Convert phones to calculation [closed]

Question

Introduction

OnePlus is a Chinese smartphone manufacturer founded in December 2013. Their latest phone, OnePlus 5, was unveiled on June 20, 2017.

I am sure you have seen that the name of the phone can easily be translated to a sum.

OnePlus can be written like 1+ thus OnePlus 2 = (1+ 2) = 3

Input

The name of one OnePlus phone. The above list in the only possible input

OnePlus 1
OnePlus 2
OnePlus X
OnePlus 3
OnePlus 3T
OnePlus 5

Output

The sum of the name (a number not a string)

OnePlus 1 => 2
OnePlus 2 => 3
OnePlus X => an integer
OnePlus 3 => 4
OnePlus 3T => 27 (T = Today = 23 thus 1+3+23=27)
OnePlus 5 => 6 

Rules

The input can be written in different versions. This applies to every names. For example

OnePlus 1
OnePlus1
One+ 1
One+1
1+ 1
1+1

• The output for OnePlus X is an integer that should be different from the other phones names. Whatever you want except 2,3,4,27,6
• The T in OnePlus 3T will always be 23 which is the day I am posting this.
• This is code-golf, so the shortest solution (in bytes) wins.

Answer 1

05AB1E, 10 bytes

0Uθ.VT26:>

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θ has been replaced by ®è on TIO since it hasn't been pulled there yet. Alternatively, ¤ would work too.

Explanation:

0Uθ.VT26:> "Accepts a single line from STDIN"\
0          "Push 0"\
 U         "Assign to X"\
  θ        "(implicit input)"\ "Take the last element"\
   .V      "Eval as 05AB1E code"\
     T     "Push 10"\
      26   "Push 26"\
        :  "Infinitely replace"\
         > "Increment"\

Answer 2

Retina, 26 16 bytes

-10 bytes thanks to @MartinEnder

O
1
T
995
.
$*
1

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Answer 3

Perl 5, 21 bytes

20 bytes of code + -p flag.

$_=/\d$/?$&+1:27*/T/

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If the input ends with an integer (/\d$/), then we add one to it ($&+1) and outputs it. Otherwise, we output 27*/T/ which is 27 if the inputs contains a T, and 0 otherwise.

Answer 4

C# (.NET Core), 138 bytes

using System.Linq;s=>s.Replace("One","1").Replace("Plus","+").Replace("T","+23").Replace("X","9").Split('+').Select(e=>int.Parse(e)).Sum()

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Answer 5

Java 8, 79 61 bytes

s->{int x=s.charAt(s.length()-1);return x<58?x-47:x<85?27:9;}

Explanation:

Try it here with all possible test cases.

s->{                             // Method with String parameter and integer return-type
  int x=s.charAt(s.length()-1);  //  Get the last characters of the input
  return x<58?                   //  If it's a digit:
          x-47                   //   Return that digit + 1
         :x<85?                  //  Else if it's a 'T':
          27                     //   Return 27
         :                       //  Else (it's a 'X')
          9;                     //   Return 9 (unique digit other than 2,3,4,6,27)
}                                // End of method

Answer 6

C (gcc), 65 63 48 bytes

f(char*s){s+=strlen(s)-1;s=*s?*s^84?*s-47:27:9;}

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Answer 7

Excel VBA, 87 51 bytes

Anonymous VBE immediate window function that takes input from cell [A1] and outputs OnePlus math to the VBE immediate window

i=Asc(Right([A1],1)):?IIf(i<58,i-47,IIf(i<85,27,9))

Old Version

Anonymous VBE immediate window function that takes input from cell [A1] that and outputs OnePlus math to the VBE immediate window

?Application.Evaluate("="&Replace(Replace(Replace([A1],"One",1),"Plus","+"),"T","+23"))

Input/Output

As a result of the Application.Evaluate call this solution is afforded access to all of the Excel WorkSheet Functions

[A1]="OnePlus 3T"
?Application.Evaluate("="&Replace(Replace(Replace([A1],"One",1),"Plus","+"),"T","+23"))
 23

[A1]="OnePlusPi()"
?Application.Evaluate("="&Replace(Replace(Replace([A1],"One",1),"Plus","+"),"T","+23"))
 4.14159265358979

[A1]="One+Day(Now())"
?Application.Evaluate("="&Replace(Replace(Replace([A1],"One",1),"Plus","+"),"T","+23"))
 26