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Timeline for Wanna See a Card Trick? (Part I)

Current License: CC BY-SA 3.0

17 events
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Feb 13, 2018 at 22:57 history edited mbomb007 CC BY-SA 3.0
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Feb 13, 2018 at 6:41 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 3:55 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 3:49 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 3:33 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 2:46 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 2:35 comment added Eliseo D'Annunzio I meant no disrespect, @Ourous... It's a great submission, don't get me wrong... I guess having code-golfed a fair bit, I've been so used to seeing code that isn't so... tidy! ;) Look forward to later golfs of this piece when you have the time :)
Feb 13, 2018 at 2:33 comment added Οurous @WallyWest It can do.. okay. I enjoy writing well-golfed, but long answers more than short and easily-golfed ones.
Feb 13, 2018 at 2:17 comment added Eliseo D'Annunzio Interesting approach, though I'm wondering if you may have done yourself an injustice with using a language that doesn't appear very golfable?
Feb 13, 2018 at 1:53 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 1:42 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 1:29 comment added Οurous @EsolangingFruit Yep. Essentially an imperative assignment, with the exception of functions which can still recurse when used in # expressions.
Feb 13, 2018 at 1:18 comment added Esolanging Fruit So # is not a prefix operator but actually away to introduce non-recursive bindings?
Feb 13, 2018 at 1:13 comment added Οurous @EsolangingFruit It's actually two statements, the function definition ?n, and the node expression #n=n-1. The second of which effectively subtracts 1 from n.
Feb 13, 2018 at 0:59 comment added Esolanging Fruit What does ?n#n do?
Feb 13, 2018 at 0:50 history edited Οurous CC BY-SA 3.0
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Feb 13, 2018 at 0:28 history answered Οurous CC BY-SA 3.0