Given a string of ASCII art like such (This isn't ASCII art but it will do for the example):

d e

Jumble it as if it was being displayed on a screen with one character per line, like so:



Print the result, wait one second, ±0.5 seconds before clearing the terminal and the print the same thing, but with 2 characters displayed per line instead of 1. Basically, the width of the display turns from 1 to 2.


Note the space after the d. Repeat waiting, then printing with an additional character per line until the inputted text is outputted.

If you hit the end of a line when trying to print characters, then you insert a newline and print the rest of them following this rule. For example the input:


Would print the following when the display length is 4.


You can find the effect of the terminal resize here: https://repl.it/GoeU/1. Run the program, then drag the thing separating the terminal from the text editor back and forth.


Once a line appears exactly how it was inputted, you can leave that line alone for future larger character counts per line.


should print


when the sentence length = 2.

This is , so least amount of bytes wins!


  • Must print to STDOUT as the only output.
  • Must clear the terminal, or create the illusion of clearing the terminal by adding 150 or so empty lines.
  • Can take input through the standard methods.
  • Default loopholes apply.
  • Trailing stuff with the text is NOT OKAY.

This idea came to me when I was resizing a terminal with ASCII art on it. It looked interesting, so I decided to make a challenge out of it.

Test cases:

Since it would be too much work to show each step for each test case individually, I will review each answer to make sure it is valid. Make sure the answer can handle the test cases.

 ______   ______     __     __   __     ______      __    __     ______    
/\  == \ /\  == \   /\ \   /\ "-.\ \   /\__  _\    /\ "-./  \   /\  ___\   
\ \  _-/ \ \  __<   \ \ \  \ \ \-.  \  \/_/\ \/    \ \ \-./\ \  \ \  __\   
 \ \_\    \ \_\ \_\  \ \_\  \ \_\\"\_\    \ \_\     \ \_\ \ \_\  \ \_____\ 
  \/_/     \/_/ /_/   \/_/   \/_/ \/_/     \/_/      \/_/  \/_/   \/_____/ 

This pastebin.

                        \    /
                  __/\__/    \__/\__
                  \                /
                  /_              _\
                    \            /
      __/\__      __/            \__      __/\__
      \    /      \                /      \    /
__/\__/    \__/\__/                \__/\__/    \__/\__

3 Answers 3


Python 3.6, 124 bytes

Loops over length of input string like officialaimm's solution

import re,time
def d(s):
 for i in range(len(s)):print(*'\n'*75,*re.split(f'(.{{1,{i+1}}})',s)[1::2],sep='\n');time.sleep(1)

143 bytes to only go to width of longest line a al Frxstrem's Bash answer

import re,time
def d(s):
 for i in range(max(map(len,s.split()))):print(*'\n'*75,*re.split(f'(.{{1,{i+1}}})', s)[1::2],sep='\n');time.sleep(.5)

Uses "re.split((.{1,i+1}))" to break the string into groups of characters. Because '.' doesn't match '\n', the groups don't wrap around from one line to the next. If the regex uses a capturing group, then re.split() returns a list with the matched groups at the odd indexes. These are retrieved with [1::2].

Uses python 3.6 f-string to make the re pattern depend on group width i.

The * in front of re.split() uses python 3.6 unpacking to turn the list into arguments to the print statement. Similarly, *'\n'*75, turns into 75 '\n' arguments to the print statement. With the print keyword argument sep='\n', the result is printing about 150 blank lines to clear the screen, followed by each group of characters on a separate line.

  • \$\begingroup\$ This ones way better and shorter than mine. Great job! (y) \$\endgroup\$
    – 0xffcourse
    Commented Apr 2, 2017 at 2:55

Bash (with GNU coreutils), 69 bytes

n=`tee x|wc -L`;for i in `seq 1 $n`;do fold -w$i x;sleep 1;clear;done

Saves input in temporary file x, then counts the longest line (GNU coreutils' wc has -L flag for this) and iterates for each console width from 1 to the longest line length. fold, sleep and clear does the rest of the magic.


Python 3.5 (238 233 229 225 223 222 bytes)

- Works fine in the windows terminal; not sure about other platforms, because of the system-specific os.system("cls") command.

- The string passed should be marked by \n for newlines eg: 'abc\nd efgh\n'

import os,time 
def b(s):
 for i in r(1,p):
  for j in r(p):
   if(j+1<p and l==i and s[j+1]!='\n'):z();l=0
  • Saved 5 bytes: removed unwanted whitespaces
  • Saved 4 bytes: shorthand for len(s)
  • Saved 4 bytes: Thanks to sparklepony (shorthand for print)
  • saved 2 bytes: Thanks to sparklepony (shorthand for range as r and r(0,i) as range(i))
  • saved 1 byte: Thanks to steve (0.5 as just .5)
  • 1
    \$\begingroup\$ Cool! I think you could shave off some bytes by using the code z=print at the top, and then changing all other instances of print() to z(). \$\endgroup\$
    – sporkl
    Commented Apr 1, 2017 at 13:09
  • 1
    \$\begingroup\$ I think you cold do the same thing you did with print with range, and instead of range(0,3) use range(3). \$\endgroup\$
    – sporkl
    Commented Apr 1, 2017 at 17:05
  • 1
    \$\begingroup\$ sleep(0.5) can be rewritten as merely sleep(.5) \$\endgroup\$
    – steve
    Commented Apr 1, 2017 at 21:36

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