Timeline for Count up folks!
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jun 17, 2020 at 9:04 | history | edited | CommunityBot |
Commonmark migration
|
|
Apr 28, 2016 at 13:58 | history | edited | Robert Benson | CC BY-SA 3.0 |
added 238 characters in body
|
Apr 27, 2016 at 4:42 | review | Suggested edits | |||
Apr 27, 2016 at 4:58 | |||||
Apr 26, 2016 at 11:10 | comment | added | Erik the Outgolfer | @OlivierDulac I prefer to say 'vote' for comments and 'upvote' for answers. | |
Apr 26, 2016 at 6:55 | comment | added | Olivier Dulac | @RobertBenson: If you edit (gain 2 bytes by taking out the curly braces around the printf, for example, and include a note showing the way to invoke it (like the one in your last comment), you'll gain 2 bytes + I would be able to revert my downvote to a vote. (right now it's locked "until it is edited") | |
Apr 25, 2016 at 17:28 | comment | added | Robert Benson |
@rexkogitans I agree that not initializing j=0 is ugly and I would never do it in production code... but this is PPCG :)
|
|
Apr 25, 2016 at 17:27 | comment | added | Robert Benson |
@OlivierDulac I can't use <$1 since j starts at 0, the first ++ gets it up to 1, so I need the <= . I didn't think I would need the awk "..." part since this could simply be placed in a file and called however you like (essentially like compiling a file in other languages). E.g. awk -f FILE <<< 21657
|
|
Apr 25, 2016 at 15:40 | comment | added | Olivier Dulac |
should be "<$1" (you go from 0 to $1-1, as you ++ before you print). You can also drop the {} after while, as you only have 1 command : {for(;j<$1;)print++j} . But : $1 is not valid in awk.. you're mixing shell's variable and awk variables. If you want $1, you also need to add the awk "..." wrapping ...
|
|
Apr 25, 2016 at 15:02 | comment | added | rexkogitans |
Not initialising with j=0 is ugly but ok here. :-)
|
|
Apr 25, 2016 at 14:22 | history | answered | Robert Benson | CC BY-SA 3.0 |