No trailing but(t)s please!

Question

This challenge was inspired by Yeah But No But Yeah.

---

maxb´s colleague recently sent him the following piece of JavaScript as a joke:

let butScript = (nrOfButs) => {
    for(var i = 0; i < nrOfButs; i++){
        if(i % 3 == 0){
            console.log("Yeah")
        }
        if(i % 2 == 0){
            console.log("But")
        }
        if(i % 3 == 1){
            console.log("No")
        }
    }
}

Since the code is not only overly long but also incorrect, I´ll suggest to maxb´s boss to fire that guy and hire one of you folks instead.

I can´t guarantee anything; but I reckon there´ll be a decent wage, health insurance and possibly a company car in it. All You have to do is A) correct the code, so the Number of Buts printed is the same as asked in the parameter B) correct the grammar. (see below) C) make it as short as possible.

He might as well block my calls after that because he doesn´t like pennypickers; but who knows.

Input

a non-negative integer, in any convenient way

Output

Yeah and No, mostly separated by Buts. The code above and the examples below should clarify the pattern.
Output should never end in a But. And a sentence should always end with a stop (.) or exclamation mark; i.e. put one after every No that is directly followed by a Yeah (without a But) and one at the end of the output.
A single trailing "Yeah." may be printed (if you want to think positive), but that´s not a must.

You may print the output or return a list of strings.
Trailing blanks are acceptable, as well as a single leading or trailing newline.

examples (input => possible output)

input 0:

Yeah.

input 1:

Yeah
But
No.

input 2:

Yeah
But
No
But
Yeah.

input 3:

Yeah
But
No
But
Yeah
But
No.
Yeah!       <optional>

...

input 5:

Yeah
But
No
But
Yeah
But
No.
Yeah
But
No
But
Yeah.

Answer 1

JavaScript (Node.js), 80 bytes

a=>{s='';for(i=0;i<a+1;i++)s+=(i%2==0?'yeah':'no')+(i<a?'\nbut\n':'.');return s}

Try it online!

Answer 2

Python 2, 105 81 bytes

f=lambda n,s=1:(n|s)*' 'and'\nBut\n'.join((['Yeah','No']*2)[:n+1])+'.\n'+f(n-3,0)

Try it online!

_{- 24 bytes, thanks to ovs}

Answer 3

Retina, 48 47 bytes

.+
*
L$`__?_?|^
Yeah$&.
__
_¶But¶Yeah
_
¶But¶No

Try it online! Explanation:

.+
*

Convert to unary.

L$`__?_?|^
Yeah$&.

Match up to three _s at a time. Also handle the zero edge case as a match. Each match results in at least a Yeah with a trailing ..

__
_¶But¶Yeah

A match of 2 or 3 _s results in a But Yeah in the second position.

_
¶But¶No

The other _s turn into But No.

52 bytes in Retina 0.8.2:

.+
$*
M!`11?1?
%`^.*
Yeah$&.
11
1¶But¶Yeah
1
¶But¶No

Try it online! Explanation:

.+
$*

Convert to unary.

M!`11?1?

Match up to three 1s at a time.

%`^.*
Yeah$&.

Add a leading Yeah and trailing . for each match. The ^.* allows it to work for the zero case too.

11
1¶But¶Yeah
1
¶But¶No

Add in the But Yeah and/or No as above.

Answer 4

05AB1E,  44  42 34 31 bytes

^{Crossed out  44  is no longer regular 44 :)}

[Ðd_#3‚ßÝ„¥æ€¸#sè'€³¶.øý'.«™,3-

Also prints the optional Yeah..

Try it online or verify all test cases.

Explanation:

[               # Loop indefinitely:
 Ð              #  Triplicate the top value
                #  (which is the implicit input `n` in the first iteration)
  d_            #  Pop one copy, and if it's negative:
    #           #   Stop the infinite loop
  3‚ß           #  Take the max `m` of another copy of `n` and 3
     Ý„¥æ€¸#sè  #  Create an alternating list of "yeah" and "no" of size `m`
  '€³¶.ø       '#  Push "\nbut\n"
        ý       #  Join the alternating list with this as delimiter
  '.«          '#  Append a trailing "."
     ™          #  Titlecase each word in this string
      ,         #  Pop and print it with trailing newline
  3-            #  Decrease `n` by 3 for the next iteration

See this 05AB1E tips of mine (section How to use the dictionary?) to understand why „¥æ€¸ is "yeah no" and '€³ is "but".

Answer 5

JavaScript (Node.js), 82 bytes

_=>_>3?f(3)+f(_-3):[...Array(_+1)].map((a,i)=>i%2?'No':'Yeah').join`\nBut\n`+'.\n'

Try it online!

Answer 6

C (clang), 80 74 bytes

f(a,i){for(i=0;-i>~a;)printf("%s%s\n","YeahNo"+i%2*5,i++<a?"\nBut":".");}

-6 bytes thanks to @Jonathan Frech

Try it online!