2 Fix typo and markdown

LINQ

Enumerable.Range(0,y).Select(i=>f(i))


to get an Enumerable with the result of function ff for every intint in [0,y[[0,y] you can use

new int[y].Select((_,i)=>f(i))


if you need stringsstring or anything that implements EnumerableEnumerable in your program you can use them too

var s="I need this anyway";
s.Select((_,i)=>f(i))


LINQ

Enumerable.Range(0,y).Select(i=>f(i))


to get an Enumerable with the result of function f for every int in [0,y[ you can use

new int[y].Select((_,i)=>f(i))


if you need strings or anything that implements Enumerable in your program you can use them too

var s="I need this anyway";
s.Select((_,i)=>f(i))


LINQ

Enumerable.Range(0,y).Select(i=>f(i))


to get an Enumerable with the result of function f for every int in [0,y] you can use

new int[y].Select((_,i)=>f(i))


if you need string or anything that implements Enumerable in your program you can use them too

var s="I need this anyway";
s.Select((_,i)=>f(i))

1

LINQ

Enumerable.Range(0,y).Select(i=>f(i))


to get an Enumerable with the result of function f for every int in [0,y[ you can use

new int[y].Select((_,i)=>f(i))


if you need strings or anything that implements Enumerable in your program you can use them too

var s="I need this anyway";
s.Select((_,i)=>f(i))