The first Predecessor-completed Ascii Cube (PAC 1) is a simple cube with side length 1 and looks like this:
/////\
///// \
\\\\\ /
\\\\\/
The PAC 2 is a geometric shape such that combining it with its predecessor (the PAC 1) completes a side length 2 cube:
front back
/////////\ /////////\
///////// \ ///////// \
/////\\\\\ \ ///////// \
///// \\\\\ \ ///////// \
\\\\\ ///// / \\\\\\\\\ /
\\\\\///// / \\\\\\\\\ /
\\\\\\\\\ / \\\\\\\\\ /
\\\\\\\\\/ \\\\\\\\\/
Because the back-view is kind of boring, we are only interested in the front-view.
The same goes for the PAC 3: With some visual thinking the PAC 2 can be turned around and plugged into the PAC 3 to form a solid side length 3 cube:
/////////////\
///////////// \
/////\\\\\\\\\ \
///// \\\\\\\\\ \
///// /////\\\\\ \
///// ///// \\\\\ \
\\\\\ \\\\\ ///// /
\\\\\ \\\\\///// /
\\\\\ ///////// /
\\\\\///////// /
\\\\\\\\\\\\\ /
\\\\\\\\\\\\\/
And so on with PAC 4:
/////////////////\
///////////////// \
/////\\\\\\\\\\\\\ \
///// \\\\\\\\\\\\\ \
///// /////////\\\\\ \
///// ///////// \\\\\ \
///// /////\\\\\ \\\\\ \
///// ///// \\\\\ \\\\\ \
\\\\\ \\\\\ ///// ///// /
\\\\\ \\\\\///// ///// /
\\\\\ \\\\\\\\\ ///// /
\\\\\ \\\\\\\\\///// /
\\\\\ ///////////// /
\\\\\///////////// /
\\\\\\\\\\\\\\\\\ /
\\\\\\\\\\\\\\\\\/
Task:
Write a full program or function which takes a positive integer n as input and returns or prints the corresponding front-view of PAC n exactly as shown above. Additional trailing white space is acceptable.
This is code-golf, so try to use as few bytes as possible in the language of your choice.