#JavaScript (ES6), 24 bytes
Based on the Python answerPython answer.
c=x=>x?(4+6/~x)*c(x-1):1
###How it works
c=x=>x?(4+6/~x)*c(x-1):1
c=x=> // Define a function c that takes a parameter x and returns:
x? :1 // If x == 0, 1.
(4+6/~x) // Otherwise, (4 + (6 / (-x - 1)))
*c(x-1) // times the previous item in the sequence.
I think this is the shortest it can get, but suggestions are welcome!