# I double the source, you double the output!

Your task, if you wish to accept it, is to write a program that outputs a positive integer (higher than 0). The tricky part is that if I duplicate your source code, the output must be double the original integer.

# Rules

• You must build a full program. That is, your output has to be printed to STDOUT.

• The initial source must be at least 1 byte long.

• Both the integers must be in base 10 (outputting them in any other base or with scientific notation is forbidden).

• Your program must not take input (or have an unused, empty input).

• Outputting the integers with trailing / leading spaces is allowed.

• You may not assume a newline between copies of your source.

• This is , so the shortest (original) code in each language wins!

• Default Loopholes apply.

### Example

Let's say your source code is ABC and its corresponding output is 4. If I write ABCABC instead and run it, the output must be 8.

This uses uses @manatwork's layout.

/* Configuration */

var QUESTION_ID = 132558; // Obtain this from the url
// It will be like https://XYZ.stackexchange.com/questions/QUESTION_ID/... on any question page
var COMMENT_FILTER = "!)Q2B_A2kjfAiU78X(md6BoYk";
var OVERRIDE_USER = 8349457; // This should be the user ID of the challenge author.

/* App */

return "https://api.stackexchange.com/2.2/questions/" +  QUESTION_ID + "/answers?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + ANSWER_FILTER;
}

}

jQuery.ajax({
method: "get",
dataType: "jsonp",
crossDomain: true,
success: function (data) {
data.items.forEach(function(a) {
});
comment_page = 1;
}
});
}

jQuery.ajax({
method: "get",
dataType: "jsonp",
crossDomain: true,
success: function (data) {
data.items.forEach(function(c) {
if (c.owner.user_id === OVERRIDE_USER)
});
else process();
}
});
}

var SCORE_REG = /<h\d>\s*([^\n,]*[^\s,]),.*?(-?\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/;

function getAuthorName(a) {
return a.owner.display_name;
}

function process() {
var valid = [];

var body = a.body;
if(OVERRIDE_REG.test(c.body))
body = '<h1>' + c.body.replace(OVERRIDE_REG, '') + '</h1>';
});

var match = body.match(SCORE_REG);
if (match)
valid.push({
user: getAuthorName(a),
size: +match[2],
language: match[1],
});

});

valid.sort(function (a, b) {
var aB = a.size,
bB = b.size;
return aB - bB
});

var languages = {};
var place = 1;
var lastSize = null;
var lastPlace = 1;
valid.forEach(function (a) {
if (a.size != lastSize)
lastPlace = place;
lastSize = a.size;
++place;

.replace("{{NAME}}", a.user)
.replace("{{LANGUAGE}}", a.language)
.replace("{{SIZE}}", a.size)

var lang = a.language;
if (! /<a/.test(lang)) lang = '<i>' + lang + '</i>';
lang = jQuery(lang).text().toLowerCase();

languages[lang] = languages[lang] || {lang: a.language, user: a.user, size: a.size, link: a.link, uniq: lang};
});

var langs = [];
for (var lang in languages)
if (languages.hasOwnProperty(lang))
langs.push(languages[lang]);

langs.sort(function (a, b) {
if (a.uniq > b.uniq) return 1;
if (a.uniq < b.uniq) return -1;
return 0;
});

for (var i = 0; i < langs.length; ++i)
{
var language = jQuery("#language-template").html();
var lang = langs[i];
language = language.replace("{{LANGUAGE}}", lang.lang)
.replace("{{NAME}}", lang.user)
.replace("{{SIZE}}", lang.size)
language = jQuery(language);
jQuery("#languages").append(language);
}

}
body { text-align: left !important}

width: 290px;
float: left;
}

#language-list {
width: 290px;
float: left;
}

font-weight: bold;
}

table td {
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr>

</tbody>
</table>
</div>
<div id="language-list">
<h2>Winners by Language</h2>
<table class="language-list">
<tr><td>Language</td><td>User</td><td>Score</td></tr>
<tbody id="languages">

</tbody>
</table>
</div>
<table style="display: none">
</tbody>
</table>
<table style="display: none">
<tbody id="language-template">
</tbody>
</table>

• @Mr.Xcoder Then I'll just have to include one in my own source. – steenbergh Jul 15 '17 at 17:55
• @Mr.Xcoder I think that you should have prevented reading your own source code. – caird coinheringaahing Jul 15 '17 at 18:09
• It only needs to work when doubled once? We don't need to support n many doublings? – Cody Gray Jul 16 '17 at 8:36
• @Daniel Let's say your source is  (empty program) and it produces 5. If you double it, your source is  (empty program) and that produces 5 as well, no matter what you do. That being said, an empty program duplicated is still the empty program, and always produces the same output, except for the case where the empty program means something else (a random number generator, for example), which could not be valid anyway. – Mr. Xcoder Jul 17 '17 at 9:11
• This shouldn't be hard for esolangs that automatically dump the top of stack upon program termination. – MD XF Jul 18 '17 at 22:26

# Fission, 13 bytes

O\aL;
+
$SV;  Returns 1 Try it online! Doubled: O\aL; +$
SV;O\aL;
+
$SV;  Returns 2 Try it online! Fun twist with this language, that doubling source will double atoms, and each atom is in general command pointer. So my idea was to build such code that second atom will be destroyed.  L Created atom, moving left (mass 1, energy 0) a stores in it ascii code of 'a' (97) \ mirrors V fission reactor, spliting atom into two with halved masses (48) ; destroy right atom S conditional mirror - mirrors right, if energy is zero (default energy level)$    increase energy by 1 (mass 48, energy 1)
+    increase mass by one (mass 49)


if one copy on source:

O    print ascii by mass of atom, destroy atom (prints 1)


if code was copied

S    conditional mirror - energy is 1 now, so goes throw
$increase energy by 1 (mass 49, energy 2) + increase mass by one (mass 50) O print ascii by mass of atom, destroy atom (prints 2)  Second atom is created with copied code \aL; on 4th row. Mirror \ sends it to the ; on the first row, where atom is destroyed ## Reflections, 10 bytes _~# _#_v  ### Explanation: • _~: read own source and push size • # _: convert to string • #_: print the first digit • v: reflects the IP down Then, the program does either end when hitting the other v or when leaving the grid. # QBasic, 12 bytes A script that takes no input and outputs to the console. Outputs 1 when single, outputs 2 when doubled. CLS n=n+1 ?n  # Small Basic, 45 bytes A script which takes no input and outputs to the TextWindow console. n=n+1 TextWindow.Clear() TextWindow.Write(n)  Try it at SmallBasic.com n=n+1 TextWindow.Clear() TextWindow.Write(n) n=n+1 TextWindow.Clear() TextWindow.Write(n)  Try it Doubled at SmallBasic.com SmallBasic.com depends on Silverlight, and thus the links must be opened in IE to function. # Python 2, 25 24 bytes x=1 print 4*'\b',x,;x=2#  Both values of x (1 and 2) get printed when the code is repeated. However the second time, the backspace character backspaces/"erases" the 1 and prints the 2 over the top of it. The behaviour of printing the backspace escape character \b seems quite system dependent (and it doesn't seem to work on many web REPLs...). Trailing comment idea inspired by W W's answer. Edit: byte saved, see comment. • Welcome to the site! – Ad Hoc Garf Hunter Jul 17 '18 at 17:52 • Why don't you put x=2 after the print and before the comment instead of multiplying by two before the print? – Ad Hoc Garf Hunter Jul 17 '18 at 17:54 • Thanks: I think that will save a byte or two... – Harry King Jul 17 '18 at 19:46 # Z80Golf, 6 bytes 00000000: 3676 f630 3ce5 6v.0<.  Try it online! ### Doubled 00000000: 3676 f630 3ce5 3676 f630 3ce5 6v.0<.6v.0<.  Try it online! ### Disassembly start: ld (hl),$76
or $30 inc a push hl  The trick is to exclude any call or rst instructions, so that the execution exactly follows the order: • The program (one or two copies) • The nop slide, then putchar at address $8000 (exactly once), and then
• halt which should be hit on return from putchar.

or $30; inc a sets up the ASCII '1' =$31 to print. push hl sets up the stack; ld (hl), $76 writes the halt instruction on the return address. When doubled, the second inc a changes the value to ASCII '2' =$32. The other instructions are effective no-ops; the return address and the halt instruction on return don't change.

1~@O+K~


Prints 1 on its own, 2 when doubled, 3 when tripled etc.

Try it online!

# Python 2, 27 bytes

+7
try:_
except:_=7;print _


Try it online!

Try it doubeled!

# Aheui, 23 bytes

분아떠망히
아뷴



outputs 4.

Doubled:

분아떠망히
아뷴
분아떠망히
아뷴



outputs 8.

Try it on jsaheui

print-s$0#  Try it online! # Doubled, 20 bytes print-s$0#print-s\$0#


Try it online!

Inspired by Sriotchilism O'Zaic recursive comment approach (Nice work by the way).

## W, 2 bytes

1+


## Explanation

1+   % Adds an (implicit) 0 (on empty input)
1+ % Add the constant 1 by 1
% Implicit output


# Unary(Inefficient conversion), 596 bytes

Not doubled: <<+.

Doubled: ++.>

Well, require left-exist tape, and output not ascii, but