# Output subdivisions of international standard paper sizes

ISO Paper Sizes Defined:

The A series paper sizes are defined by the following requirements:

The length divided by the width is the square root of 2.
The A0 size has an area of 1 unit.
Each subsequent size A(n) is defined as A(n-1) cut in half parallel to its shorter sides. given an input f[n] output A0 divided into n subdivisions.

Test cases:

f to f: Here, A0 is given by f, but this indexing isn't essential.

Winning criteria:

The shortest code in bytes wins.

• Shouldn't f be an A0 with a horizontal line dividing it? i.e., isn't the f in the test case actually f? Dec 18 '16 at 1:35
• @JungHwanMin adjusted now Dec 18 '16 at 2:15

## JavaScript (ES6) + HTML, 96 94 + 34 = 130 128 bytes

f=(n,w=297,h=210)=>n--&&f(n,h<w?w/2:w,h<w?h:h/2,(C=c.getContext2d).rect(0,0,w,h),C.stroke())

f(8)
<canvas id=c width=300 height=300>

# Mathematica, 87 85 bytes

Thanks @martin for 1 byte.

Graphics@{EdgeForm@Thin,White,Rectangle[#,0{,}]&/@NestList[Sort[#/a]&,{1,a=√2},#]}&

• Very nice! EdgeForm@Thin: -1 byte Dec 18 '16 at 2:21

## JavaScript (ES6)/SVG (HTML5), 170 bytes

a=prompt();document.write('<svg width=297 height=210>');for(w=297,h=210;a--;h>w?h/=2:w/=2)document.write(<rect fill=none stroke=#000 x=0 y=0 width=${w} height=${h} />);

Uses 1-based indexing.

# BBC BASIC 49 ASCII characters

Tokenised filesize 44 bytes

I.n:F.i=0TOn:RECTANGLE0,0,1189>>i/2+.5,841>>i/2N.


Much shorter than before! I always forget about the bitshift operators in BBC BASIC for windows as they weren't available on my old computer back in the day.

# BBC BASIC 63 ASCII characters

Tokenised filesize 58 bytes

A%=841C%=1189d=4I.n:F.i=0TOn:RECTANGLE0,0,C%,A%:d!^B%/=2d=-d:N.


Uses zero indexing, which I prefer. Thus 0 outputs the paper for A0, 1 outputs A0 divided into a pair of A1s, etc.

It is necessary to alternate between halving the X and Y coordinates, but doing that in an array would have cost too many bytes. Instead I use the fact that BBC basic has a block of static integer variables A%..Z% of 4 bytes each stored in contiguous memory. I store the X and Y values in A% and C% and access using the pointer to %B modified by the value of d, which alternates between 4 and -4.

Ungolfed

  A%=841
C%=1189
d=4
INPUTn
FORi=0TOn
RECTANGLE0,0,C%,A%
d!^B%/=2
d=-d
NEXT


Output 