17
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I've been working on this iOS app recently and I encountered a (rather easily solved) problem: How do I determine if my string is comprised only of emojis?

Well, that's your job today!

Input

A string. If the presence of unicode characters is problematic for you then you may use a different reasonable format. Please state what you do if you do something different from a regular string for taking input.

Output

Print or return a truthy value if the input string contains only emojis, and a falsey value if it contains any characters other than emojis.

Wait a sec... what's an emoji? ๐Ÿ˜…

An emoji is a character that falls in these ranges:

0x1F600...0x1F64F  // Emoticons
0x1F300...0x1F5FF  // Misc Symbols and Pictographs
0x1F680...0x1F6FF  // Transport and Map
0x2600...0x26FF    // Misc symbols
0x2700...0x27BF    // Dingbats
0xFE00...0xFE0F    // Variation Selectors

(I think)

This is ๐Ÿ”น๐Ÿ”น, so shortest code in bytes winsโ•

Test cases

"Is it an emoji? ๐Ÿค”" -> False
"๐Ÿ”นcode-golf๐Ÿ”น" -> False
"๐Ÿ˜ฎ ๐Ÿ˜ฅ ๐Ÿ˜จ ๐Ÿ˜ฉ ๐Ÿ˜ช" -> False
"I have no fancy emojis :(" -> False

"๐Ÿ˜Ž" -> True
"๐Ÿ˜Š๐Ÿ˜˜" -> True

For you poor souls who cannot see emojis, here is an image of the test cases.

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  • 2
    \$\begingroup\$ Perhaps include a version (maybe an image) for those who can't see emojis? ;-) \$\endgroup\$ – ETHproductions Dec 7 '16 at 0:10
  • \$\begingroup\$ @ETHproductions, do you suggest I link to a photo of the test cases or something else? \$\endgroup\$ – Daniel Dec 7 '16 at 0:12
  • \$\begingroup\$ Well, there are emojis spread throughout the whole question, but I guess the only really important ones are in the test cases, so an image of just the test cases will work. \$\endgroup\$ – ETHproductions Dec 7 '16 at 0:14
  • \$\begingroup\$ @ETHproductions, I added a link to a photo of the test cases \$\endgroup\$ – Daniel Dec 7 '16 at 0:22
  • \$\begingroup\$ Can input be a numeric array of Unicode code points? Also, what range of characters/numbers can the input contain? \$\endgroup\$ – Luis Mendo Dec 7 '16 at 0:24
2
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Ruby, 61 56+1 = 62 57 47 bytes

Uses the -n flag and takes input from STDIN. Prints 0 for truthy and nil for falsy.

-5 bytes because for some reason I initially thought the regex solution would not work???

-10 bytes from NieDzejkob for noticing a code point overlap that I missed :o

p$_=~/^[๐ŸŒ€-๐Ÿ™๐Ÿš€-๐Ÿ›ฟโ˜€-โžฟ๏ธ€-๏ธ€๏ธ]*$/

Try it online!

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  • 1
    \$\begingroup\$ 47 bytes if you merge two ranges in the regex. \$\endgroup\$ – NieDzejkob Dec 11 '17 at 19:40
  • 1
    \$\begingroup\$ That's 47 isn't it? \$\endgroup\$ – Asone Tuhid Jan 22 '18 at 9:24
  • \$\begingroup\$ Yeah I forgot to update the score after getting the suggestion from @NieDzejkob \$\endgroup\$ – Value Ink Jan 25 '18 at 9:25
10
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Emojicode, 179 bytes

๐Ÿ‡a๐Ÿจ๐Ÿš๐Ÿš‚โžก๐Ÿš‚๐Ÿ”‚n๐Ÿกa๐Ÿ‡๐ŸŠ๐ŸŽ‰๐ŸŽ‰โ—€n 9728๐ŸŽŠโ–ถn 10175โ—€n 65024๐ŸŽ‰๐ŸŽ‰๐ŸŽŠโ–ถn 65039โ—€n 127744๐ŸŽŠโ–ถn 128591โ—€n 128640โ–ถn 128767๐Ÿ‡๐ŸŽ0๐Ÿ‰๐Ÿ‰๐ŸŽ1๐Ÿ‰

A callable that takes a list of integers representing the codepoints and returns 1 or 0.

Try it online!

Emojicode, 187 bytes

๐Ÿ‡a๐Ÿ”กโžก๐Ÿ‘Œ๐Ÿ”‚i๐Ÿกa๐Ÿ‡๐Ÿฆn๐Ÿš‚i๐ŸŠ๐ŸŽ‰๐ŸŽ‰โ—€n 9728๐ŸŽŠโ–ถn 10175โ—€n 65024๐ŸŽ‰๐ŸŽ‰๐ŸŽŠโ–ถn 65039โ—€n 127744๐ŸŽŠโ–ถn 128591โ—€n 128640โ–ถn 128767๐Ÿ‡๐ŸŽ๐Ÿ‘Ž๐Ÿ‰๐Ÿ‰๐ŸŽ๐Ÿ‘๐Ÿ‰

A callable that takes a string and returns a boolean.

Try it online!

Ungolfed and explained

๐Ÿ‘ด A callable that takes a ๐Ÿ”ก called input and returns a ๐Ÿ‘Œ
๐Ÿ‡ input ๐Ÿ”ก โžก ๐Ÿ‘Œ
 ๐Ÿ‘ด For each character in input
 ๐Ÿ”‚ character ๐Ÿก input ๐Ÿ‡
  ๐Ÿ‘ด Create a frozen called n containing the unicode codepoint of character
  ๐Ÿฆ n ๐Ÿš‚ character
  ๐Ÿ‘ด If the value is in one of specific ranges, return ๐Ÿ‘Ž (if the current character is not an emoji)
  ๐ŸŠ๐ŸŽ‰๐ŸŽ‰โ—€n 9728๐ŸŽŠโ–ถn 10175โ—€n 65024๐ŸŽ‰๐ŸŽ‰๐ŸŽŠโ–ถn 65039โ—€n 127744๐ŸŽŠโ–ถn 128591โ—€n 128640โ–ถn 128767๐Ÿ‡
   ๐ŸŽ ๐Ÿ‘Ž
  ๐Ÿ‰
 ๐Ÿ‰
 ๐Ÿ‘ด Since we're here, all characters are an emoji, so return ๐Ÿ‘
 ๐ŸŽ๐Ÿ‘
๐Ÿ‰

Try it online!

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1
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JavaScript, 83 61 bytes

-22 bytes thanks to @Shaggy

s=>(s.match(/\ud83d[\ude00-\ude4f]/g)||"").length==s.length/2

Demo

f=s=>(s.match(/\ud83d[\ude00-\ude4f]/g)||"").length==s.length/2

document.writeln(f("๐Ÿ”นcode-golf๐Ÿ”น")) //false
document.writeln(f("๐Ÿ˜ฎ ๐Ÿ˜ฅ ๐Ÿ˜จ ๐Ÿ˜ฉ ๐Ÿ˜ช")) //false
document.writeln(f("I have no fancy emojis :(")) //false
document.writeln(f("๐Ÿ˜Ž")) //true
document.writeln(f("๐Ÿ˜Š๐Ÿ˜˜")) //true

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  • 1
    \$\begingroup\$ 61 bytes: s=>(s.match(/\ud83d[\ude00-\ude4f]/g)||"").length==s.length/2 \$\endgroup\$ – Shaggy Aug 15 '17 at 15:46
  • \$\begingroup\$ Uh, how does this work? The regex doesn't specify the codepoints of any emoji... \$\endgroup\$ – NieDzejkob Dec 11 '17 at 19:40
  • \$\begingroup\$ @NieDzejkob I believe JS uses UTF-16 for Unicode, so I guess these are the UTF-16 byte representations of those codepoints. The answer is incomplete though, it fails for ๐Ÿ›‚๐Ÿš€, โ™”โ˜บโ˜ , ๐Ÿ๐ŸŽ…๐ŸŒ etc., all of which should be truthy. It seems to check only for one range out of the six that OP mentions. \$\endgroup\$ – sundar Jul 10 '18 at 20:30
1
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Python, 87 bytes

lambda x:re.match('^[๐Ÿ˜€-๐Ÿ™๐ŸŒ€-๐Ÿ—ฟ๐Ÿš€-๐Ÿ›ฟโ˜€-โžฟ๏ธ€-๏ธ€๏ธ]*$',x)and 1
import re

Try it online!

Returns 1 as truthy value and None as falsy value.

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  • \$\begingroup\$ I "borrowed" your regex, hope you don't mind ;) \$\endgroup\$ – HyperNeutrino Aug 15 '17 at 18:29
  • \$\begingroup\$ Since I told Value Ink about it, I'll tell you too - the first two groups in the regex can be merged because of adjacent codepoints: ๐ŸŒ€-๐Ÿ™ \$\endgroup\$ – NieDzejkob Dec 11 '17 at 19:42
1
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Proton, 54 bytes

map(/[๐ŸŒ€-๐Ÿ™๐Ÿš€-๐Ÿ›ฟโ˜€-โžฟ๏ธ€-๏ธ€๏ธ]/.match)+all

Try it online!

-9 bytes (3 chars) thanks to NieDzejkob

"Borrowing" Uriel's regex :P This is shorter thanks to Proton's obscure features and regex literals

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0
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QuadR, 47 bytes

''โ‰กโต
[๐ŸŒ€-๐Ÿ™๐Ÿš€-๐Ÿ›ฟโ˜€-โžฟ๏ธ€-๏ธ€๏ธ]

Try it online!

Isโ€ฆ

โ€ƒ''โ‰กโตโ€ƒan empty string identical to the result whenโ€ฆ

โ€ƒ[๐ŸŒ€-๐Ÿ™๐Ÿš€-๐Ÿ›ฟโ˜€-โžฟ๏ธ€-๏ธ€๏ธ]โ€ƒall emojis areโ€ฆ

โ€ƒโ€ƒreplaced with nothing

?

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