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Many of you may have interacted with people from Russia on the internet at some point, and a subset of you may have noticed the slightly odd method they have of expressing themselves.

e.g. удали игру нуб)))

where the ))) are added for emphasis on the previous statement, I have been working on a theory that the ratio of )'s to the rest of the string is directly proportional to the amount of implied emphasis, however I oftentimes find it difficult to compute the ratio on the fly, as I am also trying to cope with a slew of abuse, so I would like the shortest possible code to help me calculate what the resulting string should be, for a value of enthusiasm between 0 and 500%, given the original, unenthusiastic string, this will aid my research greatly as I will not have to type out bulky scripts every time I wish to test my hypothesis.

So, the challenge:

write a full program or function, which, provided two arguments, a string of unknown length, and a number, in either integer format (between 0 and 500) or in decimal format (between 0 and 5, with 2 points of accuracy) will

  • return/display the original string, suffixed with a number of )'s
  • the number will be the calculated as a ratio of the input number to the string length.
  • so if the number 200, or 2.00 was provided, 200% of the string must be suffixed as )'s
  • the number of brackets rounded to in decimal situations does not matter.
  • script is required to support Printable ASCII characters.
  • only has to support one input number format, of your choice.

Examples:

"codegolf" 125      = codegolf))))))))))
"codegolf" 75       = codegolf))))))
"noob team omg" 0.5 = noob team omg))))))
"hi!" 4.99          = hi!)))))))))))))))

Example code (PowerShell) (with decimal input):

Function Get-RussianString ([string]$InputStr,[decimal]$Ratio){
    $StrLen = $InputStr.Length
    $SuffixCount = $StrLen * $Ratio
    $Suffix = [string]::New(")",$SuffixCount)
    return $InputStr + $Suffix
}

Get-RussianString "codegolf" 0.5
codegolf))))

This is so shortest code wins!

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  • 2
    \$\begingroup\$ I'm confused, do Russians really use ) for emphasis like an !? Is it some encoding issue? \$\endgroup\$ – Captain Man Jan 30 '17 at 16:25
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    \$\begingroup\$ @CaptainMan I believe it's more like smiley faces than !s, but they do type them as is, it's not super common, but it's quite iconic. \$\endgroup\$ – colsw Jan 30 '17 at 16:47
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    \$\begingroup\$ @CaptainMan No ) is reduced emoticon :). It is used very common between young people as far as I know. \$\endgroup\$ – talex Jan 30 '17 at 17:23
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    \$\begingroup\$ ) is not an emphasis, it is simply the smiley. As far as I know, it is harder to type : when using Russian keyboard layout, therefore they smile without eyes. \$\endgroup\$ – Džuris Jan 30 '17 at 17:28
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    \$\begingroup\$ @Juris it's as hard to write : on Russian layout (ЙЦУКЕН) as it is to type ^ on QWERTY. But indeed, the ) is a reduced version of :). It's much easier to press and hold Shift-0 than to repeatedly alternate keys. \$\endgroup\$ – Ruslan Jan 30 '17 at 18:12

36 Answers 36

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C++14, 43 bytes

As unnamed lambda modifying its input, assuming s is similar to std::string (has .append(int,char) and assuming p to be of floating point type:

[](auto&s,auto p){s.append(s.size()*p,41);}

Usage:

#include<string>
#include<iostream>

auto f=
[](auto&s,auto p){s.append(s.size()*p,41);}
;


int main() {
 std::string s = "abcdefghijk";
 f(s,0.75);
 std::cout << s << std::endl;
}
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Haskell, 37 bytes

s!n=s++([1..div(n*length s)100]>>")")

Try it online! Usage: "codegolf" ! 125


A version that takes a decimal number: (41 bytes)

s!n=s++([1..n*toRational(length s)]>>")")

Try it online! Usage: "codegolf" ! 1.25

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Jellyfish, 16 bytes

P
,$')
 *i
 #
EI

Takes input as decimal, then newline, then string. Try it online!

Explanation

Let's start from the bottom.

I

A raw string read from STDIN.

#
I

The length of the string.

*i
#
I

Multiply it by a number read from STDIN (the number is read first, since i comes before I in the source).

$')
*i
#
I

Repeat the character ) that many times, rounding down.

,$')
 *i
 #
EI

Append to the original string (the , looks for arguments from the south and east, and E tells the southward seeker to turn east, where it finds the I).

P
,$')
 *i
 #
EI

Print the resulting string.

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Mathematica, 24 bytes

#<>Table[")",#2Tr[1^#]]&

Unnamed function taking a list of characters and a decimal number as input and returning a string. Tr[1^#] is a sneaky golfy way to calculate the length of a list, so #2Tr[1^#] computes the required number of parentheses. Table[")",...] produces a list of that many right parentheses (all decimals automatically rounded down, which is nice). Finally, #<> concatenates the input string to the parentheses, flattening the list produced by Table as it goes.

| improve this answer | |
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  • \$\begingroup\$ That's quite cheaty, taking the string as a list of characters, but returning as a multi-character string. For consistent IO formats you could replace <> with ~Join~ at a cost of 4 bytes \$\endgroup\$ – LLlAMnYP Feb 1 '17 at 12:34
  • \$\begingroup\$ I'd be interested in a community judgment on this issue. If it's cheating, then of course I'll avoid this type of mismatch. But if it's just cheaty - well, it seems to me that cheaty is very much on topic for this site :) \$\endgroup\$ – Greg Martin Feb 1 '17 at 17:37
  • \$\begingroup\$ The challenge specification is sufficiently vague: return/display the original string, suffixed with a number of )'s (though I'd be picky with original string). Many other challenges specifically state "I/O formats must be consistent". If it's not a default rule, I guess you're in the white-enough part of the gray area. \$\endgroup\$ – LLlAMnYP Feb 2 '17 at 7:46
  • \$\begingroup\$ @LLlAMnYP community consensus applies for I/O methods, so I believe this is valid Mathematica \$\endgroup\$ – colsw Feb 2 '17 at 13:39
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Japt, 8 bytes

+')pUÊ*V

Try it

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GNU AWK, 59 bytes

{t=sprintf("%"n*length(s)"s","");gsub(/ /,")",t);print s t}

Accepts arguments on command line (using the decimal form) like so:

: | awk -v s="codegolf" -v n=0.75 -f russianify.awk

Yes, AWK requires something to be attached to stdin, even if that something is 0 bytes returned by the no-op shell builtin. You could also use echo | awk ..., or really anything that doesn't contain a newline.

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