This is a code golf version of a similar question I asked on stack earlier but thought it'd be an interesting puzzle.
Given a string of length 10 which represents a base 36 number, increment it by one and return the resulting string.
This means the strings will only contain digits from 0
to 9
and letters from a
to z
.
Base 36 works as follows:
The right most digit is incremented, first by using 0
to 9
#0000000000 > 9 iterations > 0000000009
0000000000 > 9 iterations > 0000000009
and after that a
to z
is used:
#000000000a > 25 iterations > 000000000z
000000000a > 25 iterations > 000000000z
If z
needs to be incremented it loops back to zero and the digit to its left is incremented:
#000000010
000000010
###Further rules:
Further rules:
- You may use upper case or lower case letters.
- You may not drop leading zeros. Both input and output are strings of length 10.
- You do not need to handle
zzzzzzzzzz
as input.
###Test Cases:
Test Cases:
"0000000000" -> "0000000001"
"0000000009" -> "000000000a"
"000000000z" -> "0000000010"
"123456zzzz" -> "1234570000"
"00codegolf" -> "00codegolg"