Skip to main content
Commonmark migration
Source Link

#Repeating Strings

Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... Better yet, and it also works in closures:

(0..<3).map{_ in"abc"}.joined()

And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

But make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... Better yet, and it also works in closures:

(0..<3).map{_ in"abc"}.joined()

And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

But make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... Better yet, and it also works in closures:

(0..<3).map{_ in"abc"}.joined()

And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

But make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

added 74 characters in body
Source Link
Mr. Xcoder
  • 42.5k
  • 9
  • 81
  • 214

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... Better yet, and it also works in closures:

(0..<3).map{_ in"abc"}.joined()

And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

 

#But

MakeBut make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

 

#But

Make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... Better yet, and it also works in closures:

(0..<3).map{_ in"abc"}.joined()

And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

But make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

added 154 characters in body
Source Link
Mr. Xcoder
  • 42.5k
  • 9
  • 81
  • 214

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

#But

Make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

#Repeating Strings

Unfortunately, Swift does not support String multiplication with *, likewise Python. A good method you can use instead is String(repeating:count:), but unfortunately that's not really golfy. Compare these two approaches:

var a=String(repeating:"abc",count:3)

and

var a="";for _ in 0..<3{a+="abc"}

The second one is a couple of bytes shorter, but that cannot be used in a closure... And what if I do it multiple times? Well, you can use String.init(). Now, this may save lots of bytes. For example (68 bytes):

let k=String.init(repeating:count:)
print(k("abcd",9)+k("XYZxyz",9))

instead of (74 bytes):

print(String(repeating:"abcd",count:9)+String(repeating:"XYZxyz",count:9))

or (70 bytes):

var f={String(repeating:$0,count:$1)}
print(f("abcd",9)+f("XYZxyz",9))

#But

Make sure your String is long enough. If you are using String(repeating:"abc",3), it is much better to use "abcabcabc" instead.

Source Link
Mr. Xcoder
  • 42.5k
  • 9
  • 81
  • 214
Loading