ASCII Triangles

Question

Your task is to write a program or a function that prints an ASCII triangle. They look like this:

|\
| \
|  \
----

Your program will take a single numeric input n, with the constraints 0 <= n <= 1000. The above triangle had a value of n=3.

The ASCII triangle will have n backslashes (\) and vertical bars (|), n+1 lines and dashes (-), and each line will have an amount of spaces equal to the line number (0-based, ie first line is line 0) besides the ultimate line.

Examples:

Input:

4

Output:

|\
| \
|  \
|   \
-----

Input:

0

Output:

In this test case, the output must be empty. No whitespace.

Input:

1

Output:

|\
--

Input & output must be exactly how I specified.

This is code-golf, so aim for the shortest code possible!

Answer 1

Jelly, 14 bytes

’⁶x⁾|\jṄµ€Ṫ”-ṁ

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How it works.

’⁶x⁾|\jṄµ€Ṫ”-ṁ  Main link. Argument: n

        µ       Combine the links to the left into a chain.
         €      Map the chain over [1, ..., n]; for each k:
’                 Decrement; yield k-1.
 ⁶x               Repeat the space character k-1 times, yielding a string.
   ⁾\j            Join the character array ['|', '\'], separating by those spaces.
      Ṅ           Print the result, followed by a linefeed.
         Ṫ      Tail; extract the last line.
                This will yield 0 if the array is empty.
          ⁾-ṁ   Mold the character '-' like that line (or 0), yielding a string
                of an equal amount of hyphen-minus characters.  

Answer 2

C, 58 bytes

i;f(n){for(i=2*n;~i--;printf(i<n?"-":"|%*c\n",2*n-i,92));}

--

Thanks to @Steadybox who's comments on this answer helped me shave a few bytes in my above solution

Answer 3

Javascript (ES6), 97 85 81 75 74 bytes

n=>(g=(n,s)=>n?g(--n,`|${" ".repeat(n)}\\
`+s):s)(n,"")+"-".repeat(n&&n+1)

Turns out I wasn't using nearly enough recursion

f=n=>(g=(n,s)=>n?g(--n,`|${" ".repeat(n)}\\
`+s):s)(n,"")+"-".repeat(n&&n+1)

console.log(f(0))
console.log(f(1))
console.log(f(2))
console.log(f(3))
console.log(f(4))

Answer 4

05AB1E, 16 15 16 bytes

Saved a byte thanks to Adnan

FðN×…|ÿ\}Dg'-×»?

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Explanation

F       }         # for N in range [0 ... input-1]
 ðN×              # push <space> repeated N times
    …|ÿ\          # to the middle of the string "|\"
         Dg       # get length of last string pushed
           '-×    # repeat "-" that many times
              »   # join strings by newline
               ?  # print without newline

Answer 5

V, 18 17 16 bytes

1 byte saved thanks to @nmjcman101 for using another way of outputting nothing if the input is 0

é\é|ÀñÙá ñÒ-xÀ«D

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Hexdump:

00000000: e95c e97c c0f1 d9e1 20f1 d22d 78c0 ab44  .\.|.... ..-x..D

Explanation (outdated)

We first have a loop to check if the argument is 0. If so, the code below executes (|\ is written). Otherwise, nothing is written and the buffer is empty.

Àñ     ñ            " Argument times do:
  é\é|              " Write |\
      h             " Exit loop by creating a breaking error

Now that we got the top of the triangle, we need to create its body.

Àñ   ñ              " Argument times do:
  Ù                 " Duplicate line, the cursor comes down
   à<SPACE>         " Append a space

Now we got one extra line at the bottom of the buffer. This has to be replaced with -s.

Ó-                  " Replace every character with a -
   x                " Delete the extra '-'

---

This answer would be shorter if we could whatever we want for input 0

V, 14 13 bytes

é\é|ÀñÙá ñÒ-x

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Answer 6

C#, 93 bytes

n=>{var s=n>0?new string('-',n+1):"";while(n-->0)s="|"+new string(' ',n)+"\\\n"+s;return s;};

Anonymous function which returns the ASCII triangle as a string.

Full program with ungolfed, commented function and test cases:

using System;

class ASCIITriangles
{
    static void Main()
    {
      Func<int, string> f =
      n =>
      {
          // creates the triangle's bottom, made of dashes
          // or an empty string if n == 0
          var s = n > 0 ? new string('-', n + 1) : "";

          // a bottom to top process
          while ( n-- > 0)
          // that creates each precedent line
            s = "|" + new string(' ', n) + "\\\n" + s;

          // and returns the resulting ASCII art
          return s;
      };

      // test cases:
      Console.WriteLine(f(4));
      Console.WriteLine(f(0));
      Console.WriteLine(f(1));
    }
}

Answer 7

Python 2, 69 bytes

lambda x:'\n'.join(['|'+' '*n+'\\'for n in range(x)]+['-'*-~x*(x>0)])

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Answer 8

CJam, 24 22 21 bytes

Saved 1 byte thanks to Martin Ender

ri_{S*'|\'\N}%\_g+'-*

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Explanation

ri                     e# Take an integer from input
  _                    e# Duplicate it
   {                   e# Map the following to the range from 0 to input-1
    S*                 e#   Put that many spaces
      '|               e#   Put a pipe
        \              e#   Swap the spaces and the pipe
         '\            e#   Put a backslash
           N           e#   Put a newline
            }%         e# (end of map block)
              \        e# Swap the top two stack elements (bring input to the top)
               _g+     e# Add the input's signum to itself. Effectively this increments any 
                       e#  non-zero number and leaves zero as zero.
                  '-*  e# Put that many dashes

Answer 9

SmileBASIC, 51 bytes

INPUT N
FOR I=0TO N-1?"|";" "*I;"\
NEXT?"-"*(N+!!N)

Answer 10

PowerShell, 51 67 bytes

param($n)if($n){1..$n|%{"|"+" "*--$_+"\"};write-host -n ('-'*++$n)}

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(Byte increase to account for no trailing newline)

Takes input $n and verifies it is non-zero. Then loops to construct the triangle, and finishes with a line of -. Implicit Write-Output happens at program completion.

Answer 11

Retina, 39 bytes

.*
$*
*\`(?<=(.*)).
|$.1$* \¶
1
-
-$
--

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Convert decimal input to unary. Replace each 1 with |<N-1 spaces>\¶, print, and undo replace. Replace each 1 with a hyphen, and the last hyphen with 2 hyphens. Tadaa!

Answer 12

Common Lisp, 89 86 bytes

Creates an anonymous function that takes the n input and prints the triangle to *standard-output* (stdout, by default).

Golfed

(lambda(n)(when(< 0 n)(dotimes(i n)(format t"|~v@t\\~%"i))(format t"~v,,,'-<~>"(1+ n))))

Ungolfed

(lambda (n)
  (when (< 0 n)
    (dotimes (i n)
      (format t "|~v@t\\~%" i))
    (format t "~v,,,'-<~>" (1+ n))))

I'm sure I could make this shorter somehow.

Answer 13

C 101 93 75 bytes

f(n){i;for(i=0;i++<n;)printf("|%*c\n",i,92);for(;n--+1;)prin‌​tf("-");}

Ungolfed version

void f(int n)
{
  int i;

  for(i=0;i++<n;)
    printf("|%*c\n",i,92);

  for(;n--+1;)
    printf("-");

}

@Steadybox Thanks for pointing out, makes a lot of sense.

Answer 14

Charcoal, 15 bytes

Ｎβ¿β«↓β→⁺¹β↖↖β»

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Breakdown

Ｎβ¿β«↓β→⁺¹β↖↖β»
Ｎβ               assign input to variable β
   ¿β«         »  if β != 0:
      ↓β           draw vertical line β bars long
        →⁺¹β       draw horizontal line β+1 dashes long
            ↖      move cursor up one line and left one character
             ↖β    draw diagonal line β slashes long

Answer 15

Japt, 20 bytes

Saved 2 bytes thanks to @ETHproductions

o@'|+SpX +'\Ãp-pUÄ)·

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Explanation

o@'|+SpX +'\Ãp-pUÄ)·
o                       // Creates a range from 0 to input
 @                      // Iterate through the array
  '|+                   // "|" + 
     SpX +              // S (" ") repeated X (index) times +
          '\Ã            // "\" }
             p-pU       // "-" repeated U (input) +1 times
                 Ä)·    // Join with newlines

Answer 16

J, 20 bytes

-13 bytes thanks to bob

*#' \|-'{~3,~2,.=@i.

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original: 33 bytes

(#&'| \'@(1,1,~])"0 i.),('-'#~>:)

ungolfed

(#&'| \' @ (1,1,~])"0 i.) , ('-'#~>:)

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Answer 17

Pyke, 18 17 bytes

I Fd*\|R\\s)Qh\-*

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Answer 18

Python2, 73 bytes

n=input()
w=0
exec'print"|"+" "*w+"\\\\"+("\\n"+"-"*-~n)*(w>n-2);w+=1;'*n

A full program. I also tried string interpolation for the last line, but it turned out be a couple bytes longer :/

exec'print"|%s\\\\%s"%(" "*w,("\\n"+"-"*-~n)*(w>n-2));w+=1;'*n

Another solution at 73 bytes:

n=j=input()
exec'print"|"+" "*(n-j)+"\\\\"+("\\n"+"-"*-~n)*(j<2);j-=1;'*n

Test cases

0:

1:
|\
--

2:
|\
| \
---

3:
|\
| \
|  \
----

6:
|\
| \
|  \
|   \
|    \
|     \
-------

Answer 19

MATL, 19 bytes

?'\|- '2GXyYc!3Yc!)

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?         % Implicit input. If non-zero
  '\|- '  %   Push this string
  2       %   Push 2
  G       %   Push input
  Xy      %   Identity matrix of that size
  Yc      %   Prepend a column of 2's to that matrix
  !       %   Transpose
  3       %   Push 3
  Yc      %   Postpend a column of 3's to the matrix
  !       %   Transpose
  )       %   Index into string
          % Implicit end. Implicit display

Answer 20

QBIC, 41 bytes

:~a>0|[a|?@|`+space$(b-1)+@\`][a+1|Z=Z+@-

Explanation

:~a>0|  Gets a, and checks if a > 0
        If it isn't the program quits without printing anything
[a|     For b=1; b <= a; b++
?@|`+   Print "|"
space$  and a number of spaces
(b-1)   euqal to our current 1-based line - 1
+@\`    and a "\"
]       NEXT
[a+1|   FOR c=1; c <= a+1; c++
Z=Z+@-  Add a dash to Z$
        Z$ gets printed implicitly at the end of the program, if it holds anything
        The last string literal, IF and second FOR loop are closed implicitly.

Answer 21

R, 101 bytes

for(i in 1:(n=scan())){stopifnot(n>0);cat("|",rep(" ",i-1),"\\\n",sep="")};cat("-",rep("-",n),sep="")

This code complies with the n=0 test-case if you only consider STDOUT !
Indeed, the stopifnot(n>0) part stops the script execution, displays nothing to STDOUT but writes Error: n > 0 is not TRUE to SDTERR.

Ungolfed :

for(i in 1:(n=scan()))
    {
    stopifnot(n>0)
    cat("|", rep(" ", i-1), "\\\n", sep = "")
    }

cat("-", rep("-", n), sep = "")

Answer 22

Python 2, 62 bytes

n=input();s='\\'
exec"print'|'+s;s=' '+s;"*n
if n:print'-'*-~n

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Prints line by line, each time adding another space before the backslash. If a function that doesn't print would be allowed, that would likely be shorter.

Answer 23

JavaScript (ES6), 71 bytes

f=
n=>console.log(' '.repeat(n).replace(/./g,'|$`\\\n')+'-'.repeat(n+!!n))

<form onsubmit=f(+i.value);return!true><input id=i type=number><input type=submit value=Go!>

Outputs to the console. Save 6 bytes if printing to the SpiderMonkey JavaScript shell is acceptable. Save 13 bytes if returning the output is acceptable.

Answer 24

Python 2, 67 bytes

Another function in Python 2, using rjust.

lambda n:('|'.join(map('\\\n'.rjust,range(n+2)))+'-'*-~n)[4:]*(n>0)

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Answer 25

Python 3, 60 bytes

f=lambda n,k=0:k<n and'|'+' '*k+'\\\n'+f(n,k+1)or'-'[:n]*-~n

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Two more solutions with the same byte count.

f=lambda n,k=0:n and'|'+' '*k+'\\\n'+f(n-1,k+1)or-~k*'-'[:k]
f=lambda n,s='|':-~n*'-'[:n]if s[n:]else s+'\\\n'+f(n,s+' ')

Answer 26

Perl, 63 bytes

$n=shift;print'|',$"x--$_,"\\\n"for 1..$n;print'-'x++$n,$/if$n

Ungolfed:

$ perl -MO=Deparse triangle.pl
$n = shift @ARGV;
print '|', $" x --$_, "\\\n" foreach (1 .. $n);
print '-' x ++$n, $/ if $n;

$" is the list separator, which defaults to " ". $/ is the output record separator, which defaults to "\n". $_ is the implicit loop variable.

Answer 27

Haskell, 82 65 bytes

g 0=""
g n=((take n$iterate(' ':)"\\\n")>>=('|':))++([0..n]>>"-")

Try it online! Usage:

Prelude> g 4
"|\\\n| \\\n|  \\\n|   \\\n-----"

Or more nicely:

Prelude> putStr $ g 4
|\
| \
|  \
|   \
-----

Answer 28

Pyth, 23 18 bytes

VQ++\|*dN\\)IQ*\-h

Test suite available online.
Thanks to Ven for golfing off 5 bytes.

Explanation

VQ++\|*dN\\)IQ*\-h
 Q           Q    Q  [Q is implicitly appended, initializes to eval(input)]
       d             [d initializes to ' ' (space)]
VQ         )         For N in range(0, eval(input)):
      *dN             Repeat space N times
   +\|                Prepend |
  +      \\           Append \
                      Implicitly print on new line
            IQ       If (input): [0 is falsy, all other valid inputs are truthy]
                 hQ   Increment input by 1
              *\-     Repeat - that many times
                      Implicitly print on new line

Answer 29

brainf**k, 256 bytes

[-]>[-]+[[-]>[-],[+[-----------[>[-]++++++[<------>-]<--<<[->>++++++++++<<]>>[-<<+>>]<+>]]]<]<>++++++++++[>+>+++>++++>+++++++++>++++++++++++<<<<<-]>>++>+++++>++>++++<<<<<<[>[-]+>>>>>.>[>+<<<<<.>>>>-]>[-<+>]<<<.>>+<<<<<.<<-]>>>>>>>[<<<.>>>-]<<<<<<[>>>.<<<-]

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How it works

# Read input and convert to number (https://esolangs.org/wiki/Brainfuck_algorithms#Input_a_decimal_number)
[-]>[-]+[[-]>[-],[+[-----------[>[-]++++++[<------>-]<--<<[->>++++++++++<<]>>[-<<+>>]<+>]]]<]<

# We need the characters {LF} (10); {space} (32); {minus} (45); \(92) | (120)

P1 > ++++++++++
   [
p0  < 
P1  >
P2  >  +                     
P3  >  +++
P4  >  ++++
P5  >  +++++++++
P6  >  ++++++++++++
P5  <
P4  <
P3  <
P2  <
P1  < -
   ]
P0 <           # Contains n
P1 >           # is zero
P2 >           # is {LF}
P3 > ++        # is {space}
P4 > +++++     # is {minus}
P5 > ++        # is \
P6 > ++++      # is |
p5 <
p4 <
p3 <
p2 <
p1 <
p0 <
   [           # Loop through n
P1 >[-]+       # p1 will be 1 if input was not 0; used to output the additional {minus}
p2 >
p3 >
p4 >
p5 >
p6 > .
## output p7 spaces; copy p7 to p8
p7 >
   [
p8 > +
p7 < 
p6 <
p5 <
p4 <
p3 < .  # output {space}
p4 >
p5 >
p6 >
p7 > -
   ]
## copy p8 back to p7
p8 >
   [
   -
p7 < +   
p8 >
   ]      
p7 <
p6 <
p5 < . # output \
p6 >
p7 > + # increase number of spaces
p6 <
p5 <
p4 <
p3 <
p2 < . # output {LF}
p1 <
p0 < -
   ]
p1 >
p2 >
p3 >
p4 >
p5 >
p6 >
## output p7 minuses
p7 >
   [
p6 <
p5 <
p4 < .
p5 >
p6 >
p7 > -
   ]
p6 <
p5 <
p4 <
p3 <
p2 <
## output additional minus
p1 <
  [
p2 >  
p3 >
p4 > .
p3 <
p2 <
p1 < -
  ]

This is my first contribution and I'm not sure whether it is allowed to re-use code from others. My code above uses the code published in the Wiki to read the input characters and convert them into a number. Hope that's okay.

Answer 30

Python 3, 72 bytes

x=int(input())
for i in range(x):
    print('|'+' '*i+'\\')
print('-'*x)

First submission. Very basic and entry level.

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