# Backstory

Not really real, sshh!

It all started one day when a coworker brought in a homemade loaf of bread for my boss's birthday.

My boss really liked this loaf of bread, and he wanted another. Unfortunately, my coworker has quit, so my boss needs me to give him another loaf.

The problem is, I have no idea how to make bread. So I told my boss that i'm not a chef and to look harder for someone who is.

He said, "Sure...but you lose your job if you can't make me a loaf."

Then I had an idea.

I would make him an loaf with my coding skilz! He said yes, under 1 condition: "You must make it in under 351 bytes." Unfortunately for me, my best code golfing got me to 375 bytes. Uh oh.

Then my boss added 2 things: "You must give me that loaf in a week (4/13), and if you do so you get an increased salary. The lower the amount of bytes you use, the better salary. But remember, if you go over 349 you lose your job."

So I need your help in your language of choice to help me keep my job!

# Rules

I was about to do a curl ... | sh on a TinyURL, but my boss told me that I can't use a list of loopholes. I probably could skirt the rules, but my job is at stake, so it's not a good idea.

# What counts as a loaf

Your program or function must take 3 positive integers as input. If your language has a list or array, you can take a list or array of those numbers. You can also take them as arguments to a function or program, or a space-separated string of numbers to STDIN, a command-line or function argument, etc.

The first number is the width of your loaf

The second number is the height of your loaf.

The third number is the depth of your loaf.

Here's a loaf with a width of 3, a height of 2, and a depth of 1:

 /---\
/---\|
|   ||
|___|/


Looks wierd? Here's a 3x2x2:

  /---\
/    |
/---\ |
|   | /
|___|/


How about a 3x3x3:

   /---\
/    |
/     |
/---\  |
|   |  /
|   | /
|___|/


A 4x1x2:

  /----\
/     |
/----\ /
|____|/


I hope you understand! See my JS (ES6) answer below for an example.

Also see complete test cases

# Notes:

• Don't worry about valid input. All sizes will be positive integers.
• You must accept any positive integers that your language can support.
• If the numbers are so high your languages crashes from StackOverflow, maximum string length overflow, etc. that's OK.

# Shortest answer in bytes wins!

• I guess if you had used Charcoal you could have asked for a 10% raise... :) – ElPedro Apr 6 '17 at 19:44
• What about 350 bytes? – boboquack Apr 7 '17 at 3:27
• "You must make it in under 351 bytes". "Remember, if you go over 349 bytes, you lose your job". What do you actually mean? Please be consistent with yourself. – HyperNeutrino Apr 9 '17 at 0:59

# Charcoal, 3533 30 bytes

Saved 2 bytes thanks to @ASCII-only

Saved 3 bytes thanks to @Neil by rearranging the order in which the lines where drawn

ＮωＮηＮδ↓η↗→×_ω↑η←\←ω↗δ→/ω↓\↓η↙δ


Try it online!

This is my first try at Charcoal. I heard it was good at , so I tried it out.

### Explanation (outdated)

ＮωＮηＮδ                  # Take the width, height and depth as input
↗¹                        # Write 1 /
↗δ                        # Write depth times /
¶ω                        # Move the cursor down and write - width times
\                         # Write \
↙↓η                       # Move the cursor one down and one left, and then write | height times
↙δ                        # Write / depth times


Now the back part of the loaf is complete. Now comes the front face.

↑↑η                       # Go up and write | height times
←\                        # Write a \ and move 1 to the left
←ω                        # Write - width times
↓↓η                       # Go down and write | height times
↗Ｐ×_ω                    # Go northeast and write _ width times

• That's just plain cool! – ElPedro Apr 6 '17 at 18:14
• hahaha I knew it soon as I saw the ascii loaf...! – Nelz Apr 6 '17 at 19:39
• You can replace ↓→ with ¶ (newline), and \←←←ω with ←\←ω – ASCII-only Apr 10 '17 at 0:11
• @ASCII-only Thanks for the tips :) – Kritixi Lithos Apr 10 '17 at 9:54
• Your explanation has ←\← but the second ← belongs before the ω on the next line. ↗δ→/ is a byte shorter than ↗¹↗δ¶, but I also saved a couple more bytes by rearranging the order in which the lines were drawn: Try it online! – Neil May 25 '17 at 21:31

# C, 270290320 328 bytes

#define P printf(
p(n,s)char*s;{P s,--n&&p(n,s));}i,j,k;f(w,h,d){P "%*c",d+1,47);p(w,"-");P "\\\n");for(i=d,j=h,k=0;--i;)P "%*c%*c\n",i+1,47,w+d+1-i-k+!!k,j-->0?124:(++k>0)*47);P "/");p(w,"-");P "\\%*c\n",d-k,j-->0?124:47);for(k&&k++;++i<h;)P "|%*c%*c\n",w+1,124,d-k>!k?d+1-k-!k:0,j-->0?124:(++k>0)*47);P "|");p(w,"_");P "|/");}


Finally (after two three incorrect versions) it works correctly with large sizes also.

Try it online!

# JS (ES6), 375 bytes

s=(s,t)=>s.repeat(t);(d,c,e)=>{z=" ",y=
,x="\\",w="/",v="|",u="-";a=s(z,e--);a=a+w+s(u,d);a+=x+y;for(b=0;b<e;b++)a+=s(z,e-b),b<c?(a+=w,a+=s(z,d+b+1),a+=v):(a+=w,a+=s(z,d+c+1),a+=w),a+=y;a=a+w+s(u,d);a+=x;f=0;b<c?(a+=s(z,e),a+=v):(a+=s(z,c-f),a+=w);b++;f++;a+=y;for(g=0;g<c;g++)a+=v,a+=s((g==c-1?"_":z),d),a+=v,b<c?(a+=s(z,e),a+=v):(a+=s(z,c-f),a+=w),b++,f++,a+=y;return a}


Ungolfed:

var proc = function(width, height, depth){
var str = "";

//Back of loaf (depth)
str += " ".repeat(depth);//initial padding before start of back of loaf
str += "/";//top left corner of back of loaf
str += "-".repeat(width);//top edge of back of loaf
str += "\\";//top left corner of back of loaf
str += "\n";//end line

//Depth lines
for(var i = 0; i < depth - 1; i++){
console.log(i)
str += " ".repeat(depth - i - 1);//space padding before start of left middle edge
if(i < height){
//str += " ".repeat(depth - i - 2);
str += "/";//left middle edge
str += " ".repeat(width + i + 1);//middle of loaf
str += "|";//end that edge
str += "\n";//end line
}else{
str += "/";//left middle edge
str += " ".repeat(width + height + 1);//between two /s
str += "/";//right middle edge
str += "\n";//end line
}
}

//front top edge of loaf
str += "/";//top left corner
str += "-".repeat(width);//top edge
str += "\\";//top right corner

var i3 = 0;

if(i < height){
str += " ".repeat(depth - 1);//space for the incoming far right edge
str += "|";//far right edge
i++;
i3++;
}else{
str += " ".repeat(height - i3);//space for the incoming far right edge
str += "/";//far right edge
i++;
i3++;
}

str += "\n";//newline

for(var i2 = 0; i2 < height; i2++){
str += "|";//left edge
str += (i2 === height - 1 ? "_" : " ").repeat(width);//if we are at the bottom, use underscores to mark that, otherwise spaces.
str += "|";
if(i < height){
str += " ".repeat(depth - 1);//space for the incoming far right edge
str += "|";//far right edge
i++;
i3++;
}else{
str += " ".repeat(height - i3);//space for the incoming far right edge
str += "/";//far right edge
i++;
i3++;
}
str += "\n";//newline
}

return str;
};


s=(s,t)=>s.repeat(t);
var bakeBread = (d,c,e)=>{z=" ",y=
,x="\\",w="/",v="|",u="-";a=s(z,e--);a=a+w+s(u,d);a+=x+y;for(b=0;b<e;b++)a+=s(z,e-b),b<c?(a+=w,a+=s(z,d+b+1),a+=v):(a+=w,a+=s(z,d+c+1),a+=w),a+=y;a=a+w+s(u,d);a+=x;f=0;b<c?(a+=s(z,e),a+=v):(a+=s(z,c-f),a+=w);b++;f++;a+=y;for(g=0;g<c;g++)a+=v,a+=s((g==c-1?"_":z),d),a+=v,b<c?(a+=s(z,e),a+=v):(a+=s(z,c-f),a+=w),b++,f++,a+=y;return a}
<input type = "number" id = "a1">
<br/>
<input type = "number" id = "a2">
<br/>
<input type = "number" id = "a3">
<br/>
<button onclick = "document.getElementById('textarea').innerText = bakeBread(+(document.getElementById('a1').value), +(document.getElementById('a2').value), +(document.getElementById('a3').value))">Bake Bread!</button>
<br/>
<textarea id = "textarea"></textarea>

• "in under 351 bytes" Someone just got fired :( – Shadow Apr 7 '17 at 1:37
• @shadow, actually, I need a < 351 bytes program to send to my boss. Any of the answers below will work! – programmer5000 Apr 7 '17 at 11:39

# Python 2, 234216 210 bytes

w,h,d=input()
f,g='|','/';z,s=g+'-'*w+'\\',' '
print'\n'.join([s*d+z]+[s*(d-c)+g+s*(w+c)+(f,g)[c>h]for c in range(1,d)]+[z+s*(d-1)+(f,g)[d>h]]+[f+s*w+f+s*(h-e-1)+(f,s+g)[d>=h]for e in range(1,h)]+[f+'_'*w+f+g])


Try it online!

Sure it can be golfed a lot more but it's a start. 210 will do for me for now.

# PHP, 420 bytes

<?php $a=$_GET["a"];$b=$_GET["b"];$c=$_GET["c"];$w="<br>";$s="&nbsp;";$u="&#95";$p="|";$k="/";$t=str_repeat;$l='';$r=$t($s,$c).$k.$t("-",$a)."\\".$w;for($i=0;$i<$c+$b-1;$i++){$i<=$b-1?($i<$c-1?$l=$t($s,$a+$i+1).$p:$l=$t($s,$c-1).$p):($i<$c-1?$l=$t($s,$a+$b+1).$k:$l=$t($s,$c+$b-$i-1).$k);$i<$c-1?$r.=$t($s,$c-$i-1).$k.$l.$w:($i==$c-1?$r.=$k.$t("-",$a)."\\".$l.$w:$r.=$p.$t($s,$a).$p.$l.$w);};echo$r.=$p.$t($u,$a).$p.$k?>  Sounds like someone's fired - maybe try convincing your boss that it's much cooler on backend. Input is attached to the URL string: ?a=[width]&b=[height]&c=[depth] - ycou can try it online on my cheap host. In these situations, I really love using GET requests. Ungolfed for transparency: <?php$a=$_GET["a"];$b=$_GET["b"];$c=$_GET["c"];$w="<br>";$s="&nbsp;";$u="&#95"; $p="|";$k="/";$t=str_repeat;$f=$v=$m=$l=''; //first line$r=$t($s,$c).$k.$t("-",$a)."\\".$w; for($i=0;$i<$c+$b-1;$i++){

//right side of the loaf
$i <=$b-1
? ($i <$c-1 ? $l=$t($s,$a+$i+1).$p : $l=$t($s,$c-1).$p) : ($i < $c-1 ?$l=$t($s,$a+$b+1).$k :$l=$t($s,$c+$b-$i-1).$k) ;

//left side, with the right side attached
$i<$c-1
? $r.=$t($s,$c-$i-1).$k.$f.$l.$w : ($i==$c-1 ?$r.=$k.$t("-",$a)."\\".$f.$l.$w
: $r.=$p.$t($s,$a).$p.$f.$l.$w); }; //final line echo$r.=$p.$t($u,$a).$p.$k;

?>


## JavaScript (ES6), 204 bytes

(w,h,d)=>[...Array(h-~d)].map((_,y)=>[...Array(w-~d)].map((_,x)=>x+y==d|x+y==h+w-~d?/:x==w+d&y<=h&&y||!x|x==w&&y>d?|:y==h+d&x<w?_:!y|y==d?x+y==w+d?\\:x+y>d&x+y<w+d?-: : ).join,++w).join\n


Where \n represents the literal newline character.

Rather than fiddle around with repeating characters, this just creates a suitably sized array and computes which character appears in each cell.