27
\$\begingroup\$

Background

When I was younger, I was taught a method of drawing a weird "S" shape, that I (along with my classmates) found fascinating. Today, I rediscovered it, and due to its formulaic approach to drawing it, thought it could lead to an interesting challenge :P

Drawing the "S"

The S can be drawn by following these simple steps:

First, draw 2 rows of three vertical lines like so

| | |

| | |

Next, connect the top left line with the bottom middle line and the top middle with the bottom right line to produce

| | |
 \ \
| | |

Finally, draw a top and bottom on the currently drawn image so that it ends up looking like

  ^
 / \
| | |
 \ \
| | |
 \ /
  v

As you can see, this results in an "S" shape. When extended however (drawing it with more than 2 rows), it produces a very interesting pattern. Your task is reproduce this interesting pattern.

Task

Given an integer where n >= 2, output The S with n rows to be made from it. Output may be returned from a function, and input may be taken in standard methods. Trailing/leading whitespace for both the overall image, as well as each line, is fine. However, leading line spaces must be consistent so that the " isn't broken. You may output as a list of lines.

Test cases

input
output
---

2

  ^
 / \
| | |
 \ \
| | |
 \ /
  v

---

8
  ^
 / \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ /
  v

---

10

  ^
 / \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ \
| | |
 \ /
  v

This is a so shortest code wins! Good luck,

\$\endgroup\$
  • 13
    \$\begingroup\$ Wikipedia calls the S the Cool S, and calls an infinite version of the an S Chain \$\endgroup\$ – Stephen Sep 20 '17 at 19:16
  • \$\begingroup\$ Can we output as a list of lines? \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 19:17
  • \$\begingroup\$ @Mr.Xcoder you may \$\endgroup\$ – caird coinheringaahing Sep 20 '17 at 19:17
  • \$\begingroup\$ @Stephen 10 minutes googling and this didn't come up. I'll edit the name of the question \$\endgroup\$ – caird coinheringaahing Sep 20 '17 at 19:18
  • \$\begingroup\$ @cairdcoinheringaahing I searched images, that might have been it :P \$\endgroup\$ – Stephen Sep 20 '17 at 19:19

39 Answers 39

15
\$\begingroup\$

Python 2, 47 bytes

lambda k:'  ^\n / '+'\\\n| | |\n \ '*k+'/\n  v'

Try it online!

\$\endgroup\$
10
\$\begingroup\$

C# (.NET Core), 73 69 66 64 62 bytes

Two less bytes and perl-like appearance thanks to Barodus. Didn't think of using int? for nulls.

n=>$@"  ^
 / {string.Join(@"\
| | |
 \ ",new int?[++n])}/
  v"

Try it online!

\$\endgroup\$
  • 1
    \$\begingroup\$ If this was a golf of the existing C# answer, I'd never have been able to tell. Well done :-) \$\endgroup\$ – ETHproductions Sep 21 '17 at 3:08
  • \$\begingroup\$ Can you explain what the new string[n+1] does? I have never seen it before. \$\endgroup\$ – Ian H. Sep 21 '17 at 7:39
  • \$\begingroup\$ Creates a array of empty strings AFAIK. I've used a hack with string.Join, aka join {"","","",""} with separator "\ \n | | | \n \" \$\endgroup\$ – someone Sep 21 '17 at 7:40
  • \$\begingroup\$ @someone Woah, I never acknowledged this trick before. Really cool! (Also my bad, i though the new string[n+1] was some kind of tricky string constructor and not an array declaration -.-) \$\endgroup\$ – Ian H. Sep 21 '17 at 8:35
6
\$\begingroup\$

Python 3, 48  56 59 61  bytes

lambda k:'  ^\n / %s/\n  v'%('\\\n| | |\n \ '*k)

Try it online!

\$\endgroup\$
  • \$\begingroup\$ You can save 2 bytes by unescaping the lone backslashes. \$\endgroup\$ – L3viathan Sep 20 '17 at 19:27
  • \$\begingroup\$ @L3viathan Just updating too \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 19:27
  • \$\begingroup\$ 56 bytes; not sure if this is fair game; doesn't work on TIO \$\endgroup\$ – L3viathan Sep 20 '17 at 19:36
  • \$\begingroup\$ @L3viathan That is not correct. Extra \ \. \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 19:36
  • \$\begingroup\$ On TIO: yes. In my terminal: no. \$\endgroup\$ – L3viathan Sep 20 '17 at 19:37
6
\$\begingroup\$

05AB1E, 27 26 bytes

…^
/ð"\
| | |
\ "I×…/
vJ.c

Try it online!

Alternate 27 byte version

'^…/ \©IF…| |û…\ \}\®R'v».c

Try it online!

Explanation

'^                             # push "^"
  …/ \©                        # push "/ \" and store a copy in register
       IF                      # input times do:
         …| |û                 # push "| | |"
              …\ \             # push "\ \"
                  }            # end loop
                   \           # discard top of stack (the extra "\ \")
                    ®R         # push "/ \" reversed = "\ /"
                      'v       # push "v"
                        »      # join stack on newlines
                         .c    # center each row
\$\endgroup\$
  • 5
    \$\begingroup\$ Your code looks a bit like an elephant to me :) \$\endgroup\$ – Wojowu Sep 21 '17 at 10:58
  • \$\begingroup\$ It's literally SCARY how close my answer was to yours: '^…/ \©IF„| ûû„\ û}\®R'v).C without looking. \$\endgroup\$ – Magic Octopus Urn Sep 21 '17 at 15:48
6
\$\begingroup\$

Japt, 34 25 23 bytes

" ^ /{ç'\²i|³1}/ v"¬¸ò5

Test it online! Outputs as an array of lines; -R flag added to join on newlines. (Thanks @Shaggy)

First Second attempt, might be improvable...

How it works

" ^ /{ ç'\²  i |³  1}/ v"¬ ¸  ò5
" ^ /{Uç'\p2 i'|p3 1}/ v"q qS ò5   Ungolfed
                                   Implicit: U = input number
        '\p2                       Repeat a backslash twice, giving "\\".
             i     1               Insert at index 1
              '|p3                   3 vertical bars. This gives "\|||\".
      Uç                           Make U copies of this string. U = 2: "\|||\\|||\"
" ^ /{              }/ v"          Insert this into this string.    " ^ /\|||\\|||\/ v"
                         q qS      Split into chars; join on spaces."  ^   / \ | | | \ \ | | | \ /   v"
                              ò5   Split into rows of length 5.    ["  ^  "," / \ ","| | |"," \ \ ","| | |"," \ / ","  v"]
                                   Joining on newlines gives "  ^  
                                                               / \ 
                                                              | | |
                                                               \ \
                                                              | | |
                                                               \ /
                                                                v"
\$\endgroup\$
  • \$\begingroup\$ Beating Charcoal and tying SOGL? Excellent work! \$\endgroup\$ – Shaggy Sep 21 '17 at 9:30
  • \$\begingroup\$ You can output an array of lines, by the way, so you can ditch the last 2 characters. \$\endgroup\$ – Shaggy Sep 21 '17 at 10:46
  • \$\begingroup\$ @Shaggy That's great, now we're winning! \$\endgroup\$ – ETHproductions Sep 21 '17 at 17:24
  • \$\begingroup\$ We've been doing well lately :) \$\endgroup\$ – Shaggy Sep 22 '17 at 10:40
6
\$\begingroup\$

SOGL V0.12, 26 25 18 bytes

°I-‘*"∑ūCƨΩ)¹‘@∑5n

Try it Here!

Uses the same strategy as ETHproductions's Japt answer

Explanation:

..‘           push "\|||\"
   *          repeat input times
    "..‘      push " ^ /ŗ/ v ", with ŗ replaced with POP. The reason why there's a trailing
              space is because otherwise it didn't have enough repeating characters to compress
        @∑    join with spaces
          5n  split to line lengths of 5
\$\endgroup\$
  • 2
    \$\begingroup\$ push "|" and " " what the heck is that builtin \$\endgroup\$ – Steven H. Sep 20 '17 at 19:35
  • 1
    \$\begingroup\$ @StevenHewitt those are actually two built-ins, but I joined them together (as I do with other stuff) because I don't think it's not necessary to separate stuff that gets used together soon \$\endgroup\$ – dzaima Sep 20 '17 at 19:37
5
\$\begingroup\$

JavaScript (ES6), 60 bytes

n=>`  ^
 / \\
${`| | |
 \\ \\
`.repeat(n-1)}| | |
 \\ /
  v`

Test Snippet

let f=
n=>`  ^
 / \\
${`| | |
 \\ \\
`.repeat(n-1)}| | |
 \\ /
  v`
;(I.oninput=_=>O.innerHTML=I.value+"\n"+f(+I.value))()
<input id=I type=range min=2 max=15 value=2><pre id=O></pre>

\$\endgroup\$
  • 1
    \$\begingroup\$ 57: n=>' ^\n /${' \\ \\\n| | |\n'.repeat(n).slice(2)} \\ /\n v' (using backticks and literal newlines) \$\endgroup\$ – edc65 Sep 21 '17 at 9:15
5
\$\begingroup\$

Charcoal, 27 26 25 bytes

-1 byte thanks to Carlos Alejo. -1 byte thanks to ASCII-only.

  ^⸿ / ×\⸿| | |⸿ \ N/⸿  v

Try it online! Link is to verbose version. #charcoal-verbose-obfucation

\$\endgroup\$
  • 1
    \$\begingroup\$ You can save 1 byte by just calling Print (instead of adding the strings) and using \r: ` ^⸿ / ×\⸿| | |⸿ \ Iθ/⸿ v`. Verbose version. \$\endgroup\$ – Charlie Sep 21 '17 at 7:09
  • \$\begingroup\$ Ah... I'll have to remember \r as the way to get newlines the sane way. Thanks! \$\endgroup\$ – totallyhuman Sep 21 '17 at 15:43
  • \$\begingroup\$ 25 bytes \$\endgroup\$ – ASCII-only Oct 4 '17 at 11:25
  • \$\begingroup\$ @ASCII-only :P - \$\endgroup\$ – totallyhuman Oct 4 '17 at 12:54
4
\$\begingroup\$

Perl 5, 39 37 bytes

say"  ^
 / ".'\
| | |
 \ 'x<>."/
  v"

Try it online!

Shaved two bytes with @DomHastings' suggestion

\$\endgroup\$
  • \$\begingroup\$ If you use single quotes, you don't need to escape the backslashes for -2! :) \$\endgroup\$ – Dom Hastings Oct 27 '17 at 12:41
3
\$\begingroup\$

Actually, 49 bytes

"| | |"@α;lD" \ \"@α@Z♂ii"  v"" \ /"))" / \""  ^"

Try it online!

Explanation:

"| | |"@α;lD" \ \"@α@Z♂ii"  v"" \ /"))" / \""  ^"
"| | |"@α                                          push a list containing n copies of the vertical lines
         ;lD" \ \"@α                               push a list containing n-1 copies of the diagonal connections
                    @Z♂i                           interleave
                        i                          flatten
                         "  v"" \ /"))             make the bottom
                                      " / \""  ^"  make the top
\$\endgroup\$
3
\$\begingroup\$

05AB1E, 38 bytes

…| |ûU"  ^
 / \"XI<F„ \2×X}" \ /
  v"»

Try it online!

…| |                         # Push "| |"
    û                        # Palindromize
     U                       # Store in X
      "..."X                 # Push the top three rows
            I<F      }       # One less than input times do:
               „ \           #   Push " \"
                  2×         #   Concatenate that with itself
                    X        #   Push "| | |"
                      "..."  # Push the last two rows
                           » # Join stack with newlines
\$\endgroup\$
3
\$\begingroup\$

Pyth, 33 32 31 bytes

Thanks Mr. Xcoder for one byte.

%"  ^
 / %s/
  v"*tj\|_B" \\
| 

Try it online: Demonstration or Test Suite

\$\endgroup\$
  • \$\begingroup\$ Very nice answer! You can bring it down to 32 bytes. \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 20:07
  • 2
    \$\begingroup\$ 31 bytes, in fact. \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 20:07
3
\$\begingroup\$

C (gcc), 82 bytes

f(n){for(puts("  ^\n / \\");--n;puts("| | |\n \\ \\"));puts("| | |\n \\ /\n  v");}

Try it online!

\$\endgroup\$
3
\$\begingroup\$

C# (.NET Core), 101 77 73 bytes

Saved 24 bytes thanks to i cri everytim!
Saved 4 bytes thanks to Kevin Cruijssen!

n=>{var s="  ^\n / ";for(;n-->0;s+="\\\n| | |\n \\ ");return s+"/\n  v";}

Try it online!

As per usual, string repeating in C# is a pain.

\$\endgroup\$
  • \$\begingroup\$ 77 bytes. \$\endgroup\$ – totallyhuman Sep 20 '17 at 21:54
  • \$\begingroup\$ @icrieverytim Ahhh, of course, thats way better. \$\endgroup\$ – Ian H. Sep 21 '17 at 7:39
  • \$\begingroup\$ You can change --n>=0 to n-->0 and s+="/\n v";return s; to return s+"/\n v"; to save some bytes. \$\endgroup\$ – Kevin Cruijssen Sep 21 '17 at 7:54
  • 1
    \$\begingroup\$ @KevinCruijssen Thanks, fixed! \$\endgroup\$ – Ian H. Sep 21 '17 at 9:15
3
\$\begingroup\$

Retina, 38 bytes

.+
$*
1
¶|||¶x\\
^
 ^¶x/\
.$
/¶ v
x?
 

Try it online!

Prints a column of leading spaces and on trailing space on each line.

Explanation

The main byte savings come from omitting the spaces in all the literal parts and inserting them at the end. The figure is structured such that there are never two non-spaces next to each other, so if we just remove them all, we can almost fix the shape by inserting a space at every position at the end:

^
/\
|||
\\
|||
\/
v

becomes:

 ^ 
 / \ 
 | | | 
 \ \ 
 | | | 
 \ / 
 v 

That's almost correct, except for indentation. The ^ and v are missing two spaces. That's actually easier to fix, because if we just insert an explicit space in front of each of them, that'll result in two additional spaces at the end. The lines with the slashes are trickier because they require just one additional space. To fix this, we insert a placeholder character there (x). When we insert the spaces at the end, we don't just insert them for every empty match, but we optionally match that x. That means instead of inserting a space in front of the x, the x itself gets replaced. And then there will still be an empty match right after the x. That means, every x adds exactly one space without changing anything else. So what we want to set up is this:

 ^
x/\
|||
x\\
|||
x\/
 v

which will give us the desired result. So here's the code:

.+
$*

Convert the input to unary.

1
¶|||¶x\\

Convert each 1 to two lines with ||| and x\\ (and a leading linefeed).

^
 ^¶x/\

Inser the first two lines with ^ and x/\.

.$
/¶ v

Fix the final x\\ by turning the last \ into / and appending a line with the v.

x?
 

Replace each x or empty match with a space.

\$\endgroup\$
  • \$\begingroup\$ Neat approach. I was trying to figure out a way to use join-on-spaces for my Pip solution, but it didn't quite work due to the different numbers of leading spaces on different rows. \$\endgroup\$ – DLosc Sep 21 '17 at 16:21
2
\$\begingroup\$

Pyth, 46 bytes

"  ^
 / \\"
+*j[jd*\|3" \ \\"k))Q" \ /
  v

Test suite.

\$\endgroup\$
  • \$\begingroup\$ 36 bytes: %" ^\n / %s/\n v"*Q"\\\n| | |\n \ \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 20:05
  • \$\begingroup\$ 31 bytes. \$\endgroup\$ – Mr. Xcoder Sep 20 '17 at 20:11
2
\$\begingroup\$

Pyth, 40 bytes

K" / \ ""  ^"Kj+b+*2+d\\b*Q]*3"| "_K"  v

Fairly similar to Steven Hewitt's, but developed independently.

Try it Online

Explanation

K" / \ ""  ^"Kj+b+*2+d\\b*Q]*3"| "_K"  v
K" / \ ""                                 Set K = " / \ "
        "  ^"                       "  v  Draw the end points.
             K                    _K      Draw the slants.
                         *Q]*3"| "        Draw the vertical bars...
              j+b+*2+d\\b                 ... interspersed with slants.
\$\endgroup\$
2
\$\begingroup\$

Retina, 45 bytes

This is a pretty simple solution.

.+
$*
^1
  ^¶ /x
$
 \ /¶  v
1
 \x
x
 \¶| | |¶

Try it online

If the art could be 1-indexed instead, it'd be a bit shorter (44 bytes):

.+
  ^¶ /x$0$*1
$
 \ /¶  v
1
 \x
x
 \¶| | |¶
\$\endgroup\$
2
\$\begingroup\$

Pip, 45 42 33 bytes

"  ^
 / "."\
| | |
 \ "Xa."/
  v"

Try it online!

Explanation

The code is really simple, though the newlines make it harder to read. Here's a better way to see the structure:

"prefix" . "repeated" X a . "suffix"

The repeated element in the S-chain is

   \
| | |
 \

Take this as a literal string and repeat it a times (where a is the first command-line argument). Then prepend the prefix:

  ^
 /

and append the suffix:

   /
  v

and print.

(I like how this ended up looking kinda like a ><> program.)

\$\endgroup\$
  • \$\begingroup\$ This looks like Lumpy Space Princess from Adventure Time :) \$\endgroup\$ – YSC Sep 21 '17 at 15:30
2
\$\begingroup\$

MATL, 47 44 43 bytes

-3 bytes thanks to Giuseppe

'  ^' ' / \ 'XK'| | |'XJGq:"' \'thJ]KP'  v'

Try it online!

\$\endgroup\$
  • \$\begingroup\$ ' ^' ' / \ 'XK'| | |'XJ`' \ \'JGq@-]KP' v' is 44 bytes. \$\endgroup\$ – Giuseppe Sep 21 '17 at 17:53
1
\$\begingroup\$

Haskell, 53 bytes

f n="  ^\n /"++([1..n]>>" \\\n| | |\n \\")++" /\n  v"

Try it online!

\$\endgroup\$
1
\$\begingroup\$

Excel, 60 bytes

="  ^
 / \
"&REPT("| | |
 \ \
",A1-1)&"| | |
 \ /
  v"
\$\endgroup\$
  • \$\begingroup\$ You should consider checking to see if this is a polyglot with Google Sheets \$\endgroup\$ – Taylor Scott Oct 4 '17 at 14:23
1
\$\begingroup\$

PowerShell, 83, 57 bytes

"  ^
 / \"
1..--$args[0]|%{"| | |
 \ \"}
"| | |
 \ /
  v"

Try it online!

Per @AdmBorkBork's suggestions,

  • Simplified for by using a number range.
  • Replaced ;'s and combined strings.
  • Removed an unnecessary variable definition.
\$\endgroup\$
  • \$\begingroup\$ You can golf your for loop a lot by using 1..--$args[0]|%{ }. \$\endgroup\$ – AdmBorkBork Sep 21 '17 at 12:34
  • \$\begingroup\$ Also, you can use literal newlines between the adjacent strings to save on ";" and it's cheaper to get rid of $s entirely. 57 bytes \$\endgroup\$ – AdmBorkBork Sep 21 '17 at 12:40
  • \$\begingroup\$ Slick. I like the newline save. Funny that I missed the 1..$args opportunity. I'm not sure what the correct etiquette is on this site. Do I make changes to my answer and credit you, or do you post your solution as a separate answer? \$\endgroup\$ – root Sep 21 '17 at 13:09
  • \$\begingroup\$ Editing in the changes and giving credit is the proper etiquette. Welcome to PPCG. \$\endgroup\$ – AdmBorkBork Sep 21 '17 at 13:27
1
\$\begingroup\$

AsciiDots, 88 bytes

.*$"  ^"$" / \"
/>#?)--*$"| | |"$" \ \"
*#1\ /-~$"| | |"$" \ /"$"  v"
*-{-}*[<]
\#0----/

Try it online!

\$\endgroup\$
1
\$\begingroup\$

Jelly, 32 bytes

Boring port of Lynn's Python solution.

“\¶| | |¶ \ ”ẋṭ“  ^¶ / ”;“/¶  v”

Try it online!

Explanation:

“\¶| | |¶ \ ”ẋṭ“  ^¶ / ”;“/¶  v”    Example input: 5
“\¶| | |¶ \ ”                       Literal string "\¶| | |¶ \ " (¶ = newline). Result: "\¶| | |¶ \ "
             ẋ                      Repeat as many times as the (implicit) input. Result: "\¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ "
              ṭ                     Tack that on the end of...
               “  ^¶ / ”            ...the string "  ^¶ / ". Result: "  ^¶ / \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ "
                        ;           Append...
                         “/¶  v”    The string "/¶  v". Result: "  ^¶ / \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ \¶| | |¶ \ /¶  v"
                                    Implicit print
\$\endgroup\$
1
\$\begingroup\$

Actually, 30 bytes

This works on the same principle as ETHproductions's Japt answer, where extra spaces are added later, and the whole string is split into rows of 5 for implicit printing. Try it online!

"\|||\"*" ^ /"+"/ v"@+#' j5@╪i

Ungolfing

            Implicit input.
"\|||\"*    Add the middle portion and multiply that by the input.
" ^ /"+     Append the top.
"/ v"@+     Append the bottom.
#           Convert into a list of strings
' j         Join with spaces.
5@╪         Split into a list of length-5 strings.
i           Flatten list onto the stack for implicit printing with newlines.
\$\endgroup\$
  • \$\begingroup\$ Nice job outgolfing Mego in his own language! \$\endgroup\$ – caird coinheringaahing Oct 4 '17 at 13:46
1
\$\begingroup\$

Jelly, 25 23 bytes

This works on the same principle as ETHproductions's Japt answer, where extra spaces are added later, and the whole string is split into strings of length 5 before printing. Try it online!

Edit: I knew there was a way to join the top and bottom of the S-chain in a golfier way. Thanks to Erik the Outgolfer for -2 bytes.

“\|||\”ẋ“ ^ /“/ v”jKs5Y

Ungolfing

                Left argument: n
“\|||\”ẋ        Repeat the middle portion n times.
“ ^ /“/ v”j     Append the top and bottom.
K               Join with spaces.
s5              Split into a list of length-5 strings.
Y               Print the strings with linefeeds.
\$\endgroup\$
  • \$\begingroup\$ “\|||\”ẋ“ ^ /“/ v”jKs5Y \$\endgroup\$ – Erik the Outgolfer Oct 4 '17 at 14:29
1
\$\begingroup\$

Charcoal, 25 bytes

↘^\¶/¶G→⁵↓⊕⊗N←⁵|¶ \↗¶\¶v/

Try it online! Link is to verbose version of code.

\$\endgroup\$
  • \$\begingroup\$ Funny how the other Charcoal answer is the same byte-count by using an completely different approach. I like yours more, though. The other is close to hard-coded, but yours is actually using Charcoal's strength. \$\endgroup\$ – Kevin Cruijssen Oct 27 '17 at 12:13
  • \$\begingroup\$ @KevinCruijssen You say strength, but that should really be printing diagonally; sadly the best I could do there was 29 bytes: ↘^\|¶/|\|¶|F⊖N↘\|\|¶|↘\|/¶|\v \$\endgroup\$ – Neil Oct 27 '17 at 13:48
1
\$\begingroup\$

bash, 67 bytes

printf -v a %\*s $1 \ ;echo '  ^
 / '"${a// /\\
| | |
 \\ }"'/
  v'

Try it online

\$\endgroup\$
0
\$\begingroup\$

Java 8, 93 76 bytes

n->{String r="  ^\n / ";for(;n-->0;r+="\\\n| | |\n \\ ");return r+"/\n  v";}

Port of @IanH.'s C# .NET answer after I golfed it a bit more.

Try it here.

\$\endgroup\$
  • \$\begingroup\$ It's funny how this is almost exactly identical expect for the string vs var part. \$\endgroup\$ – Ian H. Sep 21 '17 at 8:34
  • \$\begingroup\$ @IanH. And the n-> vs n=> ;) \$\endgroup\$ – Kevin Cruijssen Sep 21 '17 at 9:11

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.