My PPCG holiday is over :D
Intro
Fractional time is the year + (the value (minute of year) / number of minutes in the year)
.
Example calculation
You should assume that February always has 28 days and the year is always 365 days long.
Let's say we want to convert the time: 17:34 3rd March 2013
to fractional time. Firstly, you find how many minutes were in 2013: 525600 minutes. Let's call this x
.
Next, you want to find out how many minutes there have been since the start of 2013. A few quick calculations will tell you that the answer is 88894 minutes:
There have been 61 days since the start of the year, which times 1440 (number of minutes in a day) equals 87840 minutes. In 17 hours are 1020 minutes (17*60). Now, we can add 87840, 1020 and 34 minutes to equal 88894 minutes.
Let's call this y
.
Finally, you divide y
by x
and add the year, resulting in 2013.16912
(to 5 decimal places).
Input
The date and time will be given as a single string. The string will be in the following format:
YYYY-MM-DD hh:mm
The time will always be in 24 hour format and the year will always be in the range 1900-2050 inclusive.
Examples
Input: 2016-08-06 23:48
Output: 2016.59723
Input: 2013-03-03 17:34
Output: 2013.16912
Input: 1914-11-11 11:11
Output: 1914.86155
If you are going for the bounty, either ping me in the comments or in The Nineteenth Byte.
Challenge
Calculate the given date and time as a fractional year.
Give all output to five decimal places (you may round in anyway you wish: flooring, ceiling, or true rounding). Shortest code wins.
Bounty
I am offering a 100 rep bounty for the shortest program which also accepts the date in fractional year format and returns the time in YYYY-MM-DD hh:mm
format. In essence, your program (or function) has to act in the following way:
f('1914-11-11 11:11') => 1914.86155
f('1914.86155') => 1914-11-11 11:11
Leaderboard
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For this, assume February has 28 days and the year is 365 days long.
, but also... using the Gregorian calendar.
\$\endgroup\$