Timeline for Spoonerise words
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Jan 18, 2016 at 18:50 | comment | added | Dennis |
No, s is a default argument, so you don't have to specify it. An unnamed lambda is an acceptable submission; f= is not required.
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| Jan 18, 2016 at 18:37 | comment | added | Ogaday |
Thanks @Dennis, that does indeed work, nice refactoring. Interesting that the brackets are needed, and you don't need to pass s as an arg to the second lambda do you? That solution gives me 98 bytes, with a leading import statement and f=.
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| Jan 16, 2016 at 15:54 | comment | added | Dennis |
1. The question explicitly allows to take the two strings as a list, so there seems to be no good reason for the * in *g. 2. The second version can be golfed down to lambda x,y,s=lambda s:re.split("[aeiou]",s)[0]:(s(y)+x[len(s(x)):],s(x)+y[len(s(y)):]).
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| Jan 16, 2016 at 15:02 | history | edited | Ogaday | CC BY-SA 3.0 |
deleted 6 characters in body
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| Jan 16, 2016 at 15:01 | comment | added | Ogaday | Yes! Definitely. This is my first time golfing ever, so any feedback and advice is appreciated. | |
| Jan 16, 2016 at 4:13 | comment | added | xnor |
Presumably you mean s=re.split in the alternative?
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| Jan 15, 2016 at 16:49 | history | edited | ETHproductions | CC BY-SA 3.0 |
minor formatting edits
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| Jan 15, 2016 at 16:46 | review | First posts | |||
| Jan 15, 2016 at 16:57 | |||||
| Jan 15, 2016 at 16:42 | history | answered | Ogaday | CC BY-SA 3.0 |