Reverse Array Sum

Your program should take an array as input.

The array:

1. Will always be 1 dimensional
2. Will only contain integers
3. Can be empty

The program should reverse the array, and then add up the elements to the original for example:

Input: [1, 2, 3]

Original: [1, 2, 3]

Reversed: [3, 2, 1]

[1, 2, 3]
+  +  +
[3, 2, 1]

[1+3, 2+2, 3+1]


Output: [4, 4, 4]

Test Cases:

#In             #Out
[8, 92],        [100, 100]
[1, 2, 3],      [4, 4, 4]
[5, 24, 85, 6], [11, 109, 109, 11]
[],             []
[999],          [1998]


This is , the shortest code (in bytes) wins!

• J 3 bytes. Program is t. t=:+|. Feb 10, 2019 at 19:13

5 bytes save by changing to a point free as suggested by nimi

zipWith(+)=<<reverse


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• go pointfree: zipWith(+)=<<reverse.
– nimi
Jul 24, 2017 at 18:19
• @nimi Wow I didn't think to do that but thats pretty smart. Jul 24, 2017 at 18:21
• Where do I put the array? I tried arguments, and input on TIO Jul 24, 2017 at 18:23
• @NoahCristino I fixed the TIO. This is a point-free function so you just put the input after the function however Haskell requires a main to compile. Jul 24, 2017 at 18:26
• @maple_shaft: we use =<< from the function monad which is defined as: (=<<) f g x = f (g x) x. Here, written in infix: (zipWith(+) =<< reverse) x -> zipWith(+) (reverse x) x.
– nimi
Jul 24, 2017 at 19:23

Jelly, 2 bytes

+U


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or

+Ṛ


Try it online! (thanks @Mr. Xcoder for the second program)

explanation, though it's pretty self-explanatory

+U  Main link
U                    the input, reversed


+Ṛ  Main link
Ṛ                    the input, reversed, without vectorizing (same thing for depth-1 lists)


For empty array [], this outputs nothing. That is correct. Jelly's representation of an empty list is just simply nothing. Note that Jelly's representation of a list with a single element is just the element itself. Append ŒṘ to the code to see the Python internal representation of the output.

• I found 2 issues. 1) When tested on [9] it outputs 18 instead of [18], and 2) when tested on [] it doesn't output anything. Jul 24, 2017 at 18:19
• @NoahCristino It's not a full program, and there's already an explanation for that in the answer. Jul 24, 2017 at 18:19
• So I guess this is fine, it's just how Jelly outputs it Jul 24, 2017 at 18:23
• @NoahCristino Yeah. I added a part to the end of my answer so you can put that atom at the end of the code to see how Python would print it. Jul 24, 2017 at 18:24
• +Ṛ works too. Jul 24, 2017 at 18:46

JavaScript (ES6), 27 bytes

a=>[...a].map(e=>e+a.pop())


f=
a=>[...a].map(e=>e+a.pop())

console.log(f([8, 92])) // [100, 100]
console.log(f([1, 2, 3])) // [4, 4, 4]
console.log(f([5, 24, 85, 6])) // [11, 109, 109, 11]
console.log(f([])) // []
console.log(f([999])) //[1998]

• Oh, man, I was almost there, but I didn't think to use the spread operator to do the clone. Jul 24, 2017 at 19:09
• Can you add the embedded try it for javascript? Jul 24, 2017 at 23:25

05AB1E, 2 bytes

Â+


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• Passed all my tests! Jul 24, 2017 at 18:21
• R+ also works for 2 bytes. Jul 24, 2017 at 18:41

Python 2, 32 bytes

lambda l:map(sum,zip(l,l[::-1]))


Alternative solution without zip (35 bytes):

lambda l:map(int.__add__,l,l[::-1])


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Python 2, 40 bytes

lambda l:[i+j for i,j in zip(l,l[::-1])]


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The other, shorter Python answer replaces a list comprehension with map. Wish I'd thought to do that faster. ;-;

• Passes all my tests! Jul 24, 2017 at 18:20

Japt, 7 bytes

mÈ+Ug~Y


Try it online! with the -Q flag to format the output array.

Explanation

Implicit: U = input array

mÈ


Map the input by the following function...

+Ug


The value, plus the value in the input array at index...

~Y


-(index+1), which gets elements from the end of the array.

• Good job! I like the multiple input thing! Jul 24, 2017 at 18:45
• I really like the multiple-input Japt interpreter. Nice job! Jul 24, 2017 at 19:33
• That's really cool :-) I'd add that feature to the "official" interpreter, but with the current design it's sorta unextendable... Jul 24, 2017 at 21:08

Ruby, 25 bytes

->a{[*a].map{|i|i+a.pop}}


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Mathematica, 12 bytes

Reverse@#+#&


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Python 2, 33 32 bytes

-1 byte thanks to @xnor

lambda l:[i+l.pop()for i in l*1]


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• Passed all my tests good job :) Jul 24, 2017 at 20:26
• What an unusual method. l*1 saves a byte.
– xnor
Jul 24, 2017 at 20:53
• I am having difficulties understanding the par l*1, any elaboration Jul 26, 2017 at 8:23
• @dhssa l*1 makes a copy of the list l. If we would not make a copy, pop() would delete elements from the list before they were accessed in the for loop.
– ovs
Jul 26, 2017 at 8:30
• Thanks for the explanation, I got it now. good trick to know for coding. Jul 26, 2017 at 23:33

Brachylog, 6 bytes

↔;?z+ᵐ


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• Passes all cases, cool name. Jul 24, 2017 at 18:37

J, 3 bytes

+|.


Reverse, sum.

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C# (.NET Core), 61 60 bytes

-1 byte thanks to TheLethalCoder

a=>a.Reverse().Zip(a,(x,y)=>x+y).ToArray()


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Byte count also includes:

using System.Linq;


For explanation - Zip function in LINQ takes two collections and executes given function for all corresponding elements, ie. both first elements together, both second elements etc.

• Good answer. Thanks for the comment about the input. Jul 24, 2017 at 23:23
• Hello and welcome to PPCG! You don't need the trailing semi colon in the byte count. I believe you can return the collection straight from the Zip call to so no need for the ToArray(). Nice job! Jul 25, 2017 at 8:29
• @TheLethalCoder Thanks, and I added ToArray() since the challenge is about arrays, so I wanted the self-contained lambda to be array -> array. Jul 25, 2017 at 11:47

Vyxal, 2 bytes

Ḃ+


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Ḃ+
Ḃ  # bifurcate, i.e. duplicate and reverse
+ # vectorized addition of two lists


CJam, 7 bytes

{_W%.+}


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• It outputs "" for [], that's weird. Not your fault just the language. Jul 24, 2017 at 18:28
• @NoahCristino That's CJam's representation of []. Jul 24, 2017 at 18:29
• Yup, it's hard to have a standard output for my challenge since many languages display arrays differently especially [], and [4], so it's fine. Jul 24, 2017 at 18:30

APL (Dyalog), 3 bytes

⌽+⊢


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Explanation

⌽          The argument reversed
+           Plus
⊢          The argument

• ninja'd. I need to move to an APL keyboard... xD Jul 24, 2017 at 18:33
• @Uriel I am always on my APL keyboard :D Jul 24, 2017 at 18:35
• Love the simplicity. It outputs ⌽+⊢ with no input Jul 24, 2017 at 18:39
• @NoahCristino An empty input is specified with ⍬, the empty vector. With no argument, it prints the train by itself Jul 24, 2017 at 18:39

R, 17 16 bytes

-1 byte thanks to djhurio

rev(l<-scan())+l


Reads from stdin; returns the vector; numeric(0) is the zero-length numeric vector for the empty list.

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• For an empty "array" it returns numeric(0) Jul 24, 2017 at 18:36
• @NoahCristino an empty vector is represented as numeric(0) in R. Jul 24, 2017 at 18:58
• That's fine. @LeakyNun Jul 24, 2017 at 19:01
• rev(l<-scan())+l, 16 bytes? Jul 25, 2017 at 13:08
• For the record, an R+pryr functional alternative is just one byte longer: pryr::f(rev(x)+x) May 3, 2018 at 18:21

Clojure, 20 17 bytes

3 bytes saved thanks to @MattPutnam

#(map +(rseq %)%)


Seems to be quite competitive with non-golfing languages.

See it online

• Use rseq instead of reverse. Jul 26, 2017 at 19:07

Pyth, 3 bytes

+V_


Try it here.

• Yay passes all my tests! Jul 24, 2017 at 18:20
• Equivalent: sV_ Jul 24, 2017 at 18:25
• @Mr.Xcoder nevermind Jul 24, 2017 at 18:28

($a=$args)|%{+$a[--$i]+$_}  Try it online! Takes input as command-line arguments. • Can you add a TIO? and a link under the name like this one: codegolf.stackexchange.com/a/135427/61877 Jul 24, 2017 at 18:48 • @NoahCristino: Like this? Haven't used that thing so far, so no idea what I may have done wrong. By the way, if you expect people to use a certain service in their answers, then please state so in the task description. – Joey Jul 24, 2017 at 18:52 • That's fine. It's not required it just makes the answers more high quality, and easier to test out for future viewers. Jul 24, 2017 at 18:54 C, 49 bytes f(a,n,b)int*a,*b;{for(b=a+n;a<b--;a++)*a=*b+=*a;}  • Shouldn't a,n,b be a,b,n or something? Jul 24, 2017 at 20:12 • @EriktheOutgolfer No, b isn't a parameter for the function, just an extra definition stuffed in there for golfing reasons. a must be a pointer to integers, and n must be how many integers there are in the array. – orlp Jul 24, 2017 at 20:13 • Could you please add a TIO link? Jul 24, 2017 at 20:27 PowerShell, 40 32 bytes ($n=$args)|%{$n[-++$i]+$n[$i-1]}  Try it online! Takes input as individual command-line arguments, which is allowed as one of the native list format for PowerShell. Then loops through each element (i.e., a shorter way of looping through the indices), adding the element counting from the back (-1 indexed) to the current element (0 indexed, hence the decrement -1). Those are left on the pipeline and output is implicit. Saved 8 bytes thanks to @briantist • it doesn't output an array. Jul 24, 2017 at 18:27 • @NoahCristino PowerShell input/output is, in general, weird. It is outputting as an array, it's just there's nothing capturing said array, and so when the implicit Write-Output happens, it puts things on stdout one item per line. For example, you can see here that, when captured, the object is indeed an array type. Jul 24, 2017 at 18:31 • Good enough then :) atleast it tried Jul 24, 2017 at 18:38 • I'm on mobile and can't test so easily, but isn't it 1 byte shorter to remove the param and then replace 1..$n with 1..($n=$args)? Jul 24, 2017 at 21:51
• @briantist Not quite, but you did give me a different way of thinking about it, saving a bunch of bytes. Thanks! Jul 25, 2017 at 12:54

Java 8, 615756 53 bytes

a->{for(int l=0,r=a.length;l<r;a[l]=a[--r]+=a[l++]);}


-1 byte and bug-fixed thanks to @Nevay.
-3 bytes thanks to @OliverGrégoire.

(It was a port of (and golfed by 4 8 bytes) of @jkelm's C# answer, but now it's a different shorter solution thanks to @OliverGrégoire.)

Explanation:

Try it here.

The method modifies the input-array to save bytes, so no need for a return-type.

a->{                    // Method with integer-array parameter and no return-type
for(int l=0,          //  Left-integer (starting at 0)
r=a.length;   //  Right-integer (starting at the length of the input-array)
l<r;              //  Loop as long as left is smaller than right
a[l]=               //   Change the number at the current left index to:
a[--r]+=a[l++] //    The number at the right index + itself
//    (The += adds the number at the left index also to the right index)
//    (And the --/++ increases/decreases the indexes by 1,
//     until we've reached the middle of the array)
);                    //  End of loop
}                       // End of method

• You can save 1 byte by using a->{for(int i=0,l=a.length;i<l/2;a[i]=a[l+~i]+=a[i++]);}. Aug 16, 2017 at 10:56
• Besides that the code fails for arrays with an odd length 1,2,3 (returns 4,2,4 instead of 4,4,4), the loop has to run as long as 2*i<l, not i<l/2. Aug 16, 2017 at 11:03
• @Nevay Thanks. I knew it should be possible to golf l-i-1, just couldn't come up with it.. Aug 16, 2017 at 11:10
• 53 bytes: a->{for(int l=0,r=a.length;l<r;a[l]=a[--r]+=a[l++]);}. Aug 16, 2017 at 12:05
• @OlivierGrégoire Thanks. And your l and r makes sense for your implementation, so I've used those as well (and added an explanation). Aug 16, 2017 at 12:58

K4 / K (oK), 5 bytes

Solution:

x+|x:


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Example:

x+|x:,()
,()
x+|x:8 92
100 100
x+|x:,999
,1998


Explanation:

Not quite as elegant as the J solution, but same kinda thing:

x+|x: / the solution
x: / store input as x
|   / reverse it
x     / x

• Nice! I like the line by line explanation May 3, 2018 at 20:46

Factor, 18 bytes

[ dup reverse v+ ]


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Explanation

         ! { 1 2 3 }
dup      ! { 1 2 3 } { 1 2 3 }
reverse  ! { 1 2 3 } { 3 2 1 }
v+       ! { 4 4 4 }


tinylisp, 44 39 bytes

(load library
(q((p)(map* a p(reverse p


-5 bytes thanks to @DLosc

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Explanation

An anonymous function that maps the a function (addition) over pairwise elements in the input and the reverse of the input, forming a new list.

• map* is your friend here: Try it online! Feb 2 at 22:43
• @DLosc Thank you! Feb 2 at 22:47

Ohm, 3 bytes

DR+


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• It outputs floats, but I never said it couldn't, so that's fine, and for [] it doesn't output anything but that's just the language. Jul 24, 2017 at 18:26

Actually, 4 bytes

;R♀+


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• Perfect, great job. Jul 24, 2017 at 18:43
• Erik, solving my problem in like 7 languages xD Jul 24, 2017 at 18:43
• @NoahCristino Yeah I'm trying to keep it under 15...;) Jul 24, 2017 at 18:44
• I'm going to have to start adding a -1 for every submission xD Jul 24, 2017 at 18:46

anyfix, 3 bytes

"U+


The version on TryItOnline! is an outdated version of anyfix, which contains a few fatal errors such as not being able to add lists because of typos in the source code. Use the code on GitHub instead.

"U+  Program
"    Duplicate top of stack
U   Reverse top of stack if it is a list (which it should be...)


Neim, 2 bytes

This is a function that takes input on the top of the stack and outputs on the top of the stack.

𝕓𝔻


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• Is it allowed to modify the input stack via actual Neim code instead of normal input methods? Jul 25, 2017 at 11:59
• @LiefdeWen Yes, that's allowed in the defaults for I/O meta post.
– Okx
Jul 25, 2017 at 18:15