
    ans <- character()
    for (lib in lib.loc[file.exists(lib.loc)]) {
        a <- list.files(lib, all.files = FALSE, full.names = FALSE)
        pfile <- file.path(lib, a, "Meta", "package.rds")
        ans <- c(ans, a[file.exists(pfile)])
    }
    return(unique(ans))
}
s <- search()
invisible(.rmpkg(s[substr(s, 1L, 8L) == "package:"]))
}
<bytecode: 0x103fdf200>
<environment: namespace:base>

Edit: Thanks Giuseppe for the link

Answer 2

Python 3, 937

help()

Try it online!