Is this even or odd?

Question

Note: There is not been a vanilla parity test challenge yet (There is a C/C++ one but that disallows the ability to use languages other than C/C++, and other non-vanilla ones are mostly closed too), So I am posting one.

Given a positive integer, output its parity (i.e. if the number is odd or even) in truthy/falsy values. You may choose whether truthy results correspond to odd or even inputs.

---

Examples

Assuming True/False as even and odd (This is not required, You may use other Truthy/Falsy values for each), responsively:

(Input):(Output)
1:False
2:True
16384:True
99999999:False

Leaderboard

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Answer 1

Underload, 10 bytes

(0)(1)()^S

Input is in hard-coded in Unary, using ~ in the 3rd bracket. 0 for odd, 1 for even.

Try it Online!

Answer 2

AsciiDots, 16 bytes

.-#?{&}$#
 .-#1/

Outputs 0 if even, and 1 if odd. Basically just a Boolean AND with 1.

Try it online!

Answer 3

asm2bf, 7 bytes

modr1,2

Yes, it compiles. Takes input in r1, writes output to r1. 1 for odd, 0 for even.

Answer 4

SystemVerilog, 29 bytes

task t(n);$write(n%2);endtask

Prints 1 for odd numbers and 0 for even numbers.

Testbench:

module m;
  initial begin
    t(1);
    t(2);
    t(16384);
    t(99999999);
  end

  task t(n);$write(n%2);endtask
endmodule

Output (VCS on EDA Playground):

 1         0         0         1

Answer 5

FEU, 21 bytes

u/x
m/^(xx)+x$/1/x+/0

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0 for even, 1 for odd

Answer 6

Python 3, 15 bytes

lambda n:n%2==0

Try it online!

Prints True/False when even/odd respectively.

Answer 7

Rockstar, 47 bytes

listen to N
let D be N/2
turn up D
say D is N/2

Try it here (Code will need to be pasted in)

Answer 8

05AB1E, 1 Byte

É

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   # (implicit) push STDIN to stack
É  # push 1 if top of stack is odd, 0 if even
   # (implicit) output top of stack to STDOUT

Answer 9

Duocentehexaquinquagesimal, 6 bytes

5Q¬$††

Try it online!

Answer 10

Python 3, 16 bytes

x=lambda n:n%2<1

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Answer 11

INTERCAL, 39 bytes

Domain is ZERO or OH to FOUR TWO NINE FOUR NINE SIX SEVEN TWO NINE FIVE. _ (zero) for even and I (one) for odd. Also works in CLC-INTERCAL.

DOWRITEIN:1DO:1<-':1~#1'PLEASEREADOUT:1

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Answer 12

INTERCAL (C-INTERCAL), 229 bytes

This version accepts any integers, in decimal (e.g. -156); requires to be terminated with EOF.

Outputs _ for even and I for odd.

DO,1<-#1DOCOMEFROM#3DOWRITEIN,1(1)DO.1<-,1SUB#1DO.2<-.4DO(1000)NEXTDO.4<-.3PLEASE.3<-!3~#15'$!3~#240'DO.3<-!3~#15'$!3~#240'DO.2<-!3~#15'$!3~#240'PLEASE.1<-.5DO(1010)NEXT(3)DO.5<-.2PLEASECOMEFROM.1~#256DO.2<-.2~#128PLEASEREADOUT.2

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How it works

• First part is taken from 229 bytes of cat program but without READing out character.
• In ASCII 0 is 48, 1 is 49, ... 9 is 57.
• But C-INTERCAL reverses bit order, so 0 is 0x0c, 1 is 0x8c, ... 9 is 0x9c.
• If bit at 0x80 is 1, then it's odd digit.

Answer 13

LOLCODE, 151 bytes

HAI 1.2
I HAS A N
GIMMEH N
N IS NOW A NUMBAR
I HAS A V ITZ QUOSHUNT OF N AN 2
VISIBLE MAEK BOTH SAEM DIFF OF V AN MAEK V A NUMBR AN 0.5 A NUMBR
KTHXBYE

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Answer 14

Python REPL, 14 bytes

int(input())%2

Where 0 (falsy) is even, and 1 (truthy) is odd.

Answer 15

Headascii, 20 13 bytes

{UN()}:R--O<E

Try it here! Code will have to be copied and executed like this:

erun("{UN()}:R--O<E","input here")

Outputs two differing error messages. For odd inputs:

error 0:12 E [ 1, 0, 0, 1 ] (1)
'Error: E index out of range'

For even inputs:

error 0:12 E [ 1, 0, 0, 1 ] (2)
'Error: E index out of range'

Explanation:

{UN()}:R--O<E  Full program (Block 0)

{    }         Loop, which
 U             Discard(s) input byte(s)
  N() :        Until there is no input
  N(           (and stores 1 in the comparison register)
       R       Recall the last byte
        --O    Subtract 2 and save
           <   If this number is less than the comparison register (1)
                 Return the number in the comparison register (1)
               Else
                 Return 0
            E  Go to the code block corresponding to this number.
               If it is block 0, the program loops to the beginning
               with the saved byte as "input"
               If it is block 1, the program will exit with an error,
               as there is no block 1 in this program. The error message
               will include register state information, including the
               currently recall-able byte. In this state of the program,
               odd inputs will have reached 1, and even inputs will have
               reached 2.

I still think this is further golfable, but I'm proud of this clever little -7

Old solution (20 bytes):

{UN)}:R--O(<)[E:+()?

Try it here! Code will have to be copied and executed like this:

erun("{UN)}:R--O(<)[E:+()?","input here")

Prints a Headascii debug message if odd, and nothing if even.

Explanation:

{UN)}:R--O(<)[E:+()?  Full program

{   }                 Loop which
 U                    Discard(s) input byte(s)
  N) :                Until there is no more input
      R               Recall the last byte (as a number)
       --O            Subtract 2 and save
          (<)         If the number is greater than or equal to 0
             [E         Return to start of program, with saved number as input
               :      Else
                +()     If the number is -1
                   ?      Print a debug message

Repeatedly subtracts 2 from the last digit until it is -1 or -2. There might be a way to shave off a byte or two by switching the conditions / thens / elses around a bit. Just want to submit for now

Answer 16

BotEngine, 3x9=27 (27 bytes)

v  02468
>IRSSSSST
  F<<<<<

Outputs TRUE for odd and FALSE for even.

Answer 17

GolFunc, 9 bytes

.O..%.JN2

Outputs 1 for odd inputs and 0 for even inputs. (there will soon be an interpreter, but this works for now)

Explanation:

     .JN  # take input as a number
  ..%   2 # mod 2
.O        # and then output.

Answer 18

minigolf, 6 bytes

0i,0=_

Attempt This Online!

Explanation

0      0, Initial output: 0 _
i,     0, Repeat input times: _
  0=   0, Logical not (is it equal to 0?) _
_      0, End repeat _

0, Implicit output TOS _

Answer 19

Desmoslang, 10 Bytes

\mod(I,2OT

0 means even, 1 means odd.

Answer 20

sed, 20 bytes

s/^(!!)*$/T/
s/!+/F/

Try it online!

Input is in Unary, using exclamation marks.

Answer 21

Javascript <= ES5, 28 bytes

function i(n){return n%2==1}

If returning 1 or 0 is allowed, than (27 bytes):

function i(n){return n%2&1}