Detect rotated strings

Question

Read two strings from stdin.
Output Yes if one string is a rotated version of the other.
Otherwise output No

Testcases

Input

CodeGolf GolfCode

Output

Yes

Input

stackexchange changestackex

Output

Yes

Input

stackexchange changestack

Output

No

Input

Hello World

Output

No

Answer 1

Python 2, 86 Characters

a,b=raw_input().split()
print"Yes"if any(a==b[n:]+b[:n]for n in range(len(a)))else"No"

Answer 2

Perl (just a quick fix)

A fix to rubber boots' solution, being a new user that I am I can't comment yet so I'll just post a new answer.

As the mentioned method uses a regular expression constructed from user input, it is possible to perform a small regex injection, as follows:

> perl -le '$.=pop;$_=(pop)x2;print+(qw/yes no/)[!/$./]' anything '.*'
yes

The fix is to use \Q (known also as quotemeta):

> perl -le '$.=pop;$_=(pop)x2;print+(qw/yes no/)[!/\Q$./]' anything '.*'
no

The code itself could be further shortened using 'say' but this is left as an exercise to the reader :)

Answer 3

Clojure, 95

The function rotated? simply tests one string against all possible rotations of the other. Brute force.

(defn rotated?
  [a b]
  (let[l (count a)
       b (seq b)]
    (->> a cycle (partition l 1) (take l) (some #{b}))))

I personally don't care where the input strings come from, but if it has to be stdin...

(apply rotated? (.split (read-line) " "))

This would add 38 to character count, if strings were whitespace separated.

(rotated? (read-line) (read-line))

This would add 32 to character count, if strings were newline separated. The function rotated? works with any characters in the strings.

Answer 4

Fixed to say Yes/No and improved (91 chars)

import List;f[a,b]|a`elem`[x++y|x<-tails b|y<-inits b]="Yes";f _="No";main=interact$f.words

original Haskell (92 chars) that says True/False

import Data.List;f(a:b:_)=any(a==)$zipWith(++)(tails b)(inits b);main=interact(show.f.words)

Answer 5

Bash, 70 65 59 55 characters

new approach:

read a b;c=$a$a;[[ ${c/$b/} == $a ]]&&echo yes||echo no

Answer 6

JavaScript - 66

p=prompt,a=p(),b=p();alert(!b.match(a)&&!!b+b.match(a)?'Yes':'No')

Answer 7

05AB1E, 20 bytes

Code:

DgFÀD²Qi"Yes",q}}"No

Uses CP-1252 encoding. Try it online!

Answer 8

Jelly, 16 bytes

ɠJṙ@€ɠe@ị“Yes“No

Try it online!

Many thanks to @cairdcoinheringaahing and @MrXcoder for helping me out in chat.

Explanation:

ɠ                   # The first string
  ṙ@€               # Rotated by...
 J                  #   The indexes of each element in the string
     ɠ              # The second string
      e@            # Exists in that list of strings.
                    # (either '0' or '1')
        ị           # Indexed into the list...
         “Yes“No    # ["yes", "no"]

Answer 9

jq -Rn, 62 + 4 = 65 bytes

len('if[inputs|explode|sort|implode]|.[0]==.[1]then"Yes"else"No"end')

As in the accepted answer, the two strings should be on separate lines. -R is used to avoid having to quote the input strings, and -n is used to disable the default input processing because inputs takes care of that.

Answer 10

Stax, 11 bytes

Ä:∩ö┌┘/YJTI

Run and debug it

This program takes input on two lines.

Unpacked, ungolfed, and commented, it looks like this.

:(      get all rotations
s|#     other input is a member of rotations?
`n!`    "Yes"
.No     "No"
?       (a ? b : c)

Run this one

Answer 11

C (gcc), 118 113 111 bytes

-5 bytes thanks to ceilingcat

i,l,r;f(s,t)char*s,*t;{for(l=r=0,i=strlen(s);i--;)r=strncmp(s+i,t,++l)|strncmp(s,t+l,i)?r:3;puts(r+"No\0Yes");}

Try it online!

Answer 12

PHP, 57 bytes

Input via space-delimited string on STDIN, output to STDOUT is "Yes" or "No" string.

<?=strpos(($a=explode(' ',$argn))[1].$a[1],$a[0])?Yes:No;

Try it online!

Or with Default I/O input via command line args and output truthy/falsey.

PHP, 37 bytes

<?=strpos(($a=$argv)[2].$a[2],$a[1]);

Try it online!

Or as a function:

PHP, 41 bytes

function($a,$b){return strpos($b.$b,$a);}

Try it online!

Answer 13

K3 / Kona, 28

{:[y _in![;x]'!#x;`Yes;`No]}

Answer 14

Pyth, 18 bytes

?}zm.<QdlQ"YES""NO

Try it online

Explanation

?}zm.<QdlQ"YES""NO
   m   dlQ            For each number in [1, ..., len(first input)]...
    .<Q               ... rotate the first input that many characters.
 }z                   Check if the second input is in that list.
?         "YES""NO    Return "YES" or "NO" appropriately.

Answer 15

Brachylog, 17 bytes

~c₂ᵐ↔ᵈ∧"Yes"|∧"No

Try it online!

(If the input strictly has to be whitespace-separated, add two bytes to prepend ṇ₁, but note that the input still has to be quoted. Brachylog does not have any sort of direct access to stdin.)

Takes input as a list of two strings, and outputs through the output variable. The actual logic is all in the first six bytes, which succeed if the elements of the input are rotations of each other, and fail if they are not:

   ᵐ      Both strings in the input
~c₂       can be split into two pieces each
    ↔ᵈ    such that one string's two chunks are the other's swapped.

(↔ᵈ could just as well be pᵈ, pᵛ, or oᵛ which is what it was originally before I decided that ↔ᵈ is more to the point.)

Although it would be possible to brute force rotating one of them until it matches, the number of rotations would need to be explicitly bounded, and on top of that just the effort required to separate out the two elements of the input list would be fairly costly. Since it's very easy to brute force partitions in Brachylog, the fact that a rotation is just as much taking one chunk off one end and moving it to the other as it is doing that to single characters however many times saves a lot of bytes.

With very flexible I/O, this could be as short as 5 bytes, taking one string through the input variable and the other through the output variable: ~c₂↔c

Answer 16

05AB1E, 13 bytes

ā._Êßi„Noë”…Ü

Try it online or verify all test cases.

Explanation:

ā         # Push a list in the range [0, length] for the (implicit) input-string,
          # without popping this input-string itself
          #  i.e. "CodeGolf" → [1,2,3,4,5,6,7,8]
 ._       # Rotate the string that many times towards the left (vectorized)
          #  "CodeGolf" and [1,2,3,4,5,6,7,8] → ["olfCodeG","lfCodeGo","fCodeGol","CodeGolf",
          #                                      "odeGolfC","deGolfCo","eGolfCod","GolfCode"]
   Ê      # Check for each whether it's NOT equal to the second (implicit) input-string
          #  "GolfCode" → [1,1,1,0,1,1,1,1]
    ß     # Pop and push the minimum (to check if any are falsey)
          #  [1,1,1,0,1,1,1,1] → 0 (falsey)
     i    # If this minimum is truthy (so all rotations were unequal to the second input):
      „No #  Push string "No"
     ë    # Else:
      ”…Ü #  Push dictionary string "Yes"
          # (after which the result is output implicitly)

See this 05AB1E tip of mine (section How to use the dictionary?) to understand why ”…Ü is "Yes".