It's a find-a-movie challenge

Question

This is a simple(ish) web scraping challenge.

Input

Your code should take an MPAA film rating and a number from 0 to 100 as input. It can do this in any way you find convenient.

Output

Your code should return the name of any movie which has a) that film rating and b) the numerical score on the Tomatometer from rottentomatoes.

If there is no such movie it can output anything you like.

The possible MPAA film ratings are G, PG, PG-13, R, NC-17, NR.

Your code may report one or more movies, that is up to you.

To clarify, your code is meant to access the web to get the answers to queries.

Example

Say the input is "PG, 98" then your code could output "Zootropolis".

Please show an example of your code working with the film rating PG and score 98 along with your answer.

Answer 1

Bash, 182 bytes

curl "https://www.rottentomatoes.com/api/private/v2.0/browse?minTomato=$2&maxTomato=$2&type=dvd-streaming-all" 2>/dev/null|grep -o "{[^}]*aRating\":\"$1\""|grep -Po 'title":"\K[^"]*'

Usage:

$ bash script PG 98
The Island President
Inside Out
Zootopia
Paddington
Love & Friendship
Long Way North (Tout en haut du monde)

Answer 2

JavaScript (ES6), 167 162 159 bytes

Needs to be run from the root of rottentomatoes.com. Returns a Promise object containing the title.

s=>n=>fetch(`api/private/v2.0/browse?minTomato=${n}&maxTomato=${n}&type=dvd-streaming-all`).then(r=>r.json()).then(j=>j.results.find(x=>x.mpaaRating==s).title)

If we can require that it be run in a specific directory then it becomes 139 bytes:

s=>n=>fetch(`browse?minTomato=${n}&maxTomato=${n}&type=dvd-streaming-all`).then(r=>r.json()).then(j=>j.results.find(x=>x.mpaaRating==s).title)

Answer 3

Python 2 + requests, 209 204 bytes

-5 bytes thanks to Ian Gödel.

lambda r,t:[i['title']for i in get('http://rottentomatoes.com/api/private/v2.0/browse?minTomato=%d&maxTomato=%d&type=dvd-streaming-all'%(t,t)).json()['results']if i['mpaaRating']==r]
from requests import*

Answer 4

Stratos, 133 bytes

{
f"www.rottentomatoes.com/api/private/v2.0/browse?minTomato=%&maxTomato=%&type=dvd-streaming-all"r"results")s"mpaaRating"=⁰
s"title"

Try it!

Answer 5

q/kdb+, 168 bytes

Solution:

{(r(&)(r:.j.k[.Q.hg`$"https://www.rottentomatoes.com/api/private/v2.0/browse?type=dvd-streaming-all&min",t,"&max",t:"Tomato=",y]`results)[;`mpaaRating]like x)[;`title]}

Example:

q){(r(&)(r:.j.k[.Q.hg`$"https://www.rottentomatoes.com/api/private/v2.0/browse?type=dvd-streaming-all&min",t,"&max",t:"Tomato=",y]`results)[;`mpaaRating]like x)[;`title]}["PG";"98"]
"The Island President"
"Inside Out"
"Zootopia"
"Paddington"
"Love & Friendship"
"Long Way North (Tout en haut du monde)"

Explanation:

.Q.hg           / fetch a URL
.j.k            / parse json string into Q dictionaries
`results        / index into dictionary with key `results
[;`mpaaRating]  / index into these sub dictionaries extracting mpaaRating
like x          / binary list where they match, e.g. "PG"
(&)             / where, list indices where true
[;`title]       / index into dictionary with key `title

Notes:

• If you want to try this out yourself, take a read through the Cookbook/SSL page to ensure your environment is setup correctly.
• Fails if we remove the s of https, or the www., gives 301 Permanently Moved response.

Answer 6

JavaScript (ES2017), 158 bytes

async(r,n)=>(await(await fetch(`api/private/v2.0/browse?minTomato=${n}&maxTomato=${n}&type=dvd-streaming-all`)).json()).results.find(m=>m.mpaaRating==r).title

Run from the Rotten Tomatoes home page:

f=async(r,n)=>(await fetch(`api/private/v2.0/browse?minTomato=${n}&maxTomato=${n}&type=dvd-streaming-all`).then(x=>x.json())).results.find(m=>m.mpaaRating==r).title
f('PG',98).then(console.log)