47
\$\begingroup\$

Full width text is text that has a space after every character, including the last one. For instance, the first sentence of this question becomes:

F u l l   w i d t h   t e x t   i s   t e x t   t h a t   h a s   a   s p a c e   a f t e r   e v e r y   c h a r a c t e r ,   i n c l u d i n g   t h e   l a s t   o n e . 

Write a program that takes a line in text from standard input and outputs it as full-width text to standard out.

Leaderboard

var QUESTION_ID=75979,OVERRIDE_USER=52353;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

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11
  • 8
    \$\begingroup\$ Usually you should allow functions too, or you exclude a lot of languages (e.g. JavaScript). \$\endgroup\$
    – wizzwizz4
    Mar 22, 2016 at 18:00
  • 10
    \$\begingroup\$ We have a few defaults for I/O that are based on community consensus. While you are entitled to override them, insisting on STDIN/STDOUT for I/O invalidates a bunch of answers (which assumed that the defaults apply) and make the task downright impossible in other languages (they don't have standard streams). \$\endgroup\$
    – Dennis
    Mar 22, 2016 at 21:22
  • 62
    \$\begingroup\$ That is not what fullwidth text is. \$\endgroup\$ Mar 22, 2016 at 21:53
  • 4
    \$\begingroup\$ @BlueRaja-DannyPflughoeft is right. Full Width text is about underlying character encoding ( 2 bytes encoded ) required by some language ( i.e. ideograms ). In Unicode the notion of half and full size is called Unicode block \$\endgroup\$ Mar 23, 2016 at 9:27
  • 3
    \$\begingroup\$ @LudovicFrérot Actually, these are not ideograms, these are chinese english letters. \$\endgroup\$ Jul 1, 2016 at 8:29

148 Answers 148

1
\$\begingroup\$

C 55, 49 bytes

g(){c;while((c=getchar())!='\n')printf("%c ",c);}

Ungolfed version:

void g()
{
  char c;
  while((c=getchar())!='\n')
  printf("%c ", c);
}
\$\endgroup\$
1
\$\begingroup\$

C#, 35 bytes

s=>string.Join(" ",s.ToList())+" ";

C# lambda where the input and the output are string. You can try it on .NetFiddle.

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1
  • \$\begingroup\$ This requires a using System.Linq derivative, which should either be included or the language marked as LinqPad or similar. \$\endgroup\$ Jan 12, 2017 at 11:07
1
\$\begingroup\$

Python 3, 39 bytes

print("".join([x+" "for x in input()]))
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5
  • 1
    \$\begingroup\$ You could just join with a " " rather than insert it with the comprehension. Then all you need to worry about is the trailing space at the end. print(" ".join(input())+" ") gets you down to 28 bytes \$\endgroup\$
    – wnnmaw
    Mar 23, 2016 at 16:15
  • \$\begingroup\$ This is now exact duplicate of Raffi's answer, which reached this format 1 day 01:30:09 hour earlier. \$\endgroup\$
    – manatwork
    Mar 24, 2016 at 10:34
  • \$\begingroup\$ @manatwork I see. Should I change my old answer back or something? Thanks for telling! \$\endgroup\$
    – Yytsi
    Mar 24, 2016 at 11:37
  • 1
    \$\begingroup\$ Just improve it more. ;) In meantime I would revert to the previous version – it demonstrates the usage of a very popular Python feature, which has better chances for positive votes than a duplicate. \$\endgroup\$
    – manatwork
    Mar 24, 2016 at 12:17
  • \$\begingroup\$ @manatwork Very good point! Reverted it. Back to 39 bytes :D \$\endgroup\$
    – Yytsi
    Mar 24, 2016 at 12:32
1
\$\begingroup\$

Python 3, 31 28

print(' '.join(input())+' ')

I know i'm late on this one, and definitely not a winner, but thought i'd try it out.

Edit: Switched to python 3. Thanks to CatsAreFluffy for saving 3 bytes!

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2
  • \$\begingroup\$ You can cut one byte by removing the space after print. \$\endgroup\$
    – Zach Gates
    Mar 22, 2016 at 22:53
  • \$\begingroup\$ Or just switch to Python 3 (and cut 3 bytes): print(' '.join(input)+' '). raw_input is more expensive than parens with print. \$\endgroup\$ Mar 23, 2016 at 2:31
1
\$\begingroup\$

Python 3, 95 93 92 80 32 26 30 bytes

Saved a byte thanks to @caird coinheringaahing

Saved bunch of bytes from @DJMcMayhem + My idea

print(' '.join(input())+' ')

Takes input, splits it, then prints a join with spaces

This is my first time golfing.

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5
  • 1
    \$\begingroup\$ Welcome to the site! You can remove a byte by removing the space after the : as well as taking a look at these tips for Python golfing \$\endgroup\$ Jan 26, 2018 at 16:26
  • \$\begingroup\$ You could get this down to a one-liner: print(''.join(i+' 'for i in input()) \$\endgroup\$
    – DJMcMayhem
    Jan 26, 2018 at 16:41
  • 1
    \$\begingroup\$ @DJMcMayhem, made it even shorter :) \$\endgroup\$ Jan 26, 2018 at 16:45
  • \$\begingroup\$ Does this print a space after the last character? And do you need the list() part? \$\endgroup\$
    – Jo King
    Jan 27, 2018 at 5:36
  • \$\begingroup\$ oh, one second. \$\endgroup\$ Jan 27, 2018 at 16:36
1
\$\begingroup\$

Common Lisp, 40 bytes

(map()(lambda(x)(format t"~C "x))(read))

I was very surprised that format couldn't do this by itself: it can only iterate over lists, not strings.

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1
\$\begingroup\$

Canvas, 4 3 bytes

 ]∑

Try it here!

Explanation:
   Push input to stack (implicit)
   For each character in the input: (implicit)
   Push the character to the stack (implicit)
   Push " " to the stack
] Collapse results from loop into an array
∑  Join the array into a single string
   Print the ToS (implicit)

-1 byte thanks to dzaima!

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1
  • 1
    \$\begingroup\$ You can remove the leading as it can be implicit for 3 bytes \$\endgroup\$
    – dzaima
    Mar 6, 2018 at 16:23
1
\$\begingroup\$

k, 10 bytes

{,/x,'" "}

Explanation

{..} is the lambda syntax

x,'"" takes the first argument x, and applies the join operator , to every character, creating an array of "l " pairs

,/ folds the array with the join operator

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1
\$\begingroup\$

SMBF, 9 bytes

Note the trailing space. Uses the space in the code rather than creating a 32 in a cell.

,[.<.>,] 

The tryitonline.net interpreter appears to have a bug and loop indefinitely with this, so it only works in my Python interpreter. Changing the SMBF source code (currently on line 171) inside the Python code is required.

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1
\$\begingroup\$

Brainfuck, 23 24 25 Bytes

1 Byte thanks to ovs

-[-[-<]>>+<]>-<+[,.>.<]

Try it online!
This code makes use of most interpreters wrapping to 255 if the number is negative.

Previous solution:

++++[>++++++++<-]+[,.>.<]

Try it online!

Explanation:

++++[>++++++++<-]   |Leaves the second cell with the number 32, the ASCII Code for a space.
+[,.>.<]            |Simple loop, gets the input, outputs it and adds a space.

Suggestions are welcome.

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5
  • \$\begingroup\$ 24 bytes. The initialization part is taken from this page \$\endgroup\$
    – ovs
    Jan 27, 2018 at 10:13
  • \$\begingroup\$ Cool, very nice. I have problems understanding your program though. Could you explain it to me? \$\endgroup\$
    – Dust
    Jan 27, 2018 at 10:21
  • \$\begingroup\$ The code makes use of the fact that most brainfuck implementations use wrapping 8-bit cells. If you decrement a cell that is zero, you get to 255. Here is a simple example. \$\endgroup\$
    – ovs
    Jan 27, 2018 at 10:35
  • \$\begingroup\$ The , should be at the end of the loop, otherwise you print an extra nul byte. Try it online! \$\endgroup\$
    – Jo King
    Feb 12, 2019 at 0:47
  • \$\begingroup\$ 22 bytes \$\endgroup\$
    – RezNesX
    Feb 12, 2021 at 7:34
1
\$\begingroup\$

Perl 6, 14 bytes

put get.comb,$

Try it online!

Prints a trailing newline.

Explanation:

put             # print to stdout
    get.comb    # the list of characters in the input, 
            ,$  # And an empty string
put             # Implicitly separated by spaces
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1
\$\begingroup\$

Gol><>, 7 bytes

iEH}` }

Courtesy of JoKing, who golfed this to the max!!! JoKing combined the loops into one simple loop, also avoided the mistake I made, I added 2 spaces rather than one.

Try it online!

Slightly newer of My original golfed, 23 bytes

Ti:0)?t~l&T` }}&M:&?trH

Try it online!

Old version, 28 bytes

Ti:0)?t~l&T"  "}}}&M:&0)?trH

This can probably be golfed futher, but code breakdown below!

Ti:0)?t~l&T"  "}}}&M:&0)?trH

Ti:0)?t~                    //gets every char from input, and pushes them to the stack
          T"  "}}}          //push 2 spaces after every char, push to the bottom of the stack for later
        l&T       &M:&0)?t  //push original length and store, every loop decrement and if it is greater than zero, repeat
                          rH//reverse stack and output the whole stack as characters

Try it online!

\$\endgroup\$
3
  • \$\begingroup\$ 7 bytes. Mostly because you can combine all the loops into one loop over the input \$\endgroup\$
    – Jo King
    Feb 12, 2019 at 0:29
  • \$\begingroup\$ @JoKing Wow, that is really smart using the E function! Also I just realized that it only needs one space, and that I forgot to add spaces after the last characters, sorry! \$\endgroup\$ Feb 12, 2019 at 0:31
  • \$\begingroup\$ @JoKing Almost managed 6 bytes, but it prints entirely backwards... iEH@` \$\endgroup\$ Feb 12, 2019 at 0:44
1
\$\begingroup\$

PowerShell, 24 bytes

"$args"-replace'.','$0 '

Try it online!

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1
\$\begingroup\$

Zsh, 21 bytes

echo ${(s::)$(<&0)}\ 

Try it online!

$(capture), ${(s::)plit}, echo. The last "\ " is needed for the trailing space.

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1
\$\begingroup\$

Befunge-98 (PyFunge), 6 bytes

"#@~,,

Try it online!

The Befunge-98 answer is pretty long, so here is a shorter one. Basically the same answer as this Befunge-93 answer by Sp3000, but ends up being half as long, thanks to Befunge-98s ~ reflecting on EOF.

One thing that bugged me is, that when you run it on multi line input, every line but the first will be indented (since the linebreak will be followed by a space as well), so here is a version (11 bytes), that doesn't have that problem.

"#@~:,a-!j,

Try it online!

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1
\$\begingroup\$

Keg, -rs, 3 bytes

( '

Shifts the input putting a space after each character, reverses the stack via the -rs flag and then implicitly outputs the stack.

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1
\$\begingroup\$

PowerShell, 17 8 bytes

-9 bytes thanks to @mazzy!

"$args "

Try it online!

There are already a couple of PowerShell answers to this question, but I thought I'd throw mine into the mix. It takes splatter input from a command line argument. It also assumes that $ofs is equal to one space, which it is by default.

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2
  • 1
    \$\begingroup\$ Great! The codegolf allow you to use an char array instead of a string. Therefore, 8 bytes \$\endgroup\$
    – mazzy
    Jan 2, 2020 at 7:21
  • \$\begingroup\$ @mazzy finally, a competitive PowerShell answer ;) thanks! \$\endgroup\$
    – GMills
    Jan 2, 2020 at 16:37
1
\$\begingroup\$

Vyxal , 3 2 bytes

Ṅð

Try it Online!

Explanation:

     # Implicit input
Ṅ    # Insert ' ' between each character
  ð  # Push ' '
     # 'Ṫ' flag - sum entire stack and print

If the final space wasn't necessary:

Vyxal S, 0 bytes

Try it Online!

Explanation:

  # Implicit input
  # 'S' flag - Print top of stack joined by spaces
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1
  • \$\begingroup\$ ð* with s also works for 2 bytes \$\endgroup\$
    – emanresu A
    Sep 23, 2021 at 19:54
1
\$\begingroup\$

Silicon, 6 bytes

iSæ%æ+

Explanation:

iSæ%æ+
i        Input
 S       Split the input
  æ      Push a space
   %     Join at spaces
    æ+   Append a space to the end of the string
         Implicit output

7 bytes

iSæ²jæ+
\$\endgroup\$
2
  • 1
    \$\begingroup\$ Does Silicon have it's own encoding? Else, it would be 10 bytes in UTF-8 (and 7 chars). \$\endgroup\$
    – Katenkyo
    Jul 6, 2016 at 9:07
  • \$\begingroup\$ @katenkyo I think it has. \$\endgroup\$
    – user100411
    Sep 25, 2021 at 0:21
1
\$\begingroup\$

Javascript, 19 bytes

s=>[...s,,].join` `
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0
1
\$\begingroup\$

Japt, 4 bytes

®+S

Try it online!

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1
\$\begingroup\$

Pushy, 7 bytes

32DL:{'

Try it online!

Works like so:

       \ Implicit: Input is on stack as charcodes
32D    \ Set the printing delimiter to a space
L:     \ Input length times do:
  {    \   Cyclically shift the stack left
   '   \   Print the last character (includes trailing space)

Alternatively, for the same byte count, one could have:

L:{32;"

Try it online!

L:   ;   \ Length times do:
  {      \   Shift string left
   32    \   Insert char 32 (a space)
      "  \ Afterwards, print the whole string
\$\endgroup\$
1
\$\begingroup\$

Commodore C64 BASIC, 39 Tokenised BASIC bytes, 42 PETSCII characters with keyword abbreviations

0INPUTA$:FORI=1TOLEN(A$):?MID$(A$,I,1)" ";:NEXT

On running this listing, the interpreter will expect an input of strings which when the return key is pressed, will store the text entered into the variable A$. It will then iterate over each position of the string to its length and PRINT it, proceeded by a white space, and then will continue at the next cursor position until the final character of the string is printed (this will be followed by a space too).

Some notes: A Commodore C64 screen is 40 characters wide by default, and the maximum number of characters that may be stored in a string is 255, however, when using INPUT the interpreter will only accept a total entry of 77 characters without some trickery (80 characters if you delete the ? prompt, enter 80 characters and then cursor up two lines and press the RETURN key).

See screenshot for this in action.

Commodore C64 Full Width Text CodeGolf challenge

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1
\$\begingroup\$

Pascal, 90 bytes

This is a full program suitable for a processor supporting “Standard Pascal” and/or “Extended Pascal” as defined by ISO standards 7185 and 10206 respectively. As per specification it takes a line (not many lines). Note, calling EOLn(input) causes an error if EOF(input) is true prior invocation of EOLn. Hence it must be guaranteed that input contains at least an end‑of‑line marker.

program p(input,output);begin while not EOLn do begin write(input↑,' ');get(input)end end.

We can add −10 bytes if it is guaranteed that input is a non‑empty line:

program p(input,output);begin repeat write(input↑,' ');get(input)until EOLn end.
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1
\$\begingroup\$

K (ngn/k), 5 bytes

,/2$'

Try it online!

Runs as a function within the repl.

  • 2$' right-pad each individual character of the input to length 2, i.e. append a space
  • ,/ flatten the resulting list of strings into a single string and (implicitly) return

If input must be read from STDIN, the following suffices for 9 bytes:

,/2$'*0:`

It is the same as above, but takes a line of input from STDIN via *0:`.

\$\endgroup\$
0
\$\begingroup\$

Javascript, 35 chars

Full program

alert(prompt().replace(/./g,"$& "))

Javascript ES6, 24 chars

Just a function

s=>s.replace(/./g,"$& ")
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2
  • \$\begingroup\$ As we are using a leaderboard right now, would you mind modifying your title for just "Javascript", as it will actually be considered as an other language. \$\endgroup\$
    – Katenkyo
    Mar 23, 2016 at 9:50
  • \$\begingroup\$ @Katenkyo, updated \$\endgroup\$
    – Qwertiy
    Mar 23, 2016 at 9:54
0
\$\begingroup\$

Befunge-98, 21 bytes

>  ~:av
^,*84,w
@,*84,<

Lengthier than one already present but has the ending space requested by OP.

\$\endgroup\$
0
\$\begingroup\$

Japt, 5 bytes

U¬¸+S

Try it here.

\$\endgroup\$
0
\$\begingroup\$

Matlab/Octave, 51 bytes

s=s(.5:.5:length(s))
s(1:2:length(s))=' '
\$\endgroup\$
0
\$\begingroup\$

Befunge-93, 18 bytes

>~:1`#v_@
^," ",<
\$\endgroup\$

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