Print the alphabet without using each vowel

Question

Inspiration: in 1939, a man named Ernest Vincent Wright wrote a novel called Gadsby without using the letter 'e'.

Your task is to write a set of (up to 5) programs in any language (which has a text-based syntax*) to output all 26 letters of the alphabet in order. However for each vowel aeiou, at least one of the programs must not include any occurrence of the vowel.

So there must be

a program that does not use 'a' or 'A' anywhere in the syntax of the program.
a program that does not use 'e' or 'E' anywhere in the syntax of the program.
a program that does not use 'i' or 'I' anywhere in the syntax of the program.
a program that does not use 'o' or 'O' anywhere in the syntax of the program.
a program that does not use 'u' or 'U' anywhere in the syntax of the program.

All of them must output abcdefghijklmnopqrstuvwxyz.

The winner shall be the solution where the length of all programs is the shortest.

_{* since the constraint wouldn't be much of a challenge in Piet or Whitespace}

if one manages to make a single program that does not contain any vowel, do we need multiply the length of the program by 5? — Cristian Lupascu, Apr 24, 2012 at 10:55
@w0lf: No, it says "up to 5 programs" and "length of all programs", which I read as "there can be only one program and its length counts in this case". — schnaader, Apr 24, 2012 at 11:09
@PeterTaylor: You don't think having to avoid using vowels in your syntax is a unique challenge? As a JS programmer, it's especially interesting :) — mellamokb, Apr 24, 2012 at 13:51
Are newlines acceptable in the output (i.e. one per character)? I can shorten some of my code if that is the case... — Gaffi, Apr 24, 2012 at 21:17

zzzzBov · Accepted Answer · 2012-04-24 18:42:15Z

4

PHP, HTML (50)

No 'aeiou':

&#97;bcd&#101;fgh&#105;jklmn&#111;pqrst&#117;vwxyz

abcdefghijklmnopqrstuvwxyz

answered Apr 24, 2012 at 18:42

zzzzBov

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1

\$\begingroup\$ @joar, I can't tell if you're trying to be humorous, it seems to have been lost on me. \$\endgroup\$
– zzzzBov
Apr 27, 2012 at 13:39
1

\$\begingroup\$ @joar, it's not magic, but it is valid PHP. You can't pipe anything through the PHP interpreter, you need to pipe valid characters in the correct encoding. HTML happens to be valid PHP because it's used as a subset of the language. \$\endgroup\$
– zzzzBov
Apr 27, 2012 at 13:53
1

\$\begingroup\$ Nope, HTML is a subset of PHP, PHP includes everything that HTML can do, in addition to other capabilities. PHP has to parse the entire contents of the page to find the <? tags, so the HTML is parsed, and then passed through. Hamlet can be piped through PHP in the same way that you can pipe Hamlet through an HTML file and have it be HTML. Comments are not the appropriate location for these extended discussions, so send me an email if you wish to resolve your confusion. \$\endgroup\$
– zzzzBov
Apr 27, 2012 at 14:16
1

\$\begingroup\$ PHP does not parse the HTML, it scans it for the next PHP block start tag. see the definitions of parse. \$\endgroup\$
– joar
Apr 27, 2012 at 14:43
4

\$\begingroup\$ PHP does indeed output the text. The problem is, this PHP program doesn't output the whole alphabet. It outputs some of the letters, along with various other characters like #. The entity decoding is done by HTML. You could use html_entity_decode to get around this (of course it has 3 vowels, so you'd need to deal with that). \$\endgroup\$
– Matthew Flaschen
Apr 29, 2012 at 3:32

| Show 7 more comments

Benedict · Accepted Answer · 2012-04-26 09:37:40Z

4

Postscript, 46 45

(\141bcd\145fgh\151jklmn\157pqrst\165vwxyz)=

edited Apr 26, 2012 at 9:37

answered Apr 25, 2012 at 15:24

Benedict

2111 silver badge3 bronze badges

\$\begingroup\$ You can shorten that by one character by removing the space. \$\endgroup\$
– Joey
Apr 26, 2012 at 9:00

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Prince John Wesley · Accepted Answer · 2012-04-28 10:26:17Z

4

Scala,38+17=55

No 'aeio':

'\u0061't\u006f'z'm\u0061p pr\u0069nt

No 'u':

'a'to'z'map print

Output: abcdefghijklmnopqrstuvwxyz

edited Apr 28, 2012 at 10:26

answered Apr 26, 2012 at 5:34

Prince John Wesley

6891 gold badge5 silver badges6 bronze badges

2

\$\begingroup\$ Your answer only satisfies 'e' and 'u'. You need to add a version that does not use 'a', 'i' and 'o'. \$\endgroup\$
– shamp00
Apr 26, 2012 at 9:55
\$\begingroup\$ @shamp00: +1 Now fixed \$\endgroup\$
– Prince John Wesley
Apr 26, 2012 at 12:18
1

\$\begingroup\$ You still need the no 'u' version too. The task is to have as many programs as necessary to cover all 5 vowels. Then you add the lengths together for the total score. \$\endgroup\$
– shamp00
Apr 26, 2012 at 13:09
\$\begingroup\$ Regarding what @shamp00 says, just add back in your ('b'-1).toChar to'z'map print and you're good to go! \$\endgroup\$
– Gaffi
Apr 27, 2012 at 12:23
\$\begingroup\$ @Gaffi: ok. let me add my original version. \$\endgroup\$
– Prince John Wesley
Apr 28, 2012 at 1:58

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Mark Reed · Accepted Answer · 2012-05-01 23:03:10Z

4

Ruby, 47 characters

(1) Only contains 'a' and 'u', 24 chars:

puts [*97..122].pack'c*'

(2) Only contains 'o' and 'i', 23 chars:

$><<[*97.chr..'z'].join

There's a slight difference in output in that the first one adds a newline and the second doesn't. Could add the newline to the second at a cost of 4 characters; removing it from the first would be harder.

edited May 1, 2012 at 23:03

answered Apr 24, 2012 at 15:07

Mark Reed

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Community · Accepted Answer · 2017-04-13 12:39:09Z

4

Brainfuck, 25 bytes

One byte improvement c/o Sp3000.

+[+<+<+[>]<-<+<+]>[+>+.<]

Try it online!

The initial bit +[+<+<+[>]<-<+<+] initializes the tape to:

[0, 106, 106, 0, 230, 96, 0, 135, 0]
              ^

This is an ideal tape (as 230 is 256-26).

26 bytes

--[->-[<]>+>-]>[+++<<+.>>]

Try it online!

Exactly one byte per letter. The initial bit --[->-[<]>+>-] initializes the tape to:

[0, 0, 0, 0, 0, 96, 0, 178, 0]
                    ^

178 is conveniently 256 - 26·3.

Alternatives

-[-[+>--<<<]>>>]>[->-.++<]
+[+[->++<<]>>+>+]<+[-<+.>]

edited Apr 13, 2017 at 12:39

CommunityBot

1

answered Sep 16, 2016 at 5:29

primo

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1

\$\begingroup\$ 25: +[+<+<+[>]<-<+<+]>[+>+.<] \$\endgroup\$
– Sp3000
Sep 19, 2016 at 0:23
\$\begingroup\$ My pruning logic seems off - it was detected as an infinite loop. I may need to re-crunch some results >.< \$\endgroup\$
– primo
Sep 19, 2016 at 1:30

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Olivier Grégoire · Accepted Answer · 2017-09-11 09:33:45Z

4

Java (OpenJDK 8), 137 bytes

$->""+($=97)+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$+ ++$

Try it online!

Similar to another answer of mine in Java. (Ab-)uses the lack of a "no input" rule.

answered Sep 11, 2017 at 9:33

Olivier Grégoire

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\$\begingroup\$ Brilliant! Upvoted both your answers. Very original, especially for a Java answer. \$\endgroup\$
– Kevin Cruijssen
Sep 13, 2017 at 14:00
\$\begingroup\$ @KevinCruijssen Thank you! I've had a hard time making the first one (the other one), but this one was very, very similar. \$\endgroup\$
– Olivier Grégoire
Sep 13, 2017 at 14:12

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Eliseo D'Annunzio · Accepted Answer · 2019-10-03 23:43:35Z

JavaScript (single program, no vowels whatsoever) 104 99 92 90

Edit 1: ~~[]["s\157rt"]["c\157nstr\165ct\157r"]('\141l\145rt("\141bcd\145fgh\151jklmn\157pqrst\165vwxyz")')()~~

Edit 2: ~~3[$="c\157nstr\165ct\157r"][$]('\141l\145rt("\141bcd\145fgh\151jklmn\157pqrst\165vwxyz")')()~~

3[$="c\157nstr\165ct\157r"][$]('\141l\145rt`\141bcd\145fgh\151jklmn\157pqrst\165vwxyz`')()

Edit 1: Previously used "filter" as my array trigger to access global object, reduced it to "sort" for a saving of 5 chars.

Edit 2: Reduced initial array to 3 to obtain constructor primitive and reused constructor recursively to shave off 7 chars, many thanks to @Firefly for the inspiration.

Edit 3: Reduced (" and )" in single-quoted string to backticks, shaving a further 2 characters.

ugoren · Accepted Answer · 2012-04-24 12:35:34Z

3

C, 136 115 104 characteres

A C program must have a main function. So my code is valid, except for these a and i. Prints a newline at the end. Can save some characters by removing it.

No e,i,o, 50 chars:

f(x){putchar(x?123-x:10),x--&&f(x);}
main(){f(0);}

No a,u, 54 chars:

f(x){printf("%c",x?123-x:10),x--&&f(x);}
main(){f(26);}

edited Apr 24, 2012 at 12:35

answered Apr 24, 2012 at 10:52

ugoren

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1

\$\begingroup\$ "A C program must have a main function" - This SO question taught me this isn't true, see my answer :) \$\endgroup\$
– schnaader
Apr 24, 2012 at 11:11
\$\begingroup\$ @schnaader, the ANSI C standard says "The function called at program startup is named main". Your code does work, but I'm not sure how portable it is (not that the question requires portability). Anyway, I'll stick to main. \$\endgroup\$
– ugoren
Apr 24, 2012 at 12:21

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Paul · Accepted Answer · 2012-04-25 15:10:36Z

3

Javascript (139 chars), logging to console:

Uses no 'aeou' (95 chars):

q=''+{};w=q[1];this['c'+w+'ns'+w+'l'+q[4]]['l'+w+'g']('\x61bcd\x65fghijklmn\x6fpqrst\x75vwxyz')

Uses no 'i' (44 chars):

console.log('abcdefgh\x69jklmnopqrstuvwxyz')

edited Apr 25, 2012 at 15:10

answered Apr 24, 2012 at 20:44

Paul

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\$\begingroup\$ I count here 95 and 79 characters, respectively. \$\endgroup\$
– Gaffi
Apr 24, 2012 at 21:12
1

\$\begingroup\$ @Gaffi Thanks haha. I wrapped it in double quotes and used .length to get the length. Of course the \x75 and such were counting as one character haha, oops. \$\endgroup\$
– Paul
Apr 24, 2012 at 21:52
\$\begingroup\$ It happens. :-) \$\endgroup\$
– Gaffi
Apr 24, 2012 at 22:21

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l0n3sh4rk · Accepted Answer · 2012-04-25 17:14:15Z

3

PHP, 47

All credits to mellamokb

<?="\x61bcd\x65fgh\x69jklmn\x6fpqrst\x75vwxyz";

edited Apr 25, 2012 at 17:14

answered Apr 25, 2012 at 16:47

l0n3sh4rk

1,45711 silver badges13 bronze badges

1

\$\begingroup\$ You can shorten by using string concatenation instead of exiting tags: <?=chr(97).'bcd'.chr(101).... Also, you can make even shorter by using the hex escape sequences <?="\x61bcd\x65...". Here's some examples of alternative shorter solutions, the last is the shortest at 47 characters (note also that you can safely leave the final closing tag off to save 2 chars): ideone.com/7aAQh \$\endgroup\$
– mellamokb
Apr 25, 2012 at 17:03

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kernigh · Accepted Answer · 2012-05-04 20:10:48Z

Factor, 264 characters

No ae, 60 characters:

USING: io ;
"\u000061bcd\u000065fghijklmnopqrstuvwxyz" print

No io, 102 characters:

USE: eval
"USE: \u000069\u00006f
\"abcdefgh\u000069jklmn\u00006fpqrstuvwxyz\" pr\u000069nt" eval( -- )

No u, 102 characters:

FROM: math.ranges => [a,b] ;
FROM: io => print ;
FROM: strings => >string ;
97 122 [a,b] >string print

Every language, in the previous answers, uses less than 200 characters. Factor is the only language to use more than 200 characters and to use 3 programs. Factor is difficult, because outputting without io is a challenge, and programming without u is almost impossible.

The first 2 programs are variations of

USE: io
"abcdefghijklmnopqrstuvwxyz" print

Alternatives to io are scarce; formatting still needs i and o, and prettyprint needs i. I saw string evaluation in a Python answer, and took the hint. With eval, I can escape away i and o, but I need a and e in eval, and u in \uxxxxxx escapes.

The hardest challenge is to remove u. This means no USE:, USING:, \uxxxxxx, nor sequences. My best program without u needs all of aeio. I would like a Factor program without aeu, but my only way to remove ae is to use u.

Sorry, wasn't thinking straight! RENAME: each-integer math => # 26 [ 65 + write1 ] # — fede s., Dec 1, 2017 at 17:34

Ilmari Karonen · Accepted Answer · 2012-05-05 00:08:45Z

3

Perl 5.10+, 8 + 22 = 30 chars

No e, i, o, u:

say a..z

No a, i, o, u:

s//"s\x61y \x61..z"/ee

Both of these need the -M5.010 switch (which is considered free) to enable the say feature. For older perls, it can be replaced with print for an extra four chars (and loss of trailing newline in output):

print a..z
s//"pr\x69nt \x61..z"/ee

answered May 5, 2012 at 0:08

Ilmari Karonen

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Gilles Quénot · Accepted Answer · 2012-06-05 18:22:36Z

3

Bash 34 characters

This is my 34 characters long bash snippet, close to marinus snippet but shorter :

/*/?ch? $'\145ch\157 {\x61..z}'|sh

edited Jun 5, 2012 at 18:22

answered Jun 3, 2012 at 14:35

Gilles Quénot

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mykhal · Accepted Answer · 2012-12-19 22:22:58Z

3

Perl (25 24 ) (18?) (no wowels, little cheating)

script.pl contains:

$"="";s//@{["\x61"..z]}/

it has to be executed this way:

echo | perl -p script.pl

or

echo | perl -pe '$"="";s//@{["\x61"..z]}/'

If you don't mind spaces between letters in the alphabet, it can be shortened to 18 characters:

s//@{["\x61"..z]}/

($" variable defines separator to be used for printing arrays, space is default)

UPDATES:

s/^/ -> s//

edited Dec 19, 2012 at 22:22

answered Dec 19, 2012 at 22:01

mykhal

6314 silver badges7 bronze badges

\$\begingroup\$ You could whipe (useless) pipes! perl -pe 's//@{["\x61"..z]}/' <<<'' \$\endgroup\$
– F. Hauri - Give Up GitHub
Jul 8, 2014 at 22:46

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Johannes Kuhn · Accepted Answer · 2013-04-11 10:34:04Z

3

Tcl, 49 chars

p\165ts \141bcd\145fgh\151jklmn\157pqrst\165vwxyz

Yeah, \ substitution works for commands. (And all other kinds of substitution as well)

edited Apr 11, 2013 at 10:34

answered Apr 11, 2013 at 10:04

Johannes Kuhn

7,4765 gold badges31 silver badges44 bronze badges

\$\begingroup\$ demo \$\endgroup\$
– sergiol
May 23, 2017 at 22:30
\$\begingroup\$ The shortest iterative algorithm I can devise is longer, even before applying the no vowels restriction, having 51 bytes: while {[incr n]<27} {puts [format %c [expr $n+96]]} \$\endgroup\$
– sergiol
May 23, 2017 at 22:40
\$\begingroup\$ Shorter without restriction is 45:time {puts [format %c [expr [incr i]+96]]} 26 \$\endgroup\$
– sergiol
Jul 21, 2017 at 18:39

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Dennis Jaheruddin · Accepted Answer · 2014-01-29 10:43:41Z

3

Matlab: 11 characters

['' 97:122]
% Or equivalently
['' 97]:'z'

If it is allowed to output more than just the alphabet, this can be reduced to just 7:

'`':'z'

answered Jan 29, 2014 at 10:43

Dennis Jaheruddin

1,9611 gold badge14 silver badges21 bronze badges

\$\begingroup\$ Very nice! Contatenating '' to convert to string \$\endgroup\$
– Luis Mendo
Jul 26, 2015 at 3:51

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n̴̖̋h̷͉̃a̷̭̿h̸̡̅ẗ̵̨́d̷̰̀ĥ̷̳ · Accepted Answer · 2014-12-02 16:45:35Z

3

Javascript, 96

No "aeiu"

throw('\x61bcd\x65fgh\x69jklmnopqrst\x75vwxyz')

No "o"

eval("thr\x6fw('abcdefghijklmn\x6fpqrstuvwxyz')")

Run it from console

Chrome

enter image description here

Firefox

enter image description here

edited Dec 2, 2014 at 16:45

n̴̖̋h̷͉̃a̷̭̿h̸̡̅ẗ̵̨́d̷̰̀ĥ̷̳

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answered Aug 8, 2013 at 11:27

C5H8NNaO4

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\$\begingroup\$ How do I run this? I can't get it to work with JSFiddle, nor in onload(). \$\endgroup\$
– shamp00
Aug 15, 2013 at 15:52
\$\begingroup\$ @shamp00 You can run it from you browsers console, i edited the answer and added 2 screenshots =) \$\endgroup\$
– C5H8NNaO4
Aug 16, 2013 at 6:06

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Martin Ender · Accepted Answer · 2015-06-02 02:38:42Z

Fission, 21 bytes

~MR' @'`~~~~~~
S[+!
*

Control flow starts at R with a right-going atom. First we set the mass to 32 with '<space>. @ swaps mass and energy. '` sets the mass to 96, so our atom is now (96,32). We decrement the energy seven times with ~ to get (96,25) (note that the code is toroidal). M redirects the atom downwards and [ to the right. We're now on the second line. + increments the mass, the ! prints the corresponding character. By doing this repeatedly we print the alphabet starting at a. As long as the energy is still positive, the S will let the atom pass straight through, such that we keep looping through the second line. However, while doing so it will also decrement the energy. Once the energy is 0 (and we've printed z), S will instead deflect the atom downwards, where it hits *, which terminates the program.

M L · Accepted Answer · 2015-08-18 11:41:26Z

3

Cardinal, 22 20 chars

%n->,#~n'!@
 b ^+< y

output:

Executing program..

abcdefghijklmnopqrstuvwxyz

Execution complete.
>

edited Aug 18, 2015 at 11:41

answered Aug 18, 2015 at 11:12

M L

3,2751 gold badge18 silver badges19 bronze badges

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Greg Martin · Accepted Answer · 2016-09-16 07:17:10Z

Mathematica, 61 bytes

Yeah, total thread necro. Just wanted to see if I could do it at all! (Mathematica command names tend to be pretty verbose and thus vowel-heavy....)

Each of the two commands

Alphabet[]

and

Union@@(StringSplit[#,""]&/@WordList[][[443;;692]])

outputs a list of the 26 lowercase letters in order. StringSplit[#,""]& splits its input string at every occurrence of "", that is, between every character (hence accomplishes the same as the command Characters@#, but without that nasty "a" or "e"). This is applied to a set of 250 words, namely the 443rd to 692th words of the built-in word list. (The 443rd word, "adequateness", is needed for its "q", while the 692nd word, "aftershock", is needed for its "k". None of the first 427 words contains an "x", and the 428th word, "add-on", has an unfortunate hyphen; so we had to start over to find a contiguous block that works.) Finally, Union removes repetitions and sorts the list to boot.

mbomb007 · Accepted Answer · 2016-09-16 16:14:05Z

3

Python shell, 94 78 chars

It prints the alphabet when running in an interactive shell (which prints the expression it evaluates).
Python isn't the tool for this task. Printing requires print, loop constructs require in or while, so i is quite a problem.

Both these expressions evaluate to the a-z string. The first doesn't use i,o, the second doesn't use a,e,u

"%c"*26%tuple(range(97,123))
''.join([chr(ord(c)-1)+c for c in'bdfhjlnprtvxz'])

Brute-force approach, 110 chars:

"%c"*26%(97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121,122)

edited Sep 16, 2016 at 16:14

mbomb007

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answered Apr 24, 2012 at 13:26

ugoren

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\$\begingroup\$ eval's got no i. \$\endgroup\$
– boothby
Apr 25, 2012 at 1:54
4

\$\begingroup\$ @boothby Yes it does: evil. There. \$\endgroup\$
– Konrad Rudolph
Apr 25, 2012 at 9:03
\$\begingroup\$ Languages are defined by their implementation. A Python shell is not a normal implementation of Python, so it's a "different language". meta.codegolf.stackexchange.com/a/7844/34718 \$\endgroup\$
– mbomb007
Sep 16, 2016 at 16:15

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Alex Neises · Accepted Answer · 2017-08-06 19:44:42Z

JavaScript (Node.js), 32113 bytes

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Try it online!

Community · Accepted Answer · 2020-06-17 09:04:33Z

3

Japt, 2 bytes

;C

Test it here

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Sep 11, 2017 at 10:15

Shaggy

41.9k4 gold badges34 silver badges93 bronze badges

Add a comment |

Charlie · Accepted Answer · 2017-09-11 10:56:06Z

3

We can now use languages made after the question was posted, right?

Charcoal, 1 byte

β

Try it online!

In Charcoal, β is a predefined variable containing the lowercase alphabet, so no vowels there.

answered Sep 11, 2017 at 10:56

Charlie

12.9k1 gold badge41 silver badges99 bronze badges

\$\begingroup\$ this works now too :P (verbose mode) \$\endgroup\$
– ASCII-only
Oct 4, 2017 at 11:33

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Community · Accepted Answer · 2020-06-17 09:04:33Z

3

JS (ES2018), 54 bytes

\141l\145rt`\141bcd\145fgh\151jklmn\157pqrst\165vwxyz`

Alerts "abcdefghijklmnopqrstuvwxyz".

So, you can update the JS score to 54 bytes.

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 11, 2017 at 16:25

user75200

1814 bronze badges

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Dom Hastings · Accepted Answer · 2020-08-15 20:55:39Z

3

Perl 5 `-p`, 21 bytes

}{$\.=$_ for"\141".._

Try it online!

edited Aug 15, 2020 at 20:55

answered Sep 11, 2017 at 7:41

Dom Hastings

23.5k4 gold badges53 silver badges91 bronze badges

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ratchet freak · Accepted Answer · 2012-04-25 13:24:26Z

2

D no 'u' (64 chars)

import std.stdio;void main(){for(char c=96;c++<'z';){write(c);}}

D only i (92 chars)

mixin("imp\157rt std.stdi\157;v\157id m\141in(){f\157r(ch\141r c;c++<'z';){writ\145(c);}}");

abusing the mixin and octal escape in string literals

edited Apr 25, 2012 at 13:24

answered Apr 25, 2012 at 9:56

ratchet freak

1,4461 gold badge9 silver badges11 bronze badges

\$\begingroup\$ What about the complementary program(s) that don't use a,e,i,o? \$\endgroup\$
– mellamokb
Apr 25, 2012 at 12:52
\$\begingroup\$ @mellamokb check now :) \$\endgroup\$
– ratchet freak
Apr 25, 2012 at 13:24
5

\$\begingroup\$ You still need a version with no i. \$\endgroup\$
– shamp00
Apr 27, 2012 at 15:45

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Community · Accepted Answer · 2020-06-17 09:04:33Z

2

BASH: 16 + 32 = 48 characters

Here's some inspiration to all you shell-lovers:

Using a, i (no e, o, u): 16 characters

printf %q {a..z}

Using e, o (no a, i, u): 32 characters

$0<<<$'echo {\x61..z}|tr -d " "'

works well, providing you've set your computer up with an automatic

#!bin/bash

I'm sure someone out there knows how to un-vowel this!

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Apr 29, 2012 at 9:31

Max Chuquimia

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Mormegil · Accepted Answer · 2012-09-28 16:46:51Z

C# – 278/149

Variant 1 – Full standalone programs

A and I are unavoidable here because of class and static.

Without U: 81 chars:

class C{static void Main(){for(int x=65;x<91;++x)System.Console.Write((char)x);}}

Without E: 96 chars:

class C{static void Main(){for(int x=65;x<91;++x)Syst\u0065m.Consol\u0065.Writ\u0065((char)x);}}

Without O: 101 chars:

class C{static int Main(){System.C\u006fns\u006fle.Write("abcdefghijklmn\x6fpqrstuvwxyz");return 0;}}

Total (with A, I missing): 278

Variant 2 – Pure code

Without A, E, I, O: 97 chars

Syst\u0065m.C\u006fns\u006fl\u0065.Wr\u0069t\u0065("\u0061bcd\u0065fgh\x69jklmn\x6fpqrstuvwxyz");

Without U: 52 chars

for(int x=65;x<91;++x)System.Console.Write((char)x);

total: 149

class C{static void Main(){for(var x='@';x++<'Z';)System.Console.Write(x);}} shorter one for first program. — tia, Apr 25, 2013 at 12:50

Joe K · Accepted Answer · 2013-01-11 22:27:41Z

2

Befunge, 26

>"`">1+:"z"`v
:,  ^      @_

Minimizing whitespace is part of the challenge of Befunge, so I included it in the character count. It might be possible to take out some of that whitespace, but the instructions themselves seem minimal.

answered Jan 11, 2013 at 22:27

Joe K

1,0756 silver badges12 bronze badges

1

\$\begingroup\$ You can save quite a few characters. The first > is unneeded and you can arrange on lines. Also, Befunge 98 has ', the fetch character. I suggest doing this: 1st line: 'backtickv, second line: :,>1+:'zbacktick!j@ for a total count of 16 chars. \$\endgroup\$
– Justin
Dec 12, 2013 at 7:05

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Print the alphabet without using each vowel

122 Answers 122

PHP, HTML (50)

Postscript, 46 45

Scala,38+17=55

Ruby, 47 characters

Brainfuck, 25 bytes

26 bytes

Java (OpenJDK 8), 137 bytes

JavaScript (single program, no vowels whatsoever) 104 99 92 90

C, 136 115 104 characteres

PHP, 47

Factor, 264 characters

Perl 5.10+, 8 + 22 = 30 chars

Perl (25 24 ) (18?) (no wowels, little cheating)

UPDATES:

Tcl, 49 chars

Matlab: 11 characters

Javascript, 96

Chrome

Firefox

Fission, 21 bytes

Cardinal, 22 20 chars

Mathematica, 61 bytes

Python shell, 94 78 chars

JavaScript (Node.js), 32113 bytes

Japt, 2 bytes

Charcoal, 1 byte

JS (ES2018), 54 bytes

Perl 5 -p, 21 bytes

D no 'u' (64 chars)

D only i (92 chars)

BASH: 16 + 32 = 48 characters

C# – 278/149

Variant 1 – Full standalone programs

Variant 2 – Pure code

Befunge, 26

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