((15, 'less_than', 30) == true)

Use any language you are comfortable with. The only thing you must not do is mentally substitute the words for the symbols.

Here's a link to the gist if you want to fork and show your solution:


Bonus: Drink one beer first.

  • 1
    \$\begingroup\$ i don't see any unknown variables in that... equation... what exactly is to be solved? \$\endgroup\$ – mniip May 17 '13 at 15:53
  • 1
    \$\begingroup\$ Could you explain what this is supposed to be? A bit confused here. \$\endgroup\$ – Riking May 17 '13 at 16:08
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    \$\begingroup\$ I drank a beer and still cannot understand what there is to solve in ((15, 'less_than', 30) == true). I think I'll go have another. \$\endgroup\$ – DavidC May 17 '13 at 19:27
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    \$\begingroup\$ @DavidCarraher We should have a brainstorming gathering \$\endgroup\$ – Dr. belisarius May 18 '13 at 0:38
  • \$\begingroup\$ Sure. With few more people and a barrel of beer it will soon begin to make sense. \$\endgroup\$ – DavidC May 18 '13 at 1:23

PHP, 22 characters


Online demo (var_dump)



assert 15 < 30

Throws an AssertionError if not.


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