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This is the robbers' post. The cops' is here.

Your challenge is to take a cop's post and find an input that the regex matches but the program returns a falsey value.

Once you have cracked a cop's post, comment in a link to your crack. (If you don't have enough rep to comment, please say so, and someone will do it for you.) The robber with the most cracks wins.

Example

Let's say a cop's regex is (all of the flavors):

/^[0-9]$/

And the program is (JS):

x=>Boolean(parseInt(x))

Than a valid crack would be 0, because the regex matches 0 but 0 is falsey.

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4 Answers 4

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2
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Python 3, pperry

İ

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The lower case variant i̇ of this character is created by a an i and a ċȯṁḃi̇̇ṅi̇̇ṅġ ḋȯṫ which results in a length of 2.

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  • \$\begingroup\$ That was the intended solution! \$\endgroup\$
    – The Fifth Marshal
    Aug 29, 2017 at 13:08
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Python, ppperry

\n

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. doesn't match newline by default.

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JavaScript, ThePirateBay

Solution: 😩

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0
0
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Java, Roman Gräf

is.is.is.is.

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Most things which match the regex crack it, so I'm not sure if the regex is what was intended

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  • \$\begingroup\$ I think the cop misunderstood the challenge, and that you misunderstood the regex : you're right that getting a false from the program while having the regex match is trivial, even more so than you think since (?is) is java's shorthand flag notation and turns on case-insensitivity and single-line mode for the rest of the regex, rather than the positive lookahead which it looks like you understood it as. (little illustration) \$\endgroup\$
    – Aaron
    Aug 29, 2017 at 16:34
  • \$\begingroup\$ @Aaron I've used those flags before so I really should have noticed that. If you would like to post an answer assuming the cop had true and false switches I encourage it since you spotted the intended answer \$\endgroup\$
    – PunPun1000
    Aug 29, 2017 at 16:38

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