Print all Sundays in 2017

Question

Print the dates of all the Sundays in 2017 in the following format : dd.mm.yyyy.
Expected Output:

Possible dupe of Plan your Sundays? This one is a specific year though. — xnor, Apr 13, 2017 at 3:19
I checked out Plan your Sundays before posting, but it asks to print the Sundays in a given month. @xnor — smanna, Apr 13, 2017 at 3:21
Any particular reason for that specific output format? You could open in up a bit. — Riker, Apr 13, 2017 at 3:22
I actually like this as an exact-text kolmogorov challenge. Getting the date formatting right has some interesting optimizations. — xnor, Apr 13, 2017 at 3:23

Brian · Accepted Answer · 2017-04-13 13:20:41Z

0

SpecBAS - 61 bytes

1 FOR i=42736 TO 43100 STEP 7: ?DATE$(i,"dd.mm.yyyy"): NEXT i

Dates are a decimal number starting at 30-Dec-1899, so had to work out what 1 Jan 2017 and 31 Dec 2017 were, then just step through those values adding 7 days each time.

answered Apr 13, 2017 at 13:20

Brian

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Community · Accepted Answer · 2020-06-17 09:04:33Z

0

Java 7, 145 144 142 bytes

void c(){for(long x=604800000,i=-x;i<52*x;)System.out.println(new java.text.SimpleDateFormat("dd.MM.2017").format(new java.util.Date(i+=x)));}

-2 bytes thanks to Cliffroot due to a stupid mistake of me..

Try it here.

Explanation:

void c(){                                  // Method
  for(long x=604800000,                    //  Initialize `x` as 604,800,000
           i=-x;                           //  Initialize `i` as `-x` / -604,800,000 as starting number
      i<52*x;)                             //  Loop over all 52 weeks
    System.out.println(new java.text.SimpleDateFormat("dd.MM.2017")
      .format(new java.util.Date(i+=x)));  //   Raise `i` by `x` and then print it in the format `dd.MM.2017`
                                           //  End of loop (implicit / single-line body)
}                                          // End of method

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Apr 13, 2017 at 13:00

Kevin Cruijssen

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1

\$\begingroup\$ long x=605000000 is shorter \$\endgroup\$
– cliffroot
Apr 13, 2017 at 13:30
\$\begingroup\$ @cliffroot Thanks. I really should just use the entire long from now on, and in case it can be shortened change it to (long)NeM.. I think this is already the second time you've corrected me on this.. \$\endgroup\$
– Kevin Cruijssen
Apr 13, 2017 at 13:45

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cliffroot · Accepted Answer · 2017-04-13 14:32:20Z

0

Java 7, 126 bytes

void e(){for(int i=0,j=1,k;i<12;j%=k)for(k="(%('('(('('(".charAt(i++)-9;j<k+1;j+=7)System.out.format("%02d.%02d.2017\n",j,i);}

Computes everything manually. The string "(%('('(('('(" encodes number of days in month. Outer loop goes from 0 to 11 (number of months), inner loops goes until the number representing day is greater than number of days in this month.

See it online

answered Apr 13, 2017 at 14:32

cliffroot

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Richard · Accepted Answer · 2017-04-13 14:33:56Z

0

SQL (PostgreSQL), 74 Bytes

SELECT to_char(generate_series('170101'::date,'171231','7d'),'DD.MM.YYYY')

If output must be in a single string rather than individual records then the query can be run from psql with the -tA options, making it 76 bytes.

answered Apr 13, 2017 at 14:33

Richard

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idrougge · Accepted Answer · 2017-04-13 14:34:53Z

0

REXX, 91 bytes

do n=1 to 365
  if date(w,n,d)='Sunday' then say left(translate(date(e,n,d),.,'/'),6)2017
  end

answered Apr 13, 2017 at 14:34

idrougge

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Community · Accepted Answer · 2020-06-17 09:04:33Z

0

SQL (Oracle), 137 bytes

select substr(d,1,10)
from (select to_char(sysdate-1e4+rownum,'DD.MM.YYYYdy') d from dual connect by rownum<=2e4)
where d like '%2017s%';

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Apr 13, 2017 at 19:33

Kjetil S

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Community · Accepted Answer · 2020-06-17 09:04:33Z

0

c, 119 116 114 bytes

y=2017,m=1,d=1,i=53,v;main(){for(;i--;)printf("%02d.%02d.%d\n",d,m,y),v=m^2?m%2^m<8?30:31:28,(d+=7)>v?++m,d-=v:0;}

Try it online

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Apr 13, 2017 at 15:41

jdt

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\$\begingroup\$ 103 bytes - d=1,i=53,v;main(m){for(;i--;(d+=7)>v?++m,d-=v:0)printf("%02d.%02d.2017\n",d,m),v=m^2?m%2^m<8?30:31:28;} \$\endgroup\$
– gastropner
Nov 23, 2017 at 13:04
\$\begingroup\$ Suggest 31-(m%2^m<8) instead of m%2^m<8?30:31 \$\endgroup\$
– ceilingcat
Sep 22, 2021 at 8:49

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Community · Accepted Answer · 2020-06-17 09:04:33Z

0

Python 3.6, 94 bytes

from datetime import*
for x in range(53):print(f"{datetime(1,1,1)+timedelta(x*7):%d.%m.2017}")

I wanted to try using high-level features. Well, it's still readable but not that short…

edited Jun 17, 2020 at 9:04

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answered Apr 14, 2017 at 7:53

301_Moved_Permanently

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Community · Accepted Answer · 2020-06-17 09:04:33Z

0

T-SQL, 141 bytes

SELECT FORMAT(d,'dd.MM.yyyy')FROM(SELECT DATEADD(ww,ROW_NUMBER()OVER(ORDER BY name)-1,'20170101')d FROM sys.stats)a WHERE 2017=DATEPART(yy,d)

Try it here

edited Jun 17, 2020 at 9:04

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1

answered Apr 14, 2017 at 8:58

grabthefish

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\$\begingroup\$ save 53 bytes \$\endgroup\$
– t-clausen.dk
Jul 13, 2020 at 5:13

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Chromozorz · Accepted Answer · 2017-04-14 11:10:34Z

0

k, 36 Bytes

Same approach as zgrep. 2017.01.01+0 7 14..., string it, split it on ".", reverse each and join back on "." - finally print the list of strings e.g. -1@("Print";"me");

-1@"."/:'|:'"."\:'$2017.01.01+7*!53;

answered Apr 14, 2017 at 11:10

Chromozorz

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Demonblack · Accepted Answer · 2017-04-15 01:44:09Z

0

Oracle SQL, 89 bytes

    select to_char(to_date('25-DEC-16')+level*7,'DD.MM.YYYY') from dual connect by level < 54

Explanation: You can just add an integer to a date and it's treated as a number of days. Exploiting connect by we're generating 53 rows for the 53 sundays which occur in 2017. Setting the starting date as the last sunday of 2016 saves me two bytes because I don't have to subtract 7 to compensate level starting at 1.

answered Apr 15, 2017 at 1:44

Demonblack

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Andrei Odegov · Accepted Answer · 2017-04-23 05:04:57Z

0

Microsoft Sql Server, 114 bytes

with v as(select 0 n union all select n+7 from v where n<364)select format(dateadd(d,n,'2017'),'dd.MM.yyyy')from v

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answered Apr 23, 2017 at 5:04

Andrei Odegov

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\$\begingroup\$ this is the good idea, but you can save a few bytes using spt_values \$\endgroup\$
– t-clausen.dk
Jul 13, 2020 at 5:20

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Magic Octopus Urn · Accepted Answer · 2017-06-06 18:17:06Z

05AB1E, 81 79 bytes

•8tåxвÓÈCм∞º²áÝViΣþ1₄É¨Å9”ÓU2Èn¶äΔb'Î?™Íćεr$Ã]7¤¶¸M•11BR'A¡vy2ôN>".ÿ.2017"«})˜»

Try it online!

No date built-ins.

01081522A05121926A05121926A0209162330A07142128A04111825A0209162330A06132027A03101724A0108152229A05121926A0310172431

Is the compressed base-11 number at the beginning, when split on A's you get:

['01081522', '05121926', '05121926', '0209162330', '07142128', '04111825', '0209162330', '06132027', '03101724', '0108152229', '05121926', '0310172431']

Which is the days of each month that are Sundays, in order. Then, we split each one into pieces of two, and concatenate the index of those days plus 2017 to each.

Finally we just flatten and return the list separated by newlines.

Community · Accepted Answer · 2020-06-17 09:04:33Z

Jelly, 38 37 bytes

-1 thanks to user202729 (use the ⁽ quick I implemented about a month after this answer.)

Ḋ€;⁽¥Ñj”.
“£hṅ’ṃ“þœ÷‘R,€"J$;/m7+³DÇ€Y

Jelly currently has no date type or way of representing a date natively, so a purely numeric approach is required.

Try it online!

How?

Ḋ€;⁽¥Ñj”. - Link 1, format helper: list of lists   e.g. [[x,0,2],[x,0,7]] (for 2nd July)
Ḋ€        - dequeue €ach                                [[0,2],[0,7]]
   ⁽¥Ñ    - literal 2017                                2017
  ;       - concatenate                                 [[0,2],[0,7],2017]
       ”. - character '.'
      j   - join                                        [0,2,'.',0,7,'.',2017]
              which has the representation:             "02.07.2017"

“£hṅ’ṃ“þœ÷‘R,€"J$;/m7+³DÇ€Y - Main link: no arguments
“£hṅ’                       - base 250 compressed number 213991
      “þœ÷‘                 - code-page indexes [31,30,28]
     ṃ                      - base decompression: 213991 base length([31,30,28])
                                = [1,0,1,2,1,2,1,1,2,1,2,1]; indexed into [31,30,28]
                                = [31,28,31,30,31,30,31,31,30,31,30,31]
           R                - range (vectorises): [[1,2,...,31],[1,2,...,28],...]
                $           - last two links as a monad:
               J            -     range(length): [1,2,3,4,5,6,7,8,9,10,11,12]
              "             -     zip with:
            ,€              -         pair for €ach: [[[1,1],[2,1],...,[31,1]],[[1,2],[2,2],...,[28,2]],...]
                 ;/         - reduce with concatenation: [[1,1],[2,1],...,[31,1],[1,2],[2,2],...,[28,2],...]
                   m7       - every 7th item: [[1,1],[8,1],...,[24,12],[31,12]]
                      ³     - 100
                     +      - add (vectorises): [[101,101],[108,101],...[124,112],[131,112]]
                       D    - to decimal (vectorises): [[[1,0,1],[1,0,1]],[[1,0,8],[1,0,1]],...,[[1,2,4],[1,1,2]],[[1,3,1],[1,1,2]]]
                        Ç€  - call last link as a monad for €ach: [[0,1,'.',0,1,'.',2017],[0,8,'.',0,1,'.',2017],...,[2,4,'.',1,2,'.',2017],[3,1,'.',1,2,'.',2017]]
                          Y - join with line feeds: [0,1,'.',0,1,'.',2017,'\n',0,8,'.',0,1,'.',2017,'\n',...,'\n',2,4,'.',1,2,'.',2017,'\n',3,1,'.',1,2,'.',2017]
                            - implicit print

This post was made about a month before I implemented ⁽. I will update it but I have not trawled through my old posts looking for golfs using newer language features (there are probably many that could use the quicks ƊƲɗʋ, a bunch that could use Ɲ, and a few that could use Ƥ or ÐƤ, and maybe more...). — Jonathan Allan, May 11, 2018 at 7:00

sergiol · Accepted Answer · 2018-05-11 16:06:30Z

0

Tcl, 80 bytes

time {puts [clock format [expr 1482624000+[incr i 604800]] -format %d.%m.%Y]} 53

Try it online!

answered May 11, 2018 at 16:06

sergiol

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Community · Accepted Answer · 2020-06-17 09:04:33Z

Japt `-R`, 25 21 15 bytes

Locale dependent - You'll need to set your browser's locale to (among others, I'm sure) Romania (RO), Russia (RU) or Turkey (TR) for the dates to be formatted correctly.

#5ÆÐ#É7TX*7Ä s7

Test it

Explanation

Takes advantage of the fact that if you provide JavaScript's date construct a value for the day that's higher than the number of days in the month you've provided, it will rollover to the next month.

#5                        :53
  Æ                       :Create the range [0,53) and pass each integer X through a function
    #É7                   :  2017
       T                  :  0
        X*7Ä              :  X*7+1
   Ð                      :  new Date() with those 3 arguments as year, month & day
             s7           :  Convert to date string, locale formatted

Community · Accepted Answer · 2020-06-17 09:04:33Z

0

JavaScript, 80 bytes

(f=x=>x?[...f(--x),new Date(2017,0,x*7+1).toLocaleDateString()]:[])(53).join`
`

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered May 11, 2018 at 23:48

Shaggy

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\$\begingroup\$ This looks like an auto-flag, so I'm reviewing Looks OK. \$\endgroup\$
– Nissa
May 12, 2018 at 0:24

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Community · Accepted Answer · 2020-06-17 09:04:33Z

Pyth, 122 bytes

jm+X2d\.".2017"c+\0`i."0Z|´&ÓäßæÅJÈD@ßÍTû=´}¾}Zàe+ñðºâ$Ã°Gzdüä#Ò×ûíO^©¢Q Óýo`Åi2ÓàÀ{9¢à>«+íø#o^Mý"36 4

Try it online!

The code uses unprintable characters that are not displayed properly on Stack Exchange. Use the link to get the working version.

Pyth doesn't have a way to check whether a date is a Sunday, so this is the Kolmogorov version.
It uses a MAGIC STRING which represents this integer.

Explanation:

jm+X2d\.".2017"c+\0`i."…"36 4 # Code with MAGIC STRING replaced with …
                   `          # String representation of
                      "…"     # THE MAGIC STRING
                     ."       # Decompressed
                    i    36   # To int from base 36
                +\0           # With a 0 in front
               c            4 # Chopped into strings of length 4 as a list
 m                            # With each member
   X2d\.                      #  with . inserted at index 2
  +     ".2017"               #  and appended with .2017
j                             # Joined with newlines

Matias Bjarland · Accepted Answer · 2018-05-13 08:43:52Z

0

Groovy, 52 bytes

53.times{printf('%td.%<tm.2017%n',new Date(0)+it*7)}

Building on Krystian's groovy answer above with an optimisation dropping another four bytes. Uses the fact that the epoch year 1970 matches 2017 weekdays and months.

answered May 13, 2018 at 8:43

Matias Bjarland

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Galen Ivanov · Accepted Answer · 2018-05-13 08:50:16Z

0

Red, 107 bytes

f: func[n][n: pad/left/with to-string n 2 #"0"]d: 1-1-2
loop 53[print rejoin[f d/3":"f d/4":"2017]d: d + 7]

Try it online!

edited May 13, 2018 at 8:50

answered May 12, 2018 at 8:08

Galen Ivanov

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Stack Exchange Network

Print all Sundays in 2017

50 Answers 50

SpecBAS - 61 bytes

Java 7, 145 144 142 bytes

Java 7, 126 bytes

SQL (PostgreSQL), 74 Bytes

REXX, 91 bytes

SQL (Oracle), 137 bytes

c, 119 116 114 bytes

Python 3.6, 94 bytes

T-SQL, 141 bytes

k, 36 Bytes

Oracle SQL, 89 bytes

05AB1E, 81 79 bytes

Jelly, 38 37 bytes

How?

Tcl, 80 bytes

Japt `-R`, 25 21 15 bytes

Explanation

JavaScript, 80 bytes

Pyth, 122 bytes

The code uses unprintable characters that are not displayed properly on Stack Exchange. Use the link to get the working version.

Groovy, 52 bytes

Red, 107 bytes

Your Answer

Not the answer you're looking for? Browse other questions tagged
code-golf
kolmogorov-complexity
date
or ask your own question.

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Print all Sundays in 2017

50 Answers 50

SpecBAS - 61 bytes

Java 7, 145 144 142 bytes

Java 7, 126 bytes

SQL (PostgreSQL), 74 Bytes

REXX, 91 bytes

SQL (Oracle), 137 bytes

c, 119 116 114 bytes

Python 3.6, 94 bytes

T-SQL, 141 bytes

k, 36 Bytes

Oracle SQL, 89 bytes

05AB1E, 81 79 bytes

Jelly, 38 37 bytes

How?

Tcl, 80 bytes

Japt -R, 25 21 15 bytes

Explanation

JavaScript, 80 bytes

Pyth, 122 bytes

The code uses unprintable characters that are not displayed properly on Stack Exchange. Use the link to get the working version.

Groovy, 52 bytes

Red, 107 bytes

Your Answer

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Not the answer you're looking for? Browse other questions tagged code-golfkolmogorov-complexitydate or ask your own question.

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Japt `-R`, 25 21 15 bytes

Not the answer you're looking for? Browse other questions tagged
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kolmogorov-complexity
date
or ask your own question.