Revisions to Find the number of integers in the range from 1 to N that ends with 2

added 4 characters in body; added 1 character in body

Source Link

edited Jan 6, 2021 at 16:02

51
3

Python 3, 5555 40 bytes

Any help with golfing it would be appreciated

lambda N:lensum([x forx%10==2for x in range(N+1)if str(x)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

Python 3, 55 bytes

Any help with golfing it would be appreciated

lambda N:len([x for x in range(N+1)if str(x)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

Python 3, 55 40 bytes

Any help with golfing it would be appreciated

lambda N:sum(x%10==2for x in range(N+1))

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

deleted 14 characters in body

Source Link

edited Mar 13, 2020 at 14:55

4R1u

51
3

Python 3, 5755 bytes

Any help with golfing it would be appreciated

    lambda N:len([x for x in range(N+1)
    if str(x)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

Python 3, 57 bytes

Any help with golfing it would be appreciated

    lambda N:len([x for x in range(N+1)
    if str(x)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

Python 3, 55 bytes

Any help with golfing it would be appreciated

lambda N:len([x for x in range(N+1)if str(x)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

added 42 characters in body

Source Link

edited Mar 11, 2020 at 15:10

4R1u

51
3

Python 3, 57 bytes

Any help with golfing it would be appreciated

    k=0
  lambda N:len([x for nx in range(1,N+1): 
     if n%10==2:k+=1
    printstr(kx)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

Python 3, 57 bytes

Any help with golfing it would be appreciated

    k=0
    for n in range(1,N+1): 
     if n%10==2:k+=1
    print(k)

thanks to the commentors for helping me out

Python 3, 57 bytes

Any help with golfing it would be appreciated

    lambda N:len([x for x in range(N+1)
    if str(x)[-1]=="2"])

Lots of thanks to the commentors for helping me out( I have problems with memory, see names below)

added 38 characters in body

Source Link

edited Mar 11, 2020 at 14:07

4R1u

51
3

Loading

added 1 character in body

Source Link

edited Mar 2, 2020 at 13:32

4R1u

51
3

Loading

Source Link

created Mar 2, 2020 at 13:12

4R1u

51
3

Loading

Stack Exchange Network

Return to Answer

Python 3, 5555 40 bytes

Python 3, 55 bytes

Python 3, 55 40 bytes

Python 3, 5755 bytes

Python 3, 57 bytes

Python 3, 55 bytes

Python 3, 57 bytes

Python 3, 57 bytes

Python 3, 57 bytes