Enthusiastically Russianify a String

Question

Many of you may have interacted with people from Russia on the internet at some point, and a subset of you may have noticed the slightly odd method they have of expressing themselves.

e.g. удали игру нуб)))

where the ))) are added for emphasis on the previous statement, I have been working on a theory that the ratio of )'s to the rest of the string is directly proportional to the amount of implied emphasis, however I oftentimes find it difficult to compute the ratio on the fly, as I am also trying to cope with a slew of abuse, so I would like the shortest possible code to help me calculate what the resulting string should be, for a value of enthusiasm between 0 and 500%, given the original, unenthusiastic string, this will aid my research greatly as I will not have to type out bulky scripts every time I wish to test my hypothesis.

So, the challenge:

write a full program or function, which, provided two arguments, a string of unknown length, and a number, in either integer format (between 0 and 500) or in decimal format (between 0 and 5, with 2 points of accuracy) will

• return/display the original string, suffixed with a number of )'s
• the number will be the calculated as a ratio of the input number to the string length.
• so if the number 200, or 2.00 was provided, 200% of the string must be suffixed as )'s
• the number of brackets rounded to in decimal situations does not matter.
• script is required to support Printable ASCII characters.
• only has to support one input number format, of your choice.

Examples:

"codegolf" 125      = codegolf))))))))))
"codegolf" 75       = codegolf))))))
"noob team omg" 0.5 = noob team omg))))))
"hi!" 4.99          = hi!)))))))))))))))

Example code (PowerShell) (with decimal input):

Function Get-RussianString ([string]$InputStr,[decimal]$Ratio){
    $StrLen = $InputStr.Length
    $SuffixCount = $StrLen * $Ratio
    $Suffix = [string]::New(")",$SuffixCount)
    return $InputStr + $Suffix
}

Get-RussianString "codegolf" 0.5
codegolf))))

This is code-golf so shortest code wins!

Answer 1

Perl 6, 21 bytes

{$^a~")"x$^b*$a.comb}

Answer 2

Jelly, 7 bytes

ȮL×Ċ”)x

Try it online!

Uses the decimal format.

How?

ȮL×Ċ”)x - Main link: string, decimal
Ȯ       - print string
 L      - length(string)
  ×     - multiply by the decimal
   Ċ    - ceiling (since rounding method is flexible)
    ”)  - a ')' character
      x - repeated that many times
        - implicit print

Answer 3

Common Lisp, 59 52 50

Parentheses? I am in.

(lambda(s n)(format()"~a~v@{)~}"s(*(length s)n)0))

Details

(lambda(s n)               ; two arguments (string and ratio)
  (format ()               ; format as string
          "~a~v@{)~}"      ; control string (see below)
          s                ; first argument (string)
          (* (length s) n) ; second argument (number of parens)
          0))              ; one more element, the value does not matter

Format control string

• ~a : pretty print argument (here the given string)
• ~v@{...~} : iteration block, limited to V iteration, where V is taken as an argument, namely the (* ...) expression. The iteration is supposed to iterate over a list, but when you add the @ modifier, the list is the remaining list of arguments to the format function. There must be at least one element in the iterated list (otherwise we exit, disregarding V). That is why there is an additional argument to format (0).

Since no element in the list is consumed by the format, the loop is infinite but fortunately, it is also bounded by V, a.k.a. the number of parentheses to be printed.

---

Edit: thanks to Michael Vehrs for pointing out that there is no need to round the numerical argument (the question allows to truncate/round however we want, so the default behavior works here).

Answer 4

JavaScript ES6, 38 31 30 bytes

s=>n=>s+')'.repeat(s.length*n)

f=s=>n=>s+')'.repeat(s.length*n)

console.log(f("hi!")(4.99))

Answer 5

Python 2, 29 bytes

lambda s,p:s+len(s)*p/100*')'

s in the string, p is the percentage (integer).

Try it online!

Answer 6

05AB1E, 9 8 bytes

g*ï')×¹ì

Try it online!

g*       # Length, multiplied by emphasis.
  ï')×   # Covnerted to an integer, push that many parenthesis.
      ¹ì # Prepend original string.

Works for both integer and decimal, arguments order: f(String, Double)

Answer 7

Python, 30 bytes

lambda s,r:s+')'*int(len(s)*r)

Uses the decimal input.

Try it online!

Answer 8

Pyth, 8 bytes

*\)s*lpz

Online Test! Takes the excitement ratio first, then the string to be enthused about.

Explanation:

      pz  print out the enthused string
     l    ... and get its length
    *...Q multiply that by the ratio
   s      floor to get an integer, let's call this S
 \)       single-character string ")"
* ")" S   multiply that integer by the string, which gives a string of )s of length S.
          implicitly print that string of S )s.

Answer 9

PowerShell, 33 bytes

$a,$b=$args;$a+')'*($b*$a.Length)

Try it online!

Supports decimal format.

Answer 10

R, 62 46 42 bytes

Anonymous function that takes string a and decimal n, prints output to stdout.

pryr::f(cat(a,rep(")",n*nchar(a)),sep=""))

Answer 11

Pyth, 9 bytes

*s*lpzE")

Takes two lines of input: string and ratio (decimal).

Try it on pyth.herokuapp.com

Explanation

A denotes a function's first argument, B its second argument.

*s*lpzE")
    pz     # print the input string
   lAA     # take the length of the printed string
      E    # read the next line of input (the emphasis ratio)
  *AAAB    # multiply the length by the ratio
 sAAAAA    # floor the result
*AAAAAA")  # repeat ")" n times
           # implicit print

Answer 12

TI-Basic, 33 bytes

Takes decimal input.

Prompt Str1,A
")
For(I,0,9
Ans+Ans
End
Str1+sub(Ans,1,AI

Answer 13

Perl 5, 29 bytes

sub{($_=pop).')'x(y///c*pop)}

(Number is first arg, string is second.)

Try it online!

Answer 14

CJam, 9 bytes

l_,ld*')*

Try it online!

Input string on the first line, emphasis ratio in range 0 to 5 on the second.

Explanation

l    e# Read input string.
_,   e# Duplicate, get length.
ld   e# Read emphasis ratio.
*    e# Multiply by length.
')*  e# Get that many parentheses.

Answer 15

MATL, 11 10 8 bytes

yn*:"41h

This solution uses the decimal form of the second input

Try it online!

Explanation

        % Implicitly grab first input as a string
        % Implicitly grab the second input as a number
y       % Make a copy of the first input
n       % Compute the length of the string
*       % Multiply the decimal by the length to determine the # of )'s (N)
:       % Create the array [1...N]
"       % For each element in this array
  41    % Push 41 to the stack (ACSII for ")")
  h     % Horizontally concatenate this with the current string
        % Implicit end of for loop and display

Answer 16

sB~, 17 bytes

i\,N?\;')'*(N*l(\

Explained:

i\,N    input a string and a number
?\;     print the string
')'*    also print ) multiplied by...
(N*l(\  the number times the string length.

Parentheses are closed automatically

Here's the output of the compiler, if you're interested:

 INPUT  S$ ,N? S$ ;")"*(N* LEN(  S$ ))

This version of the compiler was written on 1/27/2017 at 11:12 pm, which might have been a few minutes after this question was posted. So here's a version which works on the oldest version of the compiler, written an hour earlier: iS$,N?S$;')'*(N*l(S$)) (22 bytes)

Answer 17

PostgreSQL, 102 bytes

create function q(text,int)returns text as $$select rpad($1,(100+$2)*length($1)/100,')')$$language sql

Details

Uses the integer input format.

This simply right-pads the input string with parens out to the target length.

create function q(text,int)
returns text as $$
    select rpad($1,             -- Pad the string input
        (100 + $2) *            -- to 100 + int input % ...
        length($1) / 100,       -- ...of the input string
        ')')                    -- with ) characters
$$ language sql

Called with

select q('codegolf', 125), q('codegolf', 75);
select q('noob team omg', 50), q('hi!', 499);

Answer 18

Bash + coreutils, 45 bytes

echo $1`seq -s\) $[${#1}*$2/100+1]|tr -cd \)`

Try it online!

Integer input.

Answer 19

Groovy, 27 bytes

Straightforward solution

{s,r->s+')'*(s.length()*r)}

Test program :

def f = {s,r->s+')'*(s.length()*r)}

println f("hi!", 4.99)
println f("noob team omg", 0.5)

Answer 20

Rebol, 39 bytes

func[a b][append/dup a")"b * length? a]

Answer 21

Clojure, 40 bytes

Quite boring solution :

#(reduce str %(repeat(*(count %)%2)")"))

Just reduces str function on a list of closing parentheses with a string as initial parameter.

See it online : https://ideone.com/5jEgWS

Not-so-boring solution (64 bytes) :

#(.replace(str(nth(iterate list(symbol %))(*(count %)%2)))"(""")

Converts input string to a symbol (to get rid of quotes) and repeatedly applies function list on it generating infinite sequence like this: (a (a) ((a)) (((a))) ... ). Takes nth element converts it to string and replaces all opening parentheses with nothing.

See it online : https://ideone.com/C8JmaU

Answer 22

SimpleTemplate, 92 bytes

Takes the string as the first parameter and the "ratio" as the second.
The ratio is between 0 and 5, with 2 decimal places.

{@echoargv.0}{@callstrlen intoL argv.0}{@set*Y argv.1,L}{@callstr_repeat intoO")",Y}{@echoO}

As you can see, it is non-optimal.
The 2 {echo} there could be reduced to 1.
Due to a bug in the compiler, this code can't be reduced much further.

---

Ungolfed:

{@echo argv.0}
{@call strlen into length argv.0}
{@set* ratio argv.1, length}
{@call str_repeat into parenthesis ")", ratio}
{@echo parenthesis}

---

If no bug existed, the code would look like this, 86 bytes:

{@callstrlen intoL argv.0}{@set*Y argv.1,L}{@callstr_repeat intoO")",Y}{@echoargv.0,O}

Answer 23

C# Interactive, 77 67 bytes

string r(string s,int p)=>s+new string(')',(int)(s.Length*p/100d));

C# interactive is sweet.

Answer 24

Stax, 7 bytes

é┴eó¡µf

Run and debug it

Answer 25

International Phonetic Esoteric Language, 24 bytes

A reimplementation of the old answer into the new specification. Input is as a positive integer first, then the string.

ɪ{100}viħɖf0ɑ")"x1esøɒʕo

Explanation:

ɪ{100}viħɖf0ɑ")"x1esøɒʕo
ɪ                        (push input int)
 {100}                   (push 100)
      v                  (divide int//100)
       iħ                (push input str, push len)
         ɖ               (rotate top 3 clockwise)
          f              (multiply int//100 * len)
           0             (push 0)
            ɑ            (begin loop, from 0 to int//100 * len)
             ")"         (push ")")
                x        (concat)
                 1esø    (increment index)
                     ɒ   (end loop)
                      ʕ  (list to str)
                       o (print)

---

International Phonetic Esoteric Language, 18 bytes (WIP language) (OLD)

I discovered some bugs in my interpreter because of this challenge. Takes input as string then integer.

iɢ291tʃɪðθœ<)>ɲqɶo

No TIO interpreter yet, but is runnable by cloning the repository above, and calling python3 main.py "code here".

iɢ291tʃɪðθœ<)>ɲqɶo
i                  ; push string input
 ɢ                 ; peek, push string length
  291tʃ            ; push (1 + 9)^2
       ɪ           ; push number input
        ðθ         ; push [num / 100 * len]
          œ        ; start loop: pop, run ceil(n) times
           <)>     ; push string ")"
              ɲ    ; swap top 2 elements of the stack
               q   ; pop, pop, push concatenated strings
                ɶ  ; end loop
                 o ; output

Sample cases:

python3 main.py "iɢ291tʃɪðθœ<)>ɲqɶo"
codegolf
125
codegolf))))))))))

python3 main.py "iɢ291tʃɪðθœ<)>ɲqɶo"
iɢ291tʃɪðθœ<)>ɲqɶo
300
iɢ291tʃɪðθœ<)>ɲqɶo))))))))))))))))))))))))))))))))))))))))))))))))))))))

python3 main.py "iɢ291tʃɪðθœ<)>ɲqɶo"
less than 1.00
50
less than 1.00)))))))

Answer 26

SmileBASIC, 29 bytes

INPUT S$,N?S$;")"*(LEN(S$)*N)

Answer 27

Gol><> (Golfish), 17 bytes

i:a=?v
R*Il~/Hr)`

Try it here.

The top line reads characters (i) until it finds a newline (ASCII 10, a), then goes down (v).

Then we discard one character (the newline) with ~, push the length of the stack (l), read a float (I), multiply the two, and repeatedly (R) push the character ")" that many times. Finally, reverse the stack (r), output it and halt (H).

Answer 28

PHP, 50 bytes

<?=str_pad($s=$argv[1],strlen($s)*++$argv[2],")");

takes string and decimal number as command line arguments; cuts padding. Run with -r;

breakdown

<?=                     // print ...
str_pad(                    // pad
    $s=$argv[1],            // string=argument 1
    strlen($s)*++$argv[2],  // to string length*(1+argument 2) 
    ")"                     // using ")" as padding string
);

Answer 29

Ruby, 25 bytes

->(s,n){s+')'*(s.size*n)}

I'm using lambdas. The test program would be something like:

f=->(s,n){s+')'*(s.size*n)}
f.("codegolf", 1.5)        # => "codegolf))))))))))))"
f.("hi!", 4.99)            # => "hi!))))))))))))))"

Answer 30

GNU AWK, 59 bytes

{t=sprintf("%"n*length(s)"s","");gsub(/ /,")",t);print s t}

Accepts arguments on command line (using the decimal form) like so:

: | awk -v s="codegolf" -v n=0.75 -f russianify.awk

Yes, AWK requires something to be attached to stdin, even if that something is 0 bytes returned by the no-op shell builtin. You could also use echo | awk ..., or really anything that doesn't contain a newline.