53
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The Illuminati commands you (with their mind control) to output the following string:

         ^
        /_\
       /_|_\
      /_|_|_\
     /_|/o\|_\
    /_|_\_/_|_\
   /_|_|_|_|_|_\
  /_|_|_|_|_|_|_\
 /_|_|_|_|_|_|_|_\
/_|_|_|_|_|_|_|_|_\

Rules:


Sandbox (I would leave it for the full 72 hours recommended by the sandbox FAQ, but with 7 upvotes and next to no negative feedback, 38 should be fine)

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  • 7
    \$\begingroup\$ just a small note, you should read this meta question/answer \$\endgroup\$ – Rod Oct 27 '17 at 16:42
  • 8
    \$\begingroup\$ What's with all the downvotes? I get that some people dislike kolmogorov-complex but is this a valid reason to downvote? \$\endgroup\$ – ბიმო Oct 27 '17 at 16:59
  • \$\begingroup\$ @BruceForte probably that I had my own answer to start. \$\endgroup\$ – Nissa Oct 27 '17 at 17:00
  • 14
    \$\begingroup\$ @BruceForte personal opinion is a valid reason, tbh; though IMO it's absolutely rude against a newer user. \$\endgroup\$ – Magic Octopus Urn Oct 27 '17 at 18:27
  • 15
    \$\begingroup\$ I think this is a very nice ascii art challenge. The eye and pyramid point among the pattern take creativity to handle cleanly. \$\endgroup\$ – xnor Oct 27 '17 at 20:51

23 Answers 23

23
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Charcoal, 25 21 bytes

G¬χ|_¶_|↗⁹↙^M³↓/o¶\‖B

Try it online! Link is to verbose version of code. Explanation:

  χ                     With sides of length 10
 ¬                      In the directions down and left
G                       Draw a closed polygon (implicit side)
   |_¶_|                Filled with |_ and _| on alternate lines
        ↗⁹               Draw a line of 9 /s
          ↙^            Draw a ^ and move the cursor down and left
            M³↓         Move down 3 characters
               /o¶\     Print the left half of the eye
                   ‖B  Reflect the canvas keeping the right edge
| improve this answer | |
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  • \$\begingroup\$ There it is! Was wondering how long it would be. \$\endgroup\$ – Nissa Oct 27 '17 at 16:59
  • 1
    \$\begingroup\$ @StephenLeppik I was on the phone :-( \$\endgroup\$ – Neil Oct 27 '17 at 17:00
  • \$\begingroup\$ Wait, is that the only reason? \$\endgroup\$ – Nissa Oct 27 '17 at 17:01
  • \$\begingroup\$ @StephenLeppik: well, that and depending how long before I noticed the notification for a new main post, I guess. \$\endgroup\$ – Neil Oct 27 '17 at 18:39
  • \$\begingroup\$ @DLosc < is one of the multidirectionals - when used with the Multiprint command it causes the string to be printed twice, once up right and once down right, but it can also be used as a shortcut for ↗↘ in other contexts too. \$\endgroup\$ – Neil Oct 27 '17 at 18:42
50
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Vim, 40 bytes

-2 bytes thanks to DJMcMayhem

9i_|␛r\I/␛qqYPxR /␛q8@qr^4jhR/o\␛jr/2hr\

You can see it in action in this GIF made using Lynn's python script

In action

| improve this answer | |
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10
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V, 37 bytes

9i|_á\|r/òÄó_|
>òC ^4jhR/o\j2hR\_/

Try it online!

Hexdump:

00000000: 3969 7c5f 1be1 5c7c 722f f2c4 f35f 7c0a  9i|_..\|r/..._|.
00000010: 3ef2 4320 5e1b 346a 6852 2f6f 5c1b 6a32  >.C ^.4jhR/o\.j2
00000020: 6852 5c5f 2f                             hR\_/

Explanation:

9i                              " Insert 9 copies of...
  |_                            "   '|_'
    <esc>                       " Return to normal mode
         á\                     " Append a backslash
           |                    " Move to the first character
            r/                  " Replace it with a forward slash
              ò                 " Recursively...
               Ä                "   Duplicate this line (upwards)
                ó               "   Remove one instance of..
                 _|             "     '_|'
>                               "   Indent this line with one space
 ò                              " End the loop
  C ^                           " Change this line (previously '/_\') to ' ^'
     <esc>                      " Return to normal mode
          4j                    " Move down 4 lines
            h                   " Move one character to the left
             R                  " Write this text over existing characters...
              /o\               "   '/o\'
                 <esc>          " Return to normal mode
                      j         " Move down a line
                       2h       " Move two characters to the left
                         R      " Write this text over existing characters...
                          \_/   " '\_/'
| improve this answer | |
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10
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SOGL V0.12, 31 27 25 bytes

 ^9∫Ƨ_|m└Κ}¹±§"/o¶\_”95žΓ

Try it Here!

 ^                         push "^"
  9∫      }                do 9 times, pushing counter
    Ƨ_|                      push "_|"
       m                     mold that to the counter
        └Κ                   prepend "/"
           ¹               collect the lines in an array - ["^", "/_", "/_|", ..., "/_|_|_|_|_"]
            ±              reverse each                    ["^", "_/", "|_/", ..., "_|_|_|_|_/"]
             §             reverse as ascii-art:
                            ["         ^",
                             "        /_",
                             "       /_|",
                             ...,
                             "/_|_|_|_|_"]
              "/o¶\_”      push "/o
                                 \_"
                     95ž   insert that at [9; 5]
                        Γ  palindromize horizontally

or a 24 byte version using ¼ (space to an antidiagonal) instead of ±§:

 ^9∫Ƨ_|m└Κ}¹¼"/o¶\_”95žΓ

Try it Here!

| improve this answer | |
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8
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Python 2, 103 101 98 95 bytes

-2 bytes thanks to Jonathan Frech
-3 bytes thanks to ovs

for i in range(10):print(9-i)*' '+['^','/_%s\\'%['|_'*~-i,'|/o\|_','|_\_/_|_'][i%6/4*i%3]][i>0]

Try it online!

| improve this answer | |
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8
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JavaScript (ES6), 95 92 bytes

f=(n=9,s='')=>n--?f(n,s+' ')+s+`/${n-4?n-3?'_|'.repeat(n):'_|/o\\|':'_|_\\_/_|'}_\\
`:s+`^
`

Or 91 bytes with a leading new-line -- which I think is not allowed:

f=(n=9,s=`
`)=>n--?f(n,s+' ')+s+`/${n-4?n-3?'_|'.repeat(n):'_|/o\\|':'_|_\\_/_|'}_\\`:s+`^`

Demo

f=(n=9,s='')=>n--?f(n,s+' ')+s+`/${n-4?n-3?'_|'.repeat(n):'_|/o\\|':'_|_\\_/_|'}_\\
`:s+`^
`

O.innerText = f()
<pre id=O></pre>

Formatted and commented

f = (n = 9, s = '') =>    // n = line counter, s = leading spaces
  n-- ?                   // if we haven't reached the top:
    f(n, s + ' ') +       //   do a recursive call with one more leading space
    s +                   //   append the leading spaces
    `/${                  //   append the left border
      n - 4 ?             //   if this is not the 4th row:
        n - 3 ?           //     if this is not the 3rd row:
          '_|'.repeat(n)  //       append the brick pattern
        :                 //     else (3rd row):
          '_|/o\\|'       //       append the top of the eye
      :                   //   else (4th row):
        '_|_\\_/_|'       //     append the bottom of the eye
    }_\\\n`               //   append the right border + line-feed
  :                       // else:
    s + `^\n`             //   append the top of the pyramid and stop the recursion
| improve this answer | |
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  • \$\begingroup\$ Leading whitespace is allowed. \$\endgroup\$ – Nissa Nov 13 '17 at 17:18
8
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C (gcc), 124 122 120 119 117 115 118 bytes

-1 byte thanks to @xanoetux +3 missing the lowest level...

f(i){for(printf("%*c",i=10,94);--i;printf("\n%*c%s_\\",i,47,i^6?i^5?"_|_|_|_|_|_|_|_|_|"+i*2:"_|_\\_/_|":"_|/o\\|"));}

Try it online!

| improve this answer | |
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5
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Haskell, 110 107 bytes

"         ^\n"++do z<-[1..9];([z..8]>>" ")++'/':g z++"_\\\n"
g 4="_|/o\\|"
g 5="_|_\\_/_|"
g x=[2..x]>>"_|"

Try it online!

Those 9 space at the beginning hurt.

How it works

"         ^\n"++         -- first line, followed by
do                       -- we use the "do" syntatic sugar for monads,
                         -- here the list monad 
   z<-[1..9]             -- for all 'z' from [1..9] perform the following
                         -- and collect the results in a single list
     ([z..8]>>" ")++'/'  --   make the spaces for the current line and
                         --   the left wall '/'
     g z                 --   call g to make the inner part
     "_\\\n"             --   append '_', '\' and a NL

g 4="_|/o\\|"            -- line 4 and 5 are implemented directly
g 5="_|_\\_/_|"
g x=[2..x]>>"_|"         -- all other lines are some copies of "_|"

Edit: -3 bytes thanks to @Laikoni:

| improve this answer | |
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4
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PowerShell, 109 105 bytes

filter f{' '*$_+'/'+'_|'*(8-$_)+'_\'}
' '*9+'^'
8|f
7|f
6|f
'     /_|/o\|_\
    /_|_\_/_|_\'
3..0|%{$_|f}

Try it online!

Saved 4 bytes thanks to Veskah.

| improve this answer | |
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3
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05AB1E, 47 42 40 bytes

'/„_|ûûû«η'^0ǝ.∞.C":;<IJK"Çv"/o\\_/"Nèyǝ

Try it online!

'/„_|ûûû«                                # Push bottom left tier of pyramid.
         η                               # All prefixes of...
          '^0ǝ                           # Replace the tip.
              .∞.C                       # Mirror, Center.
                  ":;<IJK"Ç              # Push [58,59,60,73,74,75].
                           v"/o\\_/"Nèyǝ # Replace those indexes with the eye.

Stupid version: „_|3×"_|/o\|".;„_|2×û"_|_\_/_".;


Other, less stupid version (but still worse):

05AB1E, 42 bytes

•~µÎт•η4¾ǝ•Σ}•4ǝ•3x1•5ǝεS"|_/\^o"sèJ}€.∞.C

Try it online!

| improve this answer | |
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2
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Bubblegum, 48 bytes

00000000: 5380 8138 2e18 4b3f 3e86 0bce ac01 72e0  S..8..K?>.....r.
00000010: 6c30 0fc6 d1cf 8f01 71e1 cae2 218a e12a  l0......q...!..*
00000020: 6ba0 ea61 7c84 085c 0021 0417 4188 0100  k..a|..\.!..A...

Try it online!

| improve this answer | |
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2
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PHP, 123+3 bytes

+3 bytes for the weird tab counting. (it still moves the cursor 8 spaces in any console!)

for($i=10;--$i;)$r.=str_pad(str_pad("
",$i)."/",20-$i,"_|")."\\";$r[48]=$r[65]="/";$r[50]=$r[63]="\\";$r[49]=o;echo"   ^$r";

Note: The first character after echo" is a tab character!

Run with -nr or try it online.

other version, same length:

for(;$i++<9;)$r.=str_pad(str_pad("
",10-$i)."/",10+$i,"_|")."\\";$r[48]=$r[65]="/";$r[50]=$r[63]="\\";$r[49]=o;echo"    ^$r";
| improve this answer | |
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  • \$\begingroup\$ What about Eclipse? I haven't used it in a while but I remember that its tabs were 4 spaces. \$\endgroup\$ – Nissa Oct 27 '17 at 22:51
  • \$\begingroup\$ @StephenLeppik Eclipse is an editor, not a shell. \$\endgroup\$ – Titus Oct 27 '17 at 23:05
  • \$\begingroup\$ It still has a console. Not to mention that the SE markdown editor and <pre> tag font both have 4-space tabs \$\endgroup\$ – Nissa Oct 27 '17 at 23:44
2
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Retina, 79 73 bytes


/8x
8
$*
+`^(.*)\Sx
 $1x¶$&
 x
 ^
/111x
/1/o\|x
/1111x
/1x_/1x
1
_|
x
_\

Try it online!

| improve this answer | |
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2
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Ruby, 92 bytes

10.times{|i|s=' '*(10-i)+(i<1??^:"/#{"_|"*~-i}_\\");i/2==2&&s[9,3]="/o\\_/"[i%2*2,3];puts s}
| improve this answer | |
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2
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Excel VBA, 104 Bytes

Anonymous VBE immediate window function that confirms the truth.

Version A:

?Spc(9)"^":For i=0To 8:[A1]=i:?Spc(8-i)"/_"[If(A1=3,"|/o\|_",If(A1=4,"|_\_/_|_",Rept("|_",A1)))]"\":Next

Version B:

?Spc(9)"^":For i=0To 8:[A1]=i:?Spc(8-i)"/_"IIf(i=3,"|/o\|_",IIf(i=4,"|_\_/_|_",[Rept("|_",A1)]))"\":Next
| improve this answer | |
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2
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Python 2, 154 bytes

l=bytearray
a,b=' _';g=[l(a*9+"^"+a*9)]+[l(a*(8-k)+"/%s\\"%"|".join(b*k+b))for k in range(9)]
g[4][8:11]=l("/o\\")
g[5][8:11]=l("\\_/")
for r in g:print r

Try it online!

-3 bytes using bytearray thanks to Rod
-1 byte thanks to bobrobbob

| improve this answer | |
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1
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Javascript 90 bytes (if default parameter a=9 is required then 92 bytes)

A=(a,x=``)=>a?A(a-1,x+" ")+x+"/".padEnd(a*2,a^5?a^4?"_|":"_|/o\\|":"_|_\\_/")+`\\
`:x+`^
`
console.log(A(9))

| improve this answer | |
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  • \$\begingroup\$ All extraneous arguments must be included in the byte total so this counts as 91 bytes \$\endgroup\$ – Nissa Oct 31 '17 at 13:34
1
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Java 8, 156 bytes

v->"".format("%1$9s^\n%1$8s/a%1$7s/ba%1$6s/bba     /b/o\\|a    /b_\\_/ba   /bbbbba  /bbbbbba /bbbbbbba/bbbbbbbba","").replace("a","_\\\n").replace("b","_|")

Explanation:

Try it here.

v->                        // Method with empty unused parameter and String return-type
  "".format(               //  Format the following String (`%1$Ns` = N spaces)
      "%1$9s^\n            //            ^
       %1$8s/a             //           /_\
       %1$7s/ba            //          /_|_\
       %1$6s/bba           //         /_|_|_\
            /b/o\\|a       //        /_|/o\|_\
           /b_\\_/ba       //       /_|_\_/_|_\
          /bbbbba          //      /_|_|_|_|_|_\
         /bbbbbba          //     /_|_|_|_|_|_|_\
        /bbbbbbba          //    /_|_|_|_|_|_|_|_\
       /bbbbbbbba","")     //   /_|_|_|_|_|_|_|_|_\
    .replace("a","_\\\n")  //  Replace all "a" with "_\" + new-line
    .replace("b","_|")     //  Replace all "b" with "_|"
                           // End of method (implicit / single-line return-statement)
| improve this answer | |
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1
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Julia, 152 141 139 130 127 120 113 112 bytes

q="_|";a+b=" "^a*b;a\b=replace(a,q^3,q*b,1);~n=n<0?9+"^\n":~(n-1)*(8-n+"/$(q^n)_\\\n");print(~8\"/o\\|"\"_\\_/")

Explained:

#Define constant q to abbreviate this string
q="_|";

#Redefine the addition operator to compactly provide whitespace 
#where needed
a+b=" "^a*b;

#Redefine the inverse division operator so we can substitute 
#"_|_|_|" with "_|"*b very compactly
a\b=replace(a,q^3,q*b,1);

#Redefine the bitwise not operator to generate pyramid layers
#Defines them recursively, calling itself to generate previous 
#layers before appending its own. 
#The base case generates the tip. 
~n=n<0?9+"^\n":~(n-1)*(8-n+"/$(q^n)_\\\n");

#Print to output
print(

    #Pyramid with 8 body layers
    ~8

    #Then patch in the eye
    \"/o\\|"
    \"_\\_/"
)
| improve this answer | |
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1
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C# (.NET Core), 174 153 bytes

()=>string.Format(@"{1,10}
{0,10}\
{0,9}{2}{3,10}{2}{0,7}|/o\{2}{3,8}\_/_{2}{0,5}{4}  {3}{4} {3}|_{4}{3}|_|_{4}","/_","^",@"|_\
","/_|_",@"|_|_|_|_|_\
")

Try it online!

An inefficient way of building the pyramid, but interesting working through it.

Acknowledgements

-21 bytes thanks to @someone

| improve this answer | |
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1
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C# (.NET Core), 144 bytes

This one may seem quite boring, because it is quite boring.

()=>@"         ^
        /_\
       /z\
      /z|_\
     /_|/o\|_\
    /z\_/z\
   /z|z|z\
  /z|z|z|_\
 /z|z|z|z\
/z|z|z|z|_\".Replace("z","_|_")

Try it online!

| improve this answer | |
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0
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JavaScript, 117 bytes

I know for a fact I'm not beating any of the golfing languages, but at least I can give my own solution.

$=>[...Array(10)].map((e,i)=>' '.repeat(9-i)+(i--?`/${['_|/o\\|','_|_\\_/_|'][i-3]||'_|'.repeat(i)}_\\`:'^')).join`
`

Here's a demo:

var f = $=>[...Array(10)].map((e,i)=>' '.repeat(9-i)+(i--?`/${['_|/o\\|','_|_\\_/_|'][i-3]||'_|'.repeat(i)}_\\`:'^')).join`
`;
console.log(f());
console.log(f.toString().length);

Explanation:

$=>                                       // outer function start
[...Array(10)]                            // create an array to map
.map(…)                                   // map it
    (e,i)=>                               // mapping function start
    ' '.repeat(9-i)                       // spaces for padding
    +(i--?…:'^')                          // use the carat if at the top of the pyramid
        `/${…}_\\`                        // otherwise, make the sides + steps
            ['_|/o\\|','_|_\\_/_|'][i-3]  // use the patterns for the eye, if in the correct rows
            ||'_|'.repeat(i)              // otherwise, make the "bricks" structure
.join`
`                                         // join all the rows into a string (yes this part has a newline in it)
| improve this answer | |
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  • 4
    \$\begingroup\$ It's not recommended to answer straight away, let people make their own solutions. \$\endgroup\$ – Okx Oct 27 '17 at 16:42
0
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Javascript, 238 bytes

My very first try at codegolfing :D

var f=()=>{let b=x=>' '.repeat(x),g='\\',h='/',i=1,st=[(b(9)+'^').split('')];for(;i<10;i++)st.push((b(9-i)+h+st.map(i=>'_').join('|')+g).split(''));st[4][8]=st[5][10]=h;st[4][9]='o';st[5][8]=st[4][10]=g;return st.map(s=>s.join('')).join('\n');}

document.getElementById("display").innerHTML = f();
console.log(f.toString().length);
<pre id="display">
</pre>

| improve this answer | |
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  • 1
    \$\begingroup\$ Welcome to the site! \$\endgroup\$ – caird coinheringaahing Oct 31 '17 at 14:36
  • \$\begingroup\$ Hardcoding is definitely shorter than what you have here. You can shorten this with a few ES6 features: function`s` instead of function('s'), a=> instead of ()=>, fill(x) instead of map(e=>x), [...s] instead of s.split(''), move a statement into the for initialization, etc. \$\endgroup\$ – Nissa Oct 31 '17 at 15:21

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