Timeline for Make it rain characters
Current License: CC BY-SA 4.0
9 events
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| Jun 17, 2020 at 9:04 | history | edited | CommunityBot |
Commonmark migration
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| Jan 31, 2020 at 0:37 | comment | added | targumon | @Arnauld Not just in theory. It is possible to get 0. Extremely small chance, but still positive. I wrote a post about it: dev.to/targumon/how-does-math-random-work-1526 | |
| Apr 14, 2019 at 1:42 | comment | added | nedla2004 | @Arnauld That makes sense, I agree that defining the language by what it does makes this dubious at best. | |
| Apr 13, 2019 at 23:31 | comment | added | Ferrybig |
For what platform did you make your javascript for? Since the challenge has a uniqueness requirement, and does not specify a max input, this really matters, as most platforms are using a math.random() implementation that has an internal state, and thus cannot generate unique output.
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| Apr 13, 2019 at 10:34 | comment | added | Arnauld | @nedla2004 In theory, yes. In practice, I think it's very likely that the implementation(s) of the PRNG can't possibly return exactly \$0\$ (let alone close enough \$0\$'s so that all configurations actually have a chance to occur). Because we define a language by its implementation, I personally think it's therefore invalid. | |
| Apr 13, 2019 at 2:30 | comment | added | nedla2004 |
Google says that Math.random() returns a number in [0, 1), so couldn't Math.random()<.5 become Math.random()>0?
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| Apr 12, 2019 at 14:15 | comment | added | Arnauld |
@orthoplex That wouldn't work because (0|'A') === (0|undefined) and the remaining letters would not be guaranteed anymore to appear on the last row. (So, basically, it's just like |!a[y+1] was removed altogether.)
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| Apr 12, 2019 at 14:12 | comment | added | orthoplex | I think you could save one byte by not negating the ternary expression. | |
| Apr 12, 2019 at 13:58 | history | answered | Arnauld | CC BY-SA 4.0 |