141
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Write the shortest code you can that produces an infinite output.

That's all. You code will only be disqualified if it stops producing output at some point. As always in code golf, the shortest code wins.

Here's a list of answers that I think are really clever, so they can get credit:

Leaderboard

var QUESTION_ID=13152,OVERRIDE_USER=8611;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

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16
  • 136
    \$\begingroup\$ All answers disqualified because at some point the Earth will be swallowed by the sun, and at some point the universe will die :P \$\endgroup\$
    – Doorknob
    Nov 9, 2013 at 20:00
  • 22
    \$\begingroup\$ Does "infinite until your computer crashes" count? <_< \$\endgroup\$
    – Izkata
    Nov 10, 2013 at 1:39
  • 5
    \$\begingroup\$ If I write mine in Piet, can I count the pixels of the text the other programs used? I believe the smallest possible repeating Piet program would be 6 pixels. That beats Befunge if "off" pixels still count. \$\endgroup\$
    – DampeS8N
    Nov 12, 2013 at 20:27
  • 9
    \$\begingroup\$ @Izkata So any answer that crashes your computer is also allowed :D \$\endgroup\$ Jul 11, 2014 at 20:11
  • 8
    \$\begingroup\$ @Doorknob So really, the challenge is to produce infinite output in a finite amount of time. Sounds easy enough. \$\endgroup\$
    – Sanchises
    Apr 10, 2015 at 21:15

320 Answers 320

0
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Java, 74 characters

Since Java 7 and later versions seeks for main function at first instead of static block; I think this would be the best option to print infinite loops with small code. For your reference: static block won't execute in Java 7.

class I{public static void main(String[]a){for(;;)System.out.println(1);}}
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3
  • 2
    \$\begingroup\$ For Java 7 and later, this is indeed what you'd need to do. Therefore, I recommend that you add #Java 7+, characterCountOfYourProgram to the beginning of your post, then golf the rest some more. Also, instead of using `s around your code, just add four spaces before the line. Here are some golfing tricks: change the class's name to 1 char, perhaps I. Change the String args[] to String[]a. Change the System.out.println to System.out.print. \$\endgroup\$
    – Justin
    Jun 21, 2014 at 19:21
  • \$\begingroup\$ Couldn't you also remove public, since methods are public by default? \$\endgroup\$
    – mbomb007
    Mar 5, 2015 at 1:56
  • \$\begingroup\$ @mbomb007 public is needed to make the code executable. \$\endgroup\$
    – dorukayhan
    May 28, 2016 at 15:50
0
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C++ 29

main(){while(1)std::cout<<1;}
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1
  • 3
    \$\begingroup\$ The shortest way to do an infinite loop in C/C++ is for(;;). If the condition is missing in a for loop, it becomes infinite. \$\endgroup\$
    – tbodt
    Jul 3, 2014 at 23:27
0
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SCALA 18

while(1>0)print(1)
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0
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AppleScript:

repeat until 1 < 0
    say "hi"
end repeat
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4
  • 1
    \$\begingroup\$ Because the question is a code-golf, could you please include the character count of your code? \$\endgroup\$
    – ProgramFOX
    Jul 11, 2014 at 18:29
  • \$\begingroup\$ I'm sorry, I'm new to this :) does that include , returns , spaces and tabs ? \$\endgroup\$
    – mcgrailm
    Jul 11, 2014 at 18:39
  • \$\begingroup\$ Yes, it does. If you have written this on Windows, then a word count application might count a newline as 2 characters (\r and \n), but here, newlines count just as one character. \$\endgroup\$
    – ProgramFOX
    Jul 20, 2014 at 8:29
  • 1
    \$\begingroup\$ You can shorten this a lot - instead of using end repeat, you can use end. You can shorten say "hi" to say"hi", or, using a different method of output entirely towards the Messages tab, you can use log"". You do not need the tab before this. You can remove the until 1 < 0 statement, as repeat is infinite by default. After all these suggestions, you shave off 26 bytes of code. \$\endgroup\$ Oct 29, 2015 at 11:14
0
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Groovy - 15 chars

for(;;)print 1
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0
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Clojure - 18 15 chars

(while 1(pr 1))
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1
  • 1
    \$\begingroup\$ (while 1(prn)) prints infinite newlines for 14 bytes. \$\endgroup\$
    – Bbrk24
    Mar 31 at 4:51
0
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CoffeeScript, 14

Pretty unoriginal and similar to JavaScript:

alert 6while 1
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1
  • \$\begingroup\$ There is a loop keyword, this could be shortened down to loop alert 1 \$\endgroup\$
    – eosterberg
    Apr 11, 2015 at 16:03
0
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PHP: 22 chars

<?PHP while(true){print(0);} ?>

My first golf, hope I did it right :)
It will hang your browser if you do it on a PHP page, but from the command line it does the expected: prints something until you get bored and stop it.

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2
  • \$\begingroup\$ Because you this is php, you can just put while(true){print(0);} the <?php ... ?> isn't actually php anyway \$\endgroup\$
    – addison
    Sep 1, 2014 at 23:43
  • \$\begingroup\$ And the php portion of your answer, while(true){print(0);}, is actually 22 characters. \$\endgroup\$
    – addison
    Sep 1, 2014 at 23:45
0
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Chinese, 2 bytes

Prints ÿ continuously.

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4
  • \$\begingroup\$ Isn't that two bytes? \$\endgroup\$ Jan 29, 2014 at 15:54
  • \$\begingroup\$ @JanDvorak He didn't specify chars or bytes, and chars is default. \$\endgroup\$
    – Timtech
    Jan 29, 2014 at 16:08
  • 5
    \$\begingroup\$ @Timtech According to the code-golf tag: If you use Unicode, byte count should use UTF-8. \$\endgroup\$
    – Sylwester
    Jan 29, 2014 at 22:14
  • \$\begingroup\$ @Sylwester Okay \$\endgroup\$
    – Timtech
    Jan 29, 2014 at 23:07
0
\$\begingroup\$

I haven't seen Thue used here much, so here we go:

Thue (22 19 bytes)

a::=ab
b::=~1
::=
a
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0
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Cardinal, 3 characters

.%$

Explanation:

.    print active value
 %   start pointers here
  $  jump to x,y = active, inactive value


.%$

Pointers spread out in all cardinal directions from every %
All pointers carry two values, initialized to 0. The upper value is
called the active value, and it can be accessed directly. The lower
value is called inactive value. Inactive values can only be accessed
by flipping both values, switching the active to inactive, and the
inactive to active, or by using instructions like $ that grab the
inactive value directly to e.g. execute a jump.
The < and > below the values are the positional and directional
markers of the pointers. In programs, they instruct pointers to change
the movement direction.

0 0     At this step, the first active value (from the left pointer)
0 0     gets printed in the console, the right pointer is going to
<%>     jump to x,y=0,0

0      The jumped (former left) pointer prints out the next 0
0
>%$

 0
 0     ... travels on ...
.>$

  0
  0
.%>    ... reaches the jump instruction again, going to jump to 0,0 again

0
0
>%$    ... print out the next 0... and so on, to infinity.

http://esolangs.org/wiki/Cardinal

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0
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Bat, 2 chars

%0

The output is (starting from a blank line, I've added nbsp to make it visible bellow)

 
d:\Temp\Supertemp>"D:\Temp\Supertemp\inf.bat"

d:\Temp\Supertemp>"D:\Temp\Supertemp\inf.bat"

d:\Temp\Supertemp>"D:\Temp\Supertemp\inf.bat"

d:\Temp\Supertemp>"D:\Temp\Supertemp\inf.bat"

d:\Temp\Supertemp>"D:\Temp\Supertemp\inf.bat"

d:\Temp\Supertemp>"D:\Temp\Supertemp\inf.bat"
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2
  • \$\begingroup\$ This is dependent to where you have stored the file, but it will always output. This is an example output. \$\endgroup\$ Oct 6, 2016 at 19:02
  • \$\begingroup\$ @EriktheGolfer, yes. \$\endgroup\$
    – Qwertiy
    Oct 6, 2016 at 21:34
0
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><> Fish - 2 characters, I'm counting the shortest one.

Thijs beat me to it, but oh well. Here are a couple more ><> answers.

1n
-Infinite 1's, 2 bytes

   >"drlow ,olleH"l  
                  ?  
                  !  
   ^              <  
                  o  

-Infinite "Hello, world", 84 bytes.

Edit: Whoops. It's character count, not bytecount. I also fixed the first answer. Edit 2: Thanks mbomb007 for shaving off 1 character.

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3
  • \$\begingroup\$ Why not just use 1n? \$\endgroup\$
    – mbomb007
    Oct 15, 2015 at 15:46
  • \$\begingroup\$ @mbomb007 Whoops, forgot that I could do that. \$\endgroup\$ Oct 15, 2015 at 15:49
  • \$\begingroup\$ "n also works. \$\endgroup\$
    – mbomb007
    Oct 15, 2015 at 16:01
0
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GoLunar, 4 bytes

This is the equivalent of 5543 zeros in a row in Unary, which is equivalent to +[.] in BrainF***.

5543
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0
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BotEngine, 1x3=3

Noncompeting as BotEngine is much too recent a language. Anyway, here we go:

>CT

It starts with a right-moving bot on the >. When it reaches the C, it creates a left-moving bot (which starts on the C.) On the next step, the left-moving bot reaches the > and is turned around to move right and the right-moving bot reaches the T, destroying itself and printing TRUE. The step after that, the other bot gets to the C starting the process over again.

>CF also works but prints FALSE instead of TRUE. Using P in this case would print empty lines instead.

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0
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Javascript ES6, 28 bytes

setInterval`console.log()`

I didn't want to code an infinite for loop like everyone else...

Try it here using anything BUT Firefox.

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0
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Mouse-2002, 3 bytes

(0!)

prints 0 forever.


Alternatively, for a more interesting and (theoretically) infinite error with no loop, the Ackermann Function in 99 bytes in this language:

"M>"?a:"N>"?b:#Y,a.b.;$Y1%n:2%m:m.0=k:n.0=j:j.k.>[n.1+!|j.k.<[#Y,m.1-,1;!|#Y,m.1-,#Y,n.,n.1-;;!]]]@

Expanded:

"M>" ? a:
"N>" ? b:

1 a:
1 b:

#Y, a. b.;!

$Y 1% n: 2% m: ~ ack
  m. 0 = k: ~ store whether m == 0 in k
  n. 0 = j:
  j. k. > [ ~ if y>x
    n.1+ ~ print it
  | j. k. < [ ~ if x>y
    #Y, m. 1-, 1;
  | #Y, m. 1-, #Y, m.,n. 1-;;!
    ]
   ]
  ]
@
$

Errors recursively, forever, as long as the input was a positive nonzero integer. (result of a bug in the interpreter: the code is correct!)

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0
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𝔼𝕊𝕄𝕚𝕟, 4 chars / 7 bytes

↻ô1;

Try it here (Firefox only).

Translates to while(output(1)); in JS.

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4
  • \$\begingroup\$ output isn't a JS function... \$\endgroup\$
    – mbomb007
    Apr 26, 2018 at 14:07
  • \$\begingroup\$ There isn't really an equivalent to that function in JS, I guess I made it a placeholder name for the custom output function that ESMin uses. \$\endgroup\$ Apr 30, 2018 at 14:11
  • \$\begingroup\$ console.log would work \$\endgroup\$
    – mbomb007
    Apr 30, 2018 at 14:51
  • \$\begingroup\$ The function doesn't output by lines, but rather appends to output... Perhaps it's more like a process.stdout.write. \$\endgroup\$ Apr 30, 2018 at 20:08
0
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C, 25 bytes

main(){while(puts("1"));}
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0
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R, 15 bytes

Infinitely prints 1

while(T)cat(1)
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0
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Pyth, 4 bytes (Non-competing)

Pyth is a new programming lenguage, so this answer doesn't count.

.V"0

Explanation:
.V   - Forever loop
  "0 - Outputs zeros
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1
  • \$\begingroup\$ You should add a note to your title saying this is non-competing because the language is newer than the question. Also this can be golfed to #0 \$\endgroup\$
    – Blue
    Feb 20, 2016 at 12:56
0
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ForceLang, 23 bytes

label l
io.write goto l

Looks weird, but it works. The key here is that goto does not interrupt the evaluation of the current line, and returns nil.

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0
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Pylons, 5

wp,1}

While 1, print the (empty) stack.

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0
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Come Here, 21 bytes

COME FROM1 1TELL1NEXT

In the reference implementation, this prints infinitely many smiley characters. Don't ask me why.

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1
  • \$\begingroup\$ The smiley characters are printed because you are using Windows cmd. \$\endgroup\$ Oct 6, 2016 at 18:58
0
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Clojure, 14 bytes

(pr(cycle[1]))
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0
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Brainfuck, 26 bytes

++++[>++++<-]>[>++<-]>+[.]

Do 4*4*2+1 (33, !) and the final loop is a infinite loop that only print the current memory cell (!).

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1
  • \$\begingroup\$ You could as well do +[.] (SOH), but then it would be a dupe. \$\endgroup\$ Oct 8, 2016 at 18:12
0
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Haystack, 6 bytes (non-competing, the language came 2 years after the challenge)

>"a"o<

This will print a [infinity] times.

If the above code gives a syntax error because of the lack of | (that character is the needle. The ultimate goal of all Haystack programs is to find the needle in the haystack), one can simply append it to the end:

>"a"o<|
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0
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Golfscript - 7

{1a}:a~

I'm still learing golfscript, but unless I'm mistaken, this puts 1 on the stack, then starts over?

But apparently, the stack only prints when the program terminates, so perhaps this is better:

{1.p}do

(thanks Dennis)

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4
  • \$\begingroup\$ You need a space between 1 and a, otherwise it's a single variable. I suggest using a non-alnum as a variable name {1?}:?+. Also, this doesn't print anything. \$\endgroup\$ Mar 4, 2014 at 5:31
  • 1
    \$\begingroup\$ This won't work, it will just print a stack level too deep error. Also, the stack is printed when the program finishes, so you have to print explicitly. Example: {1.p}do (7 bytes) @JanDvorak: [A-Za-z]+[0-9]+ is a single token, but [0-9]+[A-Za-z]+ is not. \$\endgroup\$
    – Dennis
    Jun 21, 2014 at 18:46
  • \$\begingroup\$ I would downvote, but my vote is locked in. Help me out! \$\endgroup\$
    – tbodt
    Sep 3, 2014 at 21:54
  • \$\begingroup\$ Edited as per @Dennis \$\endgroup\$
    – McKay
    Sep 7, 2016 at 21:42
0
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PHP, 9 chars

for(;;)a;

Assumes error_reporting includes notices, and you can run it like this:

php -r "for(;;)a;"

The output is the following (repeated until the script is stopped):

PHP Stack trace:
PHP   1. {main}() Command line code:0
PHP Notice:  Use of undefined constant a - assumed 'a' in Command line code on line 1

Note: 11 characters if code is written in a file: <?for(;;)a;

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3
  • 3
    \$\begingroup\$ Php is not that bad :) <?for(;;a); 11 chars \$\endgroup\$
    – tacone
    Nov 30, 2013 at 22:01
  • 1
    \$\begingroup\$ This assumes not only that E_NOTICE is enabled, but also that display_errors is set to STDOUT - no one in their right mind does this. \$\endgroup\$
    – primo
    Feb 2, 2014 at 7:17
  • \$\begingroup\$ @primo I do lol \$\endgroup\$
    – Oliver Ni
    Aug 6, 2017 at 12:02
0
\$\begingroup\$

Kitanai, 24 bytes

#print"0"&2&1#print"1"&~

The "#" defines a flag, the first "print" displays 0, then the "&2" jumps to the second "#", it then prints "1", goes to the origin ("&~") which is just after "&2", then it jumps to the first "#" thanks to the "&1". And it does all that infinitely :)

\$\endgroup\$

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