CJam, 2020 19 bytes
l_$_W=),\0=i>_W<W%+=\ci>_W<W%+=
Explanation
The basic idea is to find the minimum and maximum digit, then create a Giza number from those and then check that it's equivalent to the input.
l e# Read input.
_$ e# Get a sorted copy of the input.
_W= e# Get its last character, i.e. the maximum digit M.
), e# Get a string with all characters from the null byte up to M.
\0=\c e# Get the first character of the sorted string, i.e. the minimum
e# character m.
i> e# Convert to its character code and discard that many leading
e# characters from the string we generated before. Now we've got
e# a string with all digits from m to M, inclusive.
_W<W%+ e# Palindromise it, by appending a reversed copy without M.
= e# Check that it's equal to the input.
Instead of the minimum character, we can also use the first character, for the same byte count:
l_:e>),1$ci>_W<W%+=