2 fixing my gender
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Ruby, 201 bytes

As promised in my other answer, here's one that uses functions instead of building a new class. I'm so close to breaching the 200 byte mark... Try it online

This uses the same opcodes as @Neil in theirhis JavaScript answer, and the same order of arguments (lhs, opcode, rhs)

0: Addition
1: Difference
2: Multiplication
3: Division
4: Counting
5: Equality

The code:

->x,o,y{[->{(x+y).sort},->r=[*x]{y.map{|i|r[r.index(i)||x.size]=p};r-[p]},->{(x==[*x]?x*y :y*x).sort},->{x.uniq.map{|i|[i]*(x.count(i)/y)}.flatten},->{y.map{|i|x.count i}.min},->{x.sort==y.sort}][o][]}

Ruby, 201 bytes

As promised in my other answer, here's one that uses functions instead of building a new class. I'm so close to breaching the 200 byte mark... Try it online

This uses the same opcodes as @Neil in their JavaScript answer, and the same order of arguments (lhs, opcode, rhs)

0: Addition
1: Difference
2: Multiplication
3: Division
4: Counting
5: Equality

The code:

->x,o,y{[->{(x+y).sort},->r=[*x]{y.map{|i|r[r.index(i)||x.size]=p};r-[p]},->{(x==[*x]?x*y :y*x).sort},->{x.uniq.map{|i|[i]*(x.count(i)/y)}.flatten},->{y.map{|i|x.count i}.min},->{x.sort==y.sort}][o][]}

Ruby, 201 bytes

As promised in my other answer, here's one that uses functions instead of building a new class. I'm so close to breaching the 200 byte mark... Try it online

This uses the same opcodes as @Neil in his JavaScript answer, and the same order of arguments (lhs, opcode, rhs)

0: Addition
1: Difference
2: Multiplication
3: Division
4: Counting
5: Equality

The code:

->x,o,y{[->{(x+y).sort},->r=[*x]{y.map{|i|r[r.index(i)||x.size]=p};r-[p]},->{(x==[*x]?x*y :y*x).sort},->{x.uniq.map{|i|[i]*(x.count(i)/y)}.flatten},->{y.map{|i|x.count i}.min},->{x.sort==y.sort}][o][]}
1
source | link

Ruby, 201 bytes

As promised in my other answer, here's one that uses functions instead of building a new class. I'm so close to breaching the 200 byte mark... Try it online

This uses the same opcodes as @Neil in their JavaScript answer, and the same order of arguments (lhs, opcode, rhs)

0: Addition
1: Difference
2: Multiplication
3: Division
4: Counting
5: Equality

The code:

->x,o,y{[->{(x+y).sort},->r=[*x]{y.map{|i|r[r.index(i)||x.size]=p};r-[p]},->{(x==[*x]?x*y :y*x).sort},->{x.uniq.map{|i|[i]*(x.count(i)/y)}.flatten},->{y.map{|i|x.count i}.min},->{x.sort==y.sort}][o][]}