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Write the shortest code you can that produces an infinite output.

That's all. You code will only be disqualified if it stops producing output at some point. As always in code golf, the shortest code wins.

Here's a list of answers that I think are really clever, so they can get credit:

Leaderboard

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body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
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  • 141
    \$\begingroup\$ All answers disqualified because at some point the Earth will be swallowed by the sun, and at some point the universe will die :P \$\endgroup\$
    – Doorknob
    Nov 9, 2013 at 20:00
  • 27
    \$\begingroup\$ Does "infinite until your computer crashes" count? <_< \$\endgroup\$
    – Izkata
    Nov 10, 2013 at 1:39
  • 7
    \$\begingroup\$ If I write mine in Piet, can I count the pixels of the text the other programs used? I believe the smallest possible repeating Piet program would be 6 pixels. That beats Befunge if "off" pixels still count. \$\endgroup\$
    – DampeS8N
    Nov 12, 2013 at 20:27
  • 12
    \$\begingroup\$ @Izkata So any answer that crashes your computer is also allowed :D \$\endgroup\$ Jul 11, 2014 at 20:11
  • 11
    \$\begingroup\$ @Doorknob So really, the challenge is to produce infinite output in a finite amount of time. Sounds easy enough. \$\endgroup\$
    – Sanchises
    Apr 10, 2015 at 21:15

333 Answers 333

1
8 9 10 11
12
0
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Phooey, 4 bytes

=[?]

Try it online!

Outputs a debug dump repeatedly.

>>> DEBUG <<<
Tape: [>1<]
Stack:
>>> DEBUG <<<
Tape: [>1<]
Stack:
>>> DEBUG <<<
Tape: [>1<]
Stack:
>>> DEBUG <<<
Tape: [>1<]
Stack:
...
=      tape = tape == stack
       since tape and stack are 0, sets it to 1
[      While tape is not 0
   ?     Dump debug info
]      End

Phooey (interpreter bug, eventual crash), 2 bytes

<?

Try it online!

Based on my "Raise a SIGSEGV" entry, where an interpreter bug is used to cause an infinite printing loop.

The bug is thoroughly explained in that post.

However, as one might expect, this does eventually (and quickly) segfault. If there was no memory protection, it would run infinitely.

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0
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Motorola MC14500B Machine Code, 1.5 bytes

1BC

Explanation

1   # store data in register R
 B  # output R
  C # JMP to the start of the program
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-1
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C# (72)

using System; class P {static void Main(){for(;;) Console.Write('-');}}

Output enter image description here

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2
  • 8
    \$\begingroup\$ This can easily be shortened to: class P{static void Main(){for(;;System.Console.Write(1));}} (60); if you insist on - to be outputted it would be 62 (replacing 1 with "1"). \$\endgroup\$
    – RobIII
    May 2, 2014 at 12:31
  • 3
    \$\begingroup\$ I have no idea how to code in C# but I can still golf this" class P{static void main{for(;;) Console.Write(0);}} \$\endgroup\$
    – MilkyWay90
    Feb 13, 2019 at 1:52
1
8 9 10 11
12

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