7
\$\begingroup\$

Today your goal is to invent URL compression. You must write two programs: a compressor and a decompressor.

  • The compressor will be called with one URL on stdin and its output will be read on stdout.

  • The decompressor will be called with the output of the compressor on stdin, and must produce the exact URL passed into the compressor to stdout.

  • The sum of the size in bytes of the compressor and decompressor source may be at most 1024 bytes.

  • Your answer must come with command line instructions to run your two programs. You're not allowed to pass in information of any kind through command line arguments - they should merely be to run the program.

The standard loopholes are not allowed. Additionally, your program is not allowed to keep and use any state of any kind between executions, not in files, environment variables, etc. Lastly, you may not use any built-in data compression routines if your language has them.

Scoring

I have taken all URLs found in the StackExchange dump of PPCG and collected them in one file, one URL per line. Your score will be the sum of the size of all compressed URLs in that file. Lowest score wins.


It is not guaranteed that your program is called with a valid URL. Your program must work for every input found in the test file, but doesn't have to work for any other input.

Your answer only has to work for the given URLs, and only has to optimize for those.

\$\endgroup\$
11
  • 2
    \$\begingroup\$ The sentences in the last paragraph seem to contradict each other: everything in the test file seems to be a valid URL. \$\endgroup\$ Commented Apr 7, 2015 at 0:46
  • 1
    \$\begingroup\$ @NinjaBearMonkey That's not a contradiction, just coincidence. I did not check the file. It might very well only contain URLs, but if it contains something that's not an URL you should still be able to handle it. \$\endgroup\$
    – orlp
    Commented Apr 7, 2015 at 7:50
  • 2
    \$\begingroup\$ I think there is a little contradiction with kolmogorov-complexity and the loopholes: The loopholes state that you cannot optimize your code for the test cases. This means we cannot just replace e.g. 'codegolf.stackexchange.com/', which would be a nice thing to have for a kolmogorov complexity challenge. Can you give us more detail on what the rules are relating to that? \$\endgroup\$
    – flawr
    Commented Apr 8, 2015 at 14:54
  • 1
    \$\begingroup\$ Various compression software on my computer cannot compress it any further than 126k, so I'm really eager to see if anyone can get less than that. \$\endgroup\$
    – Sanchises
    Commented Apr 8, 2015 at 19:55
  • 1
    \$\begingroup\$ @orlp: You should change the clause to: You may assume that the input is always valid and can be found in the dump file. It's less confusing that way. \$\endgroup\$ Commented Apr 9, 2015 at 2:47

4 Answers 4

9
\$\begingroup\$

CJam 308954 268306 bytes

Compressor (511 bytes)

0000000: 22 2f 25 2d 30 31 32 33 35 61 65 0a 2e 34 37 38  "/%-01235ae..478
0000010: 39 62 63 66 67 69 6c 6d 70 73 74 75 0a 36 41 42  9bcfgilmpstu.6AB
0000020: 43 44 45 46 49 4a 4b 4c 4d 53 58 5f 64 68 6a 6b  CDEFIJKLMSX_dhjk
0000030: 6e 6f 72 76 77 78 79 7a 97 a0 a5 a6 22 0a 4e 2f  norvwxyz....".N/
0000040: 5f 3a 2b 32 35 36 63 2c 5e 61 2b 3a 47 3b 22 63  _:+256c,^a+:G;"c
0000050: 6f 7f 6d 73 74 6e 67 6f 6c 6f 72 64 65 7f 85 83  o.mstngolorde...
0000060: 66 67 87 86 88 81 61 8a 63 8b 6b 61 82 80 2f 2e  fg....a.c.ka../.
0000070: 8e 65 8f 8d 90 68 91 63 92 78 93 65 94 8c 95 65  .e...h.c.x.e...e
0000080: 72 6f 6e 84 67 77 69 9a 6b 9b 69 74 68 96 61 69  ron.gwi.k.ith.ai
0000090: 98 69 6e 65 74 6e a1 65 6e 64 69 25 32 a5 30 a6  .inetn.endi%2.0.
00000a0: a6 77 77 a8 77 6c 65 72 65 2e 99 ac 2f ad 9c 9f  .ww.wlere.../...
00000b0: 73 81 af 89 2e b1 9e b1 96 65 a4 70 b4 9c b5 72  s........e.p...r
00000c0: 69 a5 42 b7 70 b9 74 62 8f b6 61 bc ae 61 72 b2  i.B.p.tb..a..ar.
00000d0: 2f 61 74 6c 6f 61 6d 74 6d 68 c3 c4 6c 65 b0 75  /atloamtmh..le.u
00000e0: c6 71 c7 b3 c8 63 ba 73 ca 88 cb 72 6f 61 6e 69  .q...c.s...roani
00000f0: 9d cf 75 d0 bb 67 d1 65 73 75 73 d4 97 b3 d5 6a  ..u..g.esus....j
0000100: c2 63 d7 c1 77 d9 8f 70 68 db bb 70 dc 73 75 74  .c..w..ph..p.sut
0000110: de a4 df 61 e0 98 90 85 e2 69 e3 d3 83 e5 8d a9  ...a.....i......
0000120: 2e 61 dd 76 97 6f e9 8c ea eb 66 ec da 6a 73 ee  .a.v.o....f..js.
0000130: 66 ef 69 f0 64 f1 64 f2 aa 70 cd a2 2f 2e f5 f3  f.i.d.d..p../...
0000140: f6 e1 f6 e6 73 f9 ae 61 6c 75 6e bf 34 70 79 fe  ....s..alun.4py.
0000150: 9d 63 74 fc 00 b8 b8 75 72 03 8f a5 43 64 6f 06  .ct....ur...Cdo.
0000160: 63 d6 73 ed c8 a7 a7 b8 a6 a6 a5 69 73 72 c2 75  c.s........isr.u
0000170: 74 69 82 bd 2f 2e 11 a3 12 67 49 14 43 15 41 16  ti../....gI.C.A.
0000180: 16 a3 74 07 73 72 fc d2 0d 69 74 2e c5 63 68 61  ..t.sr...it..cha
0000190: 73 e8 3f 20 63 5c 22 3d be 1e 6f 03 69 aa a5 39  s.? c\"=..o.i..9
00001a0: 60 a5 6f 66 22 32 2f 31 32 39 2c 31 32 37 66 2b  `.of"2/129,127f+
00001b0: 33 33 2c 2b 3a 63 22 5c 22 3c 3e 5c 5e 60 7b 7d  33,+:c"\"<>\^`{}
00001c0: 22 2b 6c 5f 34 3d 27 73 3d 3a 4c 37 2b 3e 40 7b  "+l_4='s=:L7+>@{
00001d0: 2f 5c 28 40 5c 2a 7d 2f 30 5c 7b 47 7b 31 24 23  /\(@\*}/0\{G{1$#
00001e0: 29 7d 23 5f 47 3d 3a 54 40 23 40 54 2c 2a 2b 34  )}#_G=:T@#@T,*+4
00001f0: 2a 2b 7d 2f 32 2a 4c 2b 32 35 36 62 3a 63 0a     *+}/2*L+256b:c.

Decompressor (510 bytes)

0000000: 22 2f 25 2d 30 31 32 33 35 61 65 0a 2e 34 37 38  "/%-01235ae..478
0000010: 39 62 63 66 67 69 6c 6d 70 73 74 75 0a 36 41 42  9bcfgilmpstu.6AB
0000020: 43 44 45 46 49 4a 4b 4c 4d 53 58 5f 64 68 6a 6b  CDEFIJKLMSX_dhjk
0000030: 6e 6f 72 76 77 78 79 7a 97 a0 a5 a6 22 0a 4e 2f  norvwxyz....".N/
0000040: 5f 3a 2b 32 35 36 63 2c 5e 61 2b 3a 47 3b 22 63  _:+256c,^a+:G;"c
0000050: 6f 7f 6d 73 74 6e 67 6f 6c 6f 72 64 65 7f 85 83  o.mstngolorde...
0000060: 66 67 87 86 88 81 61 8a 63 8b 6b 61 82 80 2f 2e  fg....a.c.ka../.
0000070: 8e 65 8f 8d 90 68 91 63 92 78 93 65 94 8c 95 65  .e...h.c.x.e...e
0000080: 72 6f 6e 84 67 77 69 9a 6b 9b 69 74 68 96 61 69  ron.gwi.k.ith.ai
0000090: 98 69 6e 65 74 6e a1 65 6e 64 69 25 32 a5 30 a6  .inetn.endi%2.0.
00000a0: a6 77 77 a8 77 6c 65 72 65 2e 99 ac 2f ad 9c 9f  .ww.wlere.../...
00000b0: 73 81 af 89 2e b1 9e b1 96 65 a4 70 b4 9c b5 72  s........e.p...r
00000c0: 69 a5 42 b7 70 b9 74 62 8f b6 61 bc ae 61 72 b2  i.B.p.tb..a..ar.
00000d0: 2f 61 74 6c 6f 61 6d 74 6d 68 c3 c4 6c 65 b0 75  /atloamtmh..le.u
00000e0: c6 71 c7 b3 c8 63 ba 73 ca 88 cb 72 6f 61 6e 69  .q...c.s...roani
00000f0: 9d cf 75 d0 bb 67 d1 65 73 75 73 d4 97 b3 d5 6a  ..u..g.esus....j
0000100: c2 63 d7 c1 77 d9 8f 70 68 db bb 70 dc 73 75 74  .c..w..ph..p.sut
0000110: de a4 df 61 e0 98 90 85 e2 69 e3 d3 83 e5 8d a9  ...a.....i......
0000120: 2e 61 dd 76 97 6f e9 8c ea eb 66 ec da 6a 73 ee  .a.v.o....f..js.
0000130: 66 ef 69 f0 64 f1 64 f2 aa 70 cd a2 2f 2e f5 f3  f.i.d.d..p../...
0000140: f6 e1 f6 e6 73 f9 ae 61 6c 75 6e bf 34 70 79 fe  ....s..alun.4py.
0000150: 9d 63 74 fc 00 b8 b8 75 72 03 8f a5 43 64 6f 06  .ct....ur...Cdo.
0000160: 63 d6 73 ed c8 a7 a7 b8 a6 a6 a5 69 73 72 c2 75  c.s........isr.u
0000170: 74 69 82 bd 2f 2e 11 a3 12 67 49 14 43 15 41 16  ti../....gI.C.A.
0000180: 16 a3 74 07 73 72 fc d2 0d 69 74 2e c5 63 68 61  ..t.sr...it..cha
0000190: 73 e8 3f 20 63 5c 22 3d be 1e 6f 03 69 aa a5 39  s.? c\"=..o.i..9
00001a0: 60 a5 6f 66 22 32 2f 5b 71 32 35 36 62 32 6d 64  `.of"2/[q256b2md
00001b0: 22 68 74 74 70 22 6f 27 73 2a 6f 22 3a 2f 2f 22  "http"o's*o"://"
00001c0: 6f 7b 34 6d 64 47 3d 5f 2c 40 5c 6d 64 40 3d 5c  o{4mdG=_,@\md@=\
00001d0: 7d 68 3b 5d 57 25 31 32 39 2c 31 32 37 66 2b 33  }h;]W%129,127f+3
00001e0: 33 2c 2b 3a 63 22 5c 22 3c 3e 5c 5e 60 7b 7d 22  3,+:c"\"<>\^`{}"
00001f0: 2b 57 25 7b 2f 5c 29 40 5c 2a 7d 2f 4e 0a        +W%{/\)@\*}/N.

Algorithm

  1. Strip the <scheme>:// part from the URL.

  2. Replace character pairs by unused code points in the 0 - 255 range.

    This uses a static dictionary which is included in the source code.

  3. Use arithmetic encoding on the modified input string.

    To comply with the source code size limit, this is done by splitting the 256 code points into 4 groups and pretending the groups and the code points in a fixed group have equal probabilities.

  4. Append a bit indicating the scheme to the resulting integer.

  5. Convert the integer into a string.

Test cases

Create the source code files.

$ xxd -p -r > comp.cjam <<< 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

$ xxd -p -r > decomp.cjam <<< 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

Verify their integrity.

$ cksum comp.cjam decomp.cjam
2293013588 511 comp.cjam
1577103568 510 decomp.cjam

Download the CJam interpreter.

$ wget -q wget http://downloads.sourceforge.net/project/cjam/cjam-0.6.4/cjam-0.6.4.jar

Create an alias for running the interpreter.

$ alias cjam='java -jar cjam-0.6.4.jar'

Set encoding to ISO-8859-1 to store each character as a single byte.

$ LANG=en_US

Prepare the test file.

$ wget -q https://gist.githubusercontent.com/orlp/fd3411259469ade4c65d/raw/bb6b088c18c444d28729abc870d6076ca594a6de/urls.txt

$ echo >> urls.txt

For each line in the test file, feed the URL to the compressor, append the output to urls-comp.bin and feed it back to the decompressor. Save the combined output of all decompressions in urls-vrfy.txt. This will take a few minutes.

$ >urls-comp.bin

$ for URL in $(<urls.txt); do
> echo $URL | cjam comp.cjam | tee -a urls-comp.bin | cjam decomp.cjam
> done > urls-vrfy.txt

Verify that all URLs were decoded appropriately.

$ cksum urls.txt urls-vrfy.txt
3445245739 588562 urls.txt
3445245739 588562 urls-vrfy.txt

Compute the score.

$ wc -c urls-comp.bin
268306 urls-comp.bin

How it works

Common

Push the string containing the first three character groups.

"/%-01235ae
.4789bcfgilmpstu
6ABCDEFIJKLMSX_dhjknorvwxyz����"

Split at linefeeds, flatten a copy of the resulting array and compute the symmetric difference of the resulting string and the string of all code points.

N/_:+256c,^

Append the result to the array which now contains all four character groups. Save the result in the variable G and discard it from the stack.

a+:G;

Push the array (let's call it A) containing all character pairs to be substituted.

"comstngolorde��fg����a�c�ka��/.�e���h�c�x�e���eron�gwi�k�ith�ai�inetn�endi%2�0��ww�wlere.��/���s���.����e�p���ri�B�p�tb��a��ar�/atloamtmh��le�u�qdz�c�sʈ�roani��uлg�esusԗ��j�c��wُphۻp�sutޤ�a���i�Ӄit.�chas�? c\"=�oi��9`�of"
2/

Push the array [ 0 ... 128 ], add 127 to each element, append the array [ 0 ... 32 ], cast to Char and append the string "\"<>\^{}". The result is the string (let's call itS`) of all unused code points from 0 to 255.

129,127f+33,+:c"\"<>\^`{}"+

Compressor

...        " Generate G. Push A and S.                                        ";
l          " Read one line from STDIN.                                        ";
_4='s=     " Check if its 5th character is an 's'.                            ";
:L7+       " Save the result in L and add it to 7.                            ";
>          " Discard that many characters from the input string.              ";
@{         " For each character pair in A:                                    ";
  /        "   Split the input string at its occurrences.                     ";
  \(@\     "   Unshift one character C from S.                                ";
  *        "   Join the split string, using C as separator.                   ";
}/         "                                                                  ";
0          " Push 0 (accumulator).                                            ";
\{         " For each character C in the input string:                        ";
  G{1$#)}# "   Retrieve the index of the group C belongs to.                  ";
  _G=:T    "   Store the group in T.                                          ";
  @#       "   Push the index of C in T.                                      ";
  @T,*+4*+ "   Multiply the accumulator by the length of T and add the index. ";
}/         "                                                                  ";
2*L+       " Multiply the accumulator by 2 and add L.                         ";
256b:c     " Convert the accumulator (BigInteger) into a byte string.         ";

Decompressor

...        " Generate G. Push A.                                              ";
[q         " Start an array and read the whole input.                         ";
256b       " Convert the byte string into an integer.                         ";
2md        " Push quotient and residue of the division by 2.                  ";
"http"o    " Print 'http'.                                                    ";
's*o       " If the residue is 1, print 's'.                                  ";
"://"o     " Print '://'.                                                     ";
{          " While the integer is non-zero:                                   ";
  4md      "   Push quotient and residue of the division by 4.                ";
  G=_,     "   Push the corresponding character group and its length.         ";
  @\md     "   Divide the integer by the length. Push quotient and residue.   ";
  @=\      "   Retrieve the char corresponding to the residue from the group. ";
}h         "                                                                  ";
]W%        " End and reverse array.                                           ";
           " Since the elements are Chars, this yields a string.              ";
...        " Push S.                                                          ";
\W%{       " For each character in S reversed:                                ";
  /        "     Split the string at its occurrences.                         ";
  \)@\     "     Pop one character pair P from A.                             ";
  *        "     Join the split string, using P as separator.                 ";
}/         "                                                                  ";
N          " Push a linefeed.                                                 ";

Remarks

Decompression will work correctly only for the http and https schemes. The reasons are twofold:

  • The http part is hardcoded.

  • The arithmetic encoding uses the fact that <http|https>:// cannot be followed by a third slash.

    Since the integer 0 encodes any arbitrary run of slashes (character 0 of group 0), we would have to store the URL's length or the number of leading slashes to support, e.g., file:/// URLs.

\$\endgroup\$
1
  • \$\begingroup\$ Impressive! and i appreciate the detailed explaination \$\endgroup\$
    – Moogie
    Commented Apr 10, 2015 at 6:38
7
\$\begingroup\$

BrainFuck: 550417

Encoder:

,,,,,[.,]

Decoder:

>++++++++++[-<++++++++++>]<++++.++++++++++++..----[.,]

It needs the url without linefeed and it expects 0 as EOF.

Example:

> echo -n "http://stackoverflow.com/" | beef encode.bf 
://stackoverflow.com/
> echo -n "://stackoverflow.com/" | beef decode.bf 
http://stackoverflow.com/
\$\endgroup\$
3
  • 3
    \$\begingroup\$ A novel abuse. I'm not sure whether or not to applaud. \$\endgroup\$ Commented Apr 7, 2015 at 21:27
  • \$\begingroup\$ Does it work with https? \$\endgroup\$ Commented Apr 8, 2015 at 9:33
  • \$\begingroup\$ @IsmaelMiguel Yes. As required it works with all the URLs in the list. https://x.org becomes s://x.org \$\endgroup\$
    – Sylwester
    Commented Apr 8, 2015 at 10:53
1
\$\begingroup\$

MATLAB, 477161

Edit: something odd is going on here. When I fed the original list through a RAR compressor, it got it down to 122Kb. When I feed my compressed list, though, it can only get it down to 222Kb. So, basically I created a compression algorithm that will make it harder for other compression algorithms to work. How about that, huh... :)

Takes the input string, strips it of the http at the start, and then compresses the string into a 7-bit representation. Appends an 'x' or 'y' for the decompressor to now whether it is dealing with a complete block or not; this could have probably been done more efficient (perhaps a parity bit) but this will have to do for now (it will only decrease my score with about 10k). I only realized halfway this was not code-golf, so you'll have to do without descriptive variable names.

function t=compress(s);
s=s(5:end);
t='';
replacable='"<>\^`{}';
for(k=replacable)
    s=strrep(s,['%' dec2hex(k)],k);
end
l=numel(s);
for(i=1:8:l-mod(l,8))
    t=[t char(bin2dec(reshape(dec2bin(s(i:i+7),7),7,8)))'];
end
if(mod(l,8))
    t=[t s(l-mod(l,8)+1:l)];
    t(end+1)='x';
else
    t(end+1)='y';
end

Decompress:

function s=decompress(t);
l=numel(t)-1;
if(t(end)=='x') 
    endfor=l-mod(l,7);
    endfor(l==endfor)=l-7;
else 
    endfor=l-1;
end
s='http';
for(i=1:7:endfor)
    s=[s char(bin2dec(reshape(dec2bin(t(i:i+6),8),8,7)))'];
end
if(t(end)=='x')
    s=[s t(endfor+1:end-1)];
end

replacable='"<>\^`{}';
for(k=replacable)
    s=strrep(s,k,['%' dec2hex(k)]);
end

EDIT: fixed some bugs, added some %xx replacements; other than that I'm calling it a day because I'll never get to 300k with this approach.

\$\endgroup\$
2
  • \$\begingroup\$ This question is only not code golf if your code comfortably fits <= 1024 bytes. Otherwise you'll have to start golfing ;) \$\endgroup\$
    – orlp
    Commented Apr 8, 2015 at 18:41
  • \$\begingroup\$ It's about 500, so that was a good waste of time. \$\endgroup\$
    – Sanchises
    Commented Apr 8, 2015 at 18:46
1
\$\begingroup\$

Python (413649)

Compressor:

u=input()[4:]
for i,j in zip('"<>\\^`{}\t\r\v\f','s:// :// codegolf.stackexchange.com en.wikipedia.org/wiki cjam.aditsu.net jsfiddle.net golfscript.apphb.com ideone.com github.com stackoverflow.com esolangs.org i.sstatic.net'.split()):
 u=u.replace(j,i)
print(u)

Decompressor:

u='http'+input()
for i,j in zip('"<>\\^`{}\t\r\v\f','s:// :// codegolf.stackexchange.com en.wikipedia.org/wiki cjam.aditsu.net jsfiddle.net golfscript.apphb.com ideone.com github.com stackoverflow.com esolangs.org i.sstatic.net'.split()):
 u=u.replace(i,j)
print(u)

The algorithm is very simple. The http at the beginning is stripped because it is the same in all of the test urls. It then takes the most common domain names in the test file and substitutes each for a single ascii character, out of the characters not used in any. It also substitutes :// (http) and s:// (https) for individual characters.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.