12 hour time conversion

Question

Challenge

Convert and print out a time in a 12-hour format. HH:MM AM/PM

Examples

Input:

'Fri Jun 30 2017 21:14:20 GMT-0700 (PDT)'
'Fri Jun 30 2017 00:10:23 GMT-0700 (PDT)'
'Fri Jun 30 2017 12:10:23 GMT-0700 (PDT)'
'Sat Jun 31 2018 8:06:20 GMT-0700 (PDT)'
'Fri Jul 01 2017 01:14:20 GMT-0700 (PDT)'
'Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)'

Ouput:

9:14 PM
12:10 AM
12:10 PM
08:06 AM
1:14 AM
09:06 AM

Fine Points

A zero before a one digit number is okay, no zero is also allowed. The following examples are both allowed:
- 9:06 AM
- 09:06 AM
All tested years will be after 999 (each year will be exactly 4 digits)

Rules

This is code-golf so the shortest solution in bytes wins
Standard Loopholes Apply
You may use functions as well as programs

Suggested test cases: 00:10:23 --> 12:10 AM and 12:10:23 --> 12:10 PM. — Arnauld, Jul 3, 2017 at 1:23
there we go. Feel free to edit if you see anything else I should change. thanks for the suggestion! — zoecarver, Jul 3, 2017 at 1:25
May we assume that the time is given in the timezone the program is being run in? (e.g. 'Fri Jun 30 2017 21:14:20 GMT-0400 (EDT)' for me) — ETHproductions, Jul 3, 2017 at 1:37

darrylyeo · Accepted Answer · 2017-07-04 20:08:45Z

JavaScript (ES6), 69 bytes

d=>new Date(d).toLocaleString(0,{hour:n='numeric',minute:n,hour12:1})

f=
d=>new Date(d).toLocaleString(0,{hour:n='numeric',minute:n,hour12:1})
console.log(
  f('Fri Jun 30 2017 21:14:20 GMT-0700 (PDT)'),
  f('Fri Jun 30 2017 00:10:23 GMT-0700 (PDT)'),
  f('Fri Jun 30 2017 12:10:23 GMT-0700 (PDT)'),
  f('Sat Jun 31 2018 8:06:20 GMT-0700 (PDT)'),
  f('Fri Jul 01 2017 01:14:20 GMT-0700 (PDT)'),
  f('Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)'),
)

JavaScript (ES6), 58 55 bytes

Assumes you are in the United States.

d=>new Date(d).toLocaleTimeString().replace(/:.. /,' ')

f=
d=>new Date(d).toLocaleTimeString().replace(/:.. /,' ')
console.log(
  f('Fri Jun 30 2017 21:14:20 GMT-0700 (PDT)'),
  f('Fri Jun 30 2017 00:10:23 GMT-0700 (PDT)'),
  f('Fri Jun 30 2017 12:10:23 GMT-0700 (PDT)'),
  f('Sat Jun 31 2018 8:06:20 GMT-0700 (PDT)'),
  f('Fri Jul 01 2017 01:14:20 GMT-0700 (PDT)'),
  f('Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)')
)

JavaScript (ES6), 81 78 bytes

Answer before outputting a leading 0 in single-digit hours was made optional and test cases without leading 0s were added.

d=>([m,s]=d.slice(16).split`:`,`0${m%12||12}:${s} ${m<12?'A':'P'}M`.slice(-8))

f=
d=>([m,s]=d.slice(16).split`:`,`0${m%12||12}:${s} ${m<12?'A':'P'}M`.slice(-8))
console.log(
  f('Fri Jun 30 2017 21:14:20 GMT-0700 (PDT)'),
  f('Sat Jun 31 2018 08:06:20 GMT-0700 (PDT)'),
  f('Fri Jul 01 2017 01:14:20 GMT-0700 (PDT)'),
  f('Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)')
)

I was thinking about changing ${m>12?'P':'A'}M to ${"AP"[m>12]}M, but it doesn't work without casting the index to an integer (like with |0), which makes it the same length. Nicely golfed. — kamoroso94, Jul 3, 2017 at 4:01
Returns 12:10 AM for Fri Jun 30 2017 12:10:23 GMT-0700 (PDT). Should be PM. Changing m>12 to m>11 should fix it. — Rick Hitchcock, Jul 3, 2017 at 5:34
to save you 4 bytes: d=>(new Date(d).toLocaleString(0,{hour:'numeric',minute:'numeric',hour12:1})) — zoecarver, Jul 3, 2017 at 13:35
In fact, you could actually save 25 bytes with the following: d=>(new Date(d).toLocaleTimeString().replace(/:\d+/,'')) — zoecarver, Jul 3, 2017 at 13:52

totallyhuman · Accepted Answer · 2017-07-03 01:06:16Z

6

Python 2, 66 bytes

lambda s:`int(s[15:18])%12`+s[18:21]+'  APMM'[int(s[15:18])>11::2]

Try it online!

answered Jul 3, 2017 at 1:06

totallyhuman

16.3k3 gold badges31 silver badges86 bronze badges

\$\begingroup\$ This fails for years that have less than 4 digits (although I'm unsure whether it has to work with those). \$\endgroup\$
– notjagan
Jul 3, 2017 at 1:09
\$\begingroup\$ I think that is alright. \$\endgroup\$
– zoecarver
Jul 3, 2017 at 1:11
\$\begingroup\$ @notjagan it doesn't have to, it says so in the question. \$\endgroup\$
– Fedone
Jul 4, 2017 at 8:59
\$\begingroup\$ @totallyhuman Whoops, sorry. \$\endgroup\$
– Fedone
Jul 5, 2017 at 12:06
\$\begingroup\$ Can you change int(s[15:18])>11 to s[15:18]>"11"? \$\endgroup\$
– ETHproductions
Jul 12, 2017 at 21:50

| Show 1 more comment

Anders Kaseorg · Accepted Answer · 2017-07-03 01:08:45Z

5

sh + coreutils, 22 bytes

date +%I:%M\ %p -d"$1"

(If seconds are allowed, then date +%r -d"$1" suffices.)

edited Jul 3, 2017 at 1:08

answered Jul 3, 2017 at 1:02

Anders Kaseorg

39.3k3 gold badges72 silver badges145 bronze badges

\$\begingroup\$ impressively few bytes! also well done \$\endgroup\$
– zoecarver
Jul 3, 2017 at 1:10

Add a comment |

Arnauld · Accepted Answer · 2017-07-03 01:29:41Z

4

JavaScript (ES6), 77 bytes

Assumes that the year has 4 digits.

s=>`${([,,,h,m]=s.match(/\d./g),x=h%12||12)>9?x:'0'+x}:${m} ${'AP'[h/12|0]}M`

Test cases

let f =

s=>`${([,,,h,m]=s.match(/\d./g),x=h%12||12)>9?x:'0'+x}:${m} ${'AP'[h/12|0]}M`

console.log(f('Fri Jun 30 2017 21:14:20 GMT-0700 (PDT)')) // 09:14 PM
console.log(f('Fri Jun 30 2017 00:10:23 GMT-0700 (PDT)')) // 12:10 AM
console.log(f('Fri Jun 30 2017 12:10:23 GMT-0700 (PDT)')) // 12:10 PM
console.log(f('Sat Jun 31 2018 08:06:20 GMT-0700 (PDT)')) // 08:06 AM
console.log(f('Fri Jul 01 2017 01:14:20 GMT-0700 (PDT)')) // 01:14 AM
console.log(f('Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)')) // 09:06 AM

answered Jul 3, 2017 at 1:29

Arnauld

186k18 gold badges171 silver badges625 bronze badges

\$\begingroup\$ Like above, I have found a smaller way to create and answer. Feel free to use my code, I don't think that it is really fare to answer my own question. d=>(new Date(d).toLocaleTimeString().replace(/:\d+/,'')) \$\endgroup\$
– zoecarver
Jul 4, 2017 at 0:26
\$\begingroup\$ @pudility This would only work if your Locale is en-US and your timezone is GMT-0700 (PDT). For instance, none of these assumptions are true for me. \$\endgroup\$
– Arnauld
Jul 4, 2017 at 5:57

Add a comment |

ETHproductions · Accepted Answer · 2017-07-03 20:01:00Z

2

Japt, 15 bytes

ÐU¯24)s8 r.³+SS

Try it online!

12 bytes if we can assume that the time will be given in the computer's local time:

ÐU s8 r.³+SS

Try it online!

Mathy approach, 40 bytes

tG5 r"^.."_<C?+Z+B:°TnZ)%CÄÃ+" {"AP"gT}M

Test it online!

edited Jul 3, 2017 at 20:01

answered Jul 3, 2017 at 1:34

ETHproductions

49.9k6 gold badges93 silver badges239 bronze badges

Add a comment |

DJMcMayhem · Accepted Answer · 2017-07-03 02:17:59Z

1

V, 36 bytes

16x3wC AMÇ^0ü^1[0-2]/12WrP
ç^ä:/é0

Try it online!

Hexdump:

00000000: 3136 7833 7743 2041 4d1b c75e 30fc 5e31  16x3wC AM..^0.^1
00000010: 5b30 2d32 5d2f 3132 1857 7250 0ae7 5ee4  [0-2]/12.WrP..^.
00000020: 3a2f e930                                :/.0

answered Jul 3, 2017 at 2:17

DJMcMayhem

58.8k17 gold badges194 silver badges345 bronze badges

Add a comment |

jankes · Accepted Answer · 2017-07-03 09:58:46Z

1

PHP, 45 bytes

Answer improved thanks to manatwork

<?=(new DateTime($argv[1]))->format('h:i A');

First attempt:

<? $d=new DateTime($argv[1]);echo$d->format('h:i A');

Example usage through php CLI:

php d.php "Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)"

This is my first golf try.

edited Jul 3, 2017 at 9:58

answered Jul 3, 2017 at 9:39

jankes

1112 bronze badges

\$\begingroup\$ No need for variable $d and that way you can get rid of the explicit echo: <?=(new DateTime($argv[1]))->format('h:i A');. \$\endgroup\$
– manatwork
Jul 3, 2017 at 9:43

Add a comment |

Erik the Outgolfer · Accepted Answer · 2017-07-04 08:49:58Z

1

Jelly, 43 bytes

Ḳ5ịṣ”:Ṗṁ3µV’%12‘Dµ1¦µV>11ị⁾PAµ3¦“0: M”żFṫ-7

Try it online!

This is superfluously too long! That is, Jelly sucks at time manipulation.

EDIT: I'm even outgolfed by PHP!

edited Jul 4, 2017 at 8:49

answered Jul 3, 2017 at 11:38

Erik the Outgolfer

40.4k5 gold badges41 silver badges121 bronze badges

Add a comment |

Eric Lagergren · Accepted Answer · 2017-07-03 05:52:58Z

0

Go, 103 bytes

func f(s*string){t,_:=time.Parse("Mon Jan 02 2006 15:04:05 MST-0700 (MST)",*s)
*s=t.Format("03:04 PM")}

Test here: https://play.golang.org/p/P1zRWGske-

edited Jul 3, 2017 at 5:52

answered Jul 3, 2017 at 5:46

Eric Lagergren

4833 silver badges9 bronze badges

Add a comment |

Erik the Outgolfer · Accepted Answer · 2017-07-03 12:00:54Z

0

05AB1E, 39 bytes

#4è':¡¨`sD11›„APès<12%>0ìR2£R)Á… :M‚øJJ

Try it online!

answered Jul 3, 2017 at 12:00

Erik the Outgolfer

40.4k5 gold badges41 silver badges121 bronze badges

Add a comment |

kip · Accepted Answer · 2017-07-03 13:41:48Z

0

PHP, 42 bytes

<?=date_create($argv[1])->format('h:i A');

Try it online!

answered Jul 3, 2017 at 13:41

kip

1414 bronze badges

Add a comment |

TheLethalCoder · Accepted Answer · 2017-07-04 09:09:28Z

C#, 145 bytes

namespace System.Linq{s=>{var d=DateTime.Parse(string.Join(" ",s.Split(' ').Skip(1).Take(4)));return d.ToString("h:mm ")+(d.Hour>11?"PM":"AM");}}

Full/Formatted version:

namespace System.Linq
{
    class P
    {
        static void Main()
        {
            Func<string, string> f = s =>
            {
                var d = DateTime.Parse(string.Join(" ", s.Split(' ').Skip(1).Take(4)));

                return d.ToString("h:mm ") + (d.Hour > 11 ? "PM" : "AM");
            };

            Console.WriteLine(f("Fri Jun 30 2017 21:14:20 GMT-0700 (PDT)"));
            Console.WriteLine(f("Fri Jun 30 2017 00:10:23 GMT-0700 (PDT)"));
            Console.WriteLine(f("Fri Jun 30 2017 12:10:23 GMT-0700 (PDT)"));
            Console.WriteLine(f("Fri Jul 01 2017 01:14:20 GMT-0700 (PDT)"));
            Console.WriteLine(f("Sat Apr 10 2020 09:06:20 GMT-0700 (PDT)"));

            Console.ReadLine();
        }
    }
}

Community · Accepted Answer · 2020-06-17 09:04:33Z

0

,,,, 41 bytes

::18⊢3⊣⇆15⊢3⊣i11>"  APMM"⇆⊢2⟛↔15⊢3⊣i12%s#

Explanation

WIP

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Jul 4, 2017 at 18:07

totallyhuman

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Suever · Accepted Answer · 2022-09-04 02:11:00Z

0

MATL, 9 bytes

5:24)16XO

Try it at MATL online! Or verify all test cases.

Explanation

5:24    % Push array [5 6 ... 24]
)       % Implicit input. Get characters at those positions. This
        % removes the first four characters with the day of the week
16      % Push 16
XO      % Convert to date string format 16, which is 'HH:MM PM'
        % Implicitly display

edited Sep 4, 2022 at 2:11

Suever

11.1k1 gold badge22 silver badges52 bronze badges

answered Jul 3, 2017 at 8:55

Luis Mendo

104k9 gold badges132 silver badges364 bronze badges

\$\begingroup\$ Can we have an explanation? \$\endgroup\$
– totallyhuman
Jul 4, 2017 at 21:19
1

\$\begingroup\$ @totallyhuman Sure, thanks for reminding me. Edited. Basically the builtin XO does most of the work \$\endgroup\$
– Luis Mendo
Jul 4, 2017 at 21:28

Add a comment |

Stack Exchange Network

12 hour time conversion

Challenge

Examples

Fine Points

Rules

14 Answers 14

JavaScript (ES6), 69 bytes

JavaScript (ES6), 58 55 bytes

JavaScript (ES6), 81 78 bytes

Python 2, 66 bytes

sh + coreutils, 22 bytes

JavaScript (ES6), 77 bytes

Test cases

Japt, 15 bytes

Mathy approach, 40 bytes

V, 36 bytes

PHP, 45 bytes

Jelly, 43 bytes

Go, 103 bytes

05AB1E, 39 bytes

PHP, 42 bytes

C#, 145 bytes

,,,, 41 bytes

Explanation

MATL, 9 bytes

Explanation

Your Answer

Not the answer you're looking for? Browse other questions tagged
code-golf
or ask your own question.

Linked

Hot Network Questions

12 hour time conversion

Challenge

Examples

Fine Points

Rules

14 Answers 14

JavaScript (ES6), 69 bytes

JavaScript (ES6), 58 55 bytes

JavaScript (ES6), 81 78 bytes

Python 2, 66 bytes

sh + coreutils, 22 bytes

JavaScript (ES6), 77 bytes

Test cases

Japt, 15 bytes

Mathy approach, 40 bytes

V, 36 bytes

PHP, 45 bytes

Jelly, 43 bytes

Go, 103 bytes

05AB1E, 39 bytes

PHP, 42 bytes

C#, 145 bytes

,,,, 41 bytes

Explanation

MATL, 9 bytes

Explanation

Your Answer

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Post as a guest

Not the answer you're looking for? Browse other questions tagged code-golf or ask your own question.

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Hot Network Questions

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code-golf
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