When will SE be down?

Question

SE will be down/read only today 2017-05-04 at 00:00 UTC until 00:20 UTC.

Your challenge is to output a truthy value if SE is down/read only and a falsy value if SE is not. You may not have any input, and you must use date builtins to determine if SE is down/read only (no actually querying the SE api!) Example output:

12:34 UTC 03 May 2017 -> false

00:00 UTC 04 May 2017 -> true

00:20 UTC 20 May 2017 -> undefined, see below

That's undefined behavior, because it's too far after the window of time. To be clear, you can assume your program will be run from UTC 8:00 today (5/3/17) to UTC 1:00 tomorrow (5/4/17).

00:21 UTC 04 May 2017 -> false

00:20 UTC 04 May 2017 -> true

00:10 UTC 04 May 2017 -> true

Note that any truthy or falsy values are allowed, not just true and false. You must be accurate to the nearest second, and no changing the system clock! You may assume that your program is being run on a machine on the +0 UTC time zone.

Answer 1

JavaScript (ES6), 26 24 23 22 21 bytes

Saved 3 bytes thanks to Shaggy and 1 byte thanks to Luke.

_=>new Date/12e5%72<1

Checks if time passed in current day is less than 1200000ms (1200s or 20min). Assumes downtime to be 20 minutes not 21, which appears to be the case in the linked post. 00:20UTC is the exclusive upper bound.

Answer 2

05AB1E, 32 26 11 9 8 bytes

žažb«21‹

Explanation:

ža          Is the current hour &
  žb        current minute
     «      concatenated
        ‹   less than
      21    twenty one?

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Answer 3

Python 2, 41 39 bytes

Saved 2 bytes thanks to Erik the Outgolfer

import time
print time.time()/1200%72<1

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Uses the same algorithm as my JS and Charcoal answers.

Answer 4

Jelly, 9 bytes

6ŒT|0Ḍ<21

Requires TZ to be set to UTC, which is the case for TIO.

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How it works

6ŒT|0Ḍ<21  Main link. No arguments.

6ŒT        Get the current time as a string, in the format HH:MM.
   |0      Bitwise OR each character with 0. This casts the characters to int and
           maps the non-digit character : to 0.
     Ḍ     Undecimal; convert from base 10 to integer.
      <21  Compare the result with 21, so 00:00 to 00:20 return 1, all others
           return 0.

Answer 5

Japt, 32 11 bytes

K/12e5%72<1

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Answer 6

JS (ES6), 52 50 49 bytes

y=>(x=new Date).getUTCMinutes()<21&&!x.getUTCHours()

Why is Date so long? Just gets the minutes past 00:00 and returns true if they are < 21, and false otherwise.

Answer 7

zsh, 38 37 bytes:

date +%H\ %M|read h m;((h==0&&m<21))

Answer 8

bash, 40 bytes:

read h m< <(date +%H\ %M);((h==0&&m<21))

Answer 9

APL (Dyalog), 14 bytes

∧/1 20>2↑3↓⎕TS

∧/ is it all-true (AND reduction) that

1 20> these numbers are greater than

2↑ the first two elements of

3↓⎕TS the current Time Stamp with three elements dropped

Answer 10

Charcoal, 25 bytes

‹﹪÷ＵＰtime.time⟦⟧¹²⁰⁰¦⁷²¦¹

Prints - for truthy, nothing for falsy.

Explanation

    ＵＰtime.time⟦⟧          Python function time.time()
   ÷               ¹²⁰⁰      Divided by 1200
 ﹪                    ¦⁷²   Modulo 72
‹                         ¦¹ Less than 1

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Answer 11

Alice, 17 bytes

/o
\T@/4&;'-.C+n

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Assumes to be run on a machine whose timezone is set to UTC (like the TIO server).

Explanation

While in Ordinal mode, the IP bounces diagonally up and down through the program. While in Cardinal mode, the IP wraps around the edges like most other Fungeoids.

/   Reflect to SE. Switch to Ordinal.
T   Push a string representing the current date and time, in the format:
    YYYY-MM-DDTHH:MM:SS.mmm±AA:BB
/   Reflect to E. Switch to Cardinal.
4&  Run the next command 4 times.
;   Discard four elements from the top of the stack. Since we're in Cardinal mode,
    this attempts to discard four integers. But the top stack value is a string so
    it gets implicitly converted to all the integers contained in the string. So
    year, month, day, hour, minute, seconds, milliseconds, timezone hour,
    timezone minute will be pushed separately. Then the last four of these
    will be discarded, so that we end up with the minute and the hour on
    top of the stack.
'  Push 21.
-   Subtract it from the minutes. Gives something negative for minutes 0 to 20.
.C  Compute the binomial coefficient n-choose-n. This gives 0 for negative
    results and 1 for non-negative ones. SE is down if both this value and
    the current hour are zero.
+   Add the two values. Iff they are both zero, we still get a zero.
n   Logical NOT of the value. Turns 0 into 1 and everything else into 0.
\   Reflect to NE. Switch to Ordinal.
o   Implicitly convert the result to a string and print it.
@   Terminate the program.

Answer 12

MATL, 10 bytes

Thanks to Dennis for several corrections

Z'1\480*7<

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Explanation

Z'    % Push current date and time as a float. Integer part is day, decimal part is time
1\    % Modulo 1. This gives the time, in units of one day
480*  % Multiply by 480
7<    % Less than 7? Note that 21 minutes / one day equals 7 / 480. Implicitly display. 

Answer 13

Python 3 (NON-REPL) + time, 81 77 bytes

^{-4 bytes thanks to Bahrom}

import time;e=str(time.strftime('%H:%M'));print(e[:2]=='00'and int(e[3:])<21)

A naïve approach, turning the current date to string and analysing its characters.

Answer 14

Pyth, 11 bytes

&g20.d7!.d6

Online interpreter link

Answer 15

Bash, 55 53 51 50 bytes

-1 byte from @robbie0630's comment.

a=`date +%s`;echo $[1493856000<a&a<1493857200?1:0]

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The advantage of this solution is that it works for any date (so will return 1 only for the period defined in the challenge, as it uses epoch time).

Answer 16

Swift + Foundation, 178 bytes

import Foundation;var d=String(describing:Date());func g(_ s:Int)->String{return String(d[d.index(d.startIndex,offsetBy:s)])};print(g(11)+g(12)=="00" ?Int(g(14)+g(15))!<21:false)

Quite short by swift standards. Check it out!

As in my Python answer, I basically converted the current Date to a string and have analysed its digits, depending on which I printed the bool.

Answer 17

R, 65 bytes

library(lubridate)
x=Sys.time()
print(all(!hour(x)&minute(x)<21))

Checks if the hour == 0 and the minute < 21.

Answer 18

PostgreSQL, 43 characters

select now()between'170503'and'170503 0:20'

Just because I prefer SQL for date/time calculations.

Sample run:

bash-4.3$ psql -c "select now()between'170503'and'170503 0:20'"
 ?column? 
----------
 f
(1 row)