Reverse words without changing capitals or punctuation

Question

Create a program with the lowest amount of characters to reverse each word in a string while keeping the order of the words, as well as punctuation and capital letters, in their initial place.

By "Order of the words," I mean that each word is split by a empty space (" "), so contractions and such will be treated as one word. The apostrophe in contractions should stay in the same place. ("Don't" => "Tno'd").

(Punctuation means any characters that are not a-z, A-Z or whitespace*).

• Numbers were removed from this list due to the fact that you cannot have capital numbers. Numbers are now treated as punctuation.

For example, for the input:

Hello, I am a fish.

it should output:

Olleh, I ma a hsif.

Notice that O, which is the first letter in the first word, is now capital, since H was capital before in the same location.

The comma and the period are also in the same place.

More examples:

This; Is Some Text!

would output

Siht; Si Emos Txet!

Any language can be used. The program with the lowest amount of characters wins.

Answer 1

GolfScript, 58 54 48 characters

" "/{.{65- 223&26<}:A,\{.A{96&\)31&@+}*}%+}%" "*

This is a GolfScript solution which became rather long. Lots of the code is actually finding out if a character is in a-zA-Z. Maybe someone can find an even shorter way of testing it.

You can try the code online. Examples:

> Hello, I am fish.
Olleh, I ma hsif.

> This; Is Some Text!
Siht; Si Emos Txet!

> Don't try this at home.
Tno'd yrt siht ta emoh.

Answer 2

APL 69

Takes screen input via: t←⍞

⎕av[1↓∊(↑¨v),¨((¯1×⌽¨z)+z←¯32×~1↓¨v>97)+¨⌽¨1↓¨v←(+\v<66)⊂v←0,⎕av⍳t←⍞]

Answer 3

Coffeescript, 134 133 characters

alert prompt().replace /\S+/g,(x)->c=x.match r=/[a-z]/gi;return x.replace r,(y)->return c.pop()[`(y<"a"?"toUpp":"toLow")`+"erCase"]()

Coffeescript is (for the purposes of code golf) a slightly denser version of javascript. It doesn't have the ternary operator, but it has an escape to javascript.

Here's the javascript version:

Javascript, 152 151 characters

alert(prompt().replace(/\S+/g,function(x){c=x.match(r=/[a-z]/gi);return x.replace(r,function(y){return c.pop()[(y<"a"?"toUpp":"toLow")+"erCase"]()})}))

Indented:

alert(prompt().replace(/\S+/g,function(x){
  c=x.match(r=/[a-z]/gi);
  return x.replace(r, function(y){
    return c.pop()[(y<"a"?"toUpp":"toLow")+"erCase"]()
  })
}))

Answer 4

Ruby: 89 characters (including 1 for the -p switch)

Not copied Jan Dvorak's CoffeeScript solution, but after many attempts my code ended looking like an exact copy. A subconscious voice probably kept whispering “follow the white rabbit Jan Dvorak”. So upvotes for the algorithm should go to his answer.

$_.gsub!(/\S+/){|m|l=m.scan r=/[a-z]/i;m.gsub(r){|c|l.pop.send c<?a?:upcase: :downcase}}

Sample run:

bash-4.2$ ruby -p reverse-word.rb <<< "Hello, I am a fish.
This; Is Some Text!
Don't touch that!
S'm00ch1e"
Olleh, I ma a hsif.
Siht; Si Emos Txet!
Tno'd hcuot taht!
E'h00cm1s

Answer 5

Lua, 143

print(((io.read"*l"):gsub("%w+",function(s)local r=""for i=1,#s do r=("")[s:byte(-i)>96 and"lower"or"upper"](s:sub(i,i))..r end return r end)))

Answer 6

EcmaScript 6 (112 characters)

The input is provided in s.

alert(s.replace(/\S+/g,x=>(_=x.match(X=/[a-z]/gi),x.replace(X,a=>_.pop()[(a<"a"?"toUpp":"toLow")+"erCase"]()))))

Based on @Jan Dorvak's answer.

Answer 7

C# (375)

 public static string rev(string s)
    {
        var r = new Regex("[^A-za-z]");

        var result = "";
        var token = "";
        foreach (var c in s)
        {
            if (!r.IsMatch(c + ""))
            {
                token += c;
            }
            else
            {
                result += new string(token.Reverse().ToArray());
                result += c;
                token = "";
            }
        }

        var arr = result.ToArray();
        int i = 0;
        foreach (var c in s)
        {
            arr[i] = char.IsUpper(c) ? char.ToUpper(arr[i]) : char.ToLower(arr[i]);
            i++;
        }

        result = new string(arr);
        return result;
    }

Minified

public static string rev(string s){var r=new Regex("[^A-za-z]");var result="";var token="";foreach(var c in s){if(!r.IsMatch(c+"")){token+=c;}else{result+=new string(token.Reverse().ToArray());result+=c;token="";}}var arr=result.ToArray();int i=0;foreach(var c in s){arr[i]=char.IsUpper(c)?char.ToUpper(arr[i]):char.ToLower(arr[i]);i++;}result=new string(arr);return result;}